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TALLER DE CONVERSIONES 
DECIMAL A BINARIO Y BINARIO A DECIMAL 
M. TÉCNICA EN SISTEMAS GRADO 10 
SEPTIEMBRE DE 2014 
INTEGRANTES: 
Nombres y apellidos Yeison Arley Agudelo Mejia 
Nombres y apellidos 
1. CONVIERTA LOS SIGUIENTES NÚMEROS BINARIOS A DECIMAL. DEBE REALIZAR TODO EL PROCEDIMIENTO. 
No. NÚMERO BINARIO RESPUESTA EN DECIMAL (PROCEMIENTO) 
1 10001112 1x26 + 0x25 + 0x24 + 0x23 + 1x22 + 1x21 +1x20 = 64+0+0+0+4+2+1 = 7110 
2 10000002 1x26 + 0x25 + 0x24 + 0x23 + 0x22 + 0x21 + 0x20 = 64+0+0+0+0+0+0 = 6410 
3 11111112 1x26 + 1x25 + 1x24 + 1x23 + 1x22 + 1x21 + 1x20 = 64+32+16+8+4+2+1 = 12710 
4 101010102 1x27 + 0x26 + 1x25 + 0x24 + 1x23 + 0x22 + 1x21 + 0x20 = 128+0+32+0+8+0+2+0 = 17010 
5 110101012 1x27 + 1x26 + 0x25 + 1x24 + 0x23 + 1x22 + 0x21 + 1x20 =128+64+0+16+0+4+0+1= 21310 
6 10001112 1x26 + 0x25 + 0x24 + 0x23 + 1x22 + 1x21 +1x20 = 64+0+0+0+4+2+1 = 7110 
7 111111102 
1x27 + 1x26 + 1x25 + 1x24 + 1x23 + 1x22 + 1x21 + 0x20 = 128+64+32+16+8+4+2+0 = 
25410 
8 1110000112 
1x28 + 1x27 + 1x26 + 0x25 + 0x24 + 0x23 + 0x22 + 1x21 + 1x20 = 
256+128+64+0+0+0+0+2+1 = 45110 
9 101110002 1x27 + 0x26 + 1x25 + 1x24 + 1x23 + 0x22 + 0x21 + 0x20= 128+0+32+16+8+0+0+0= 18410 
10 1100011102 
1x28 + 1x27 + 0x26 + 0x25 + 0x24 + 1x23 + 1x22 + 1x21 + 0x20 = 
256+128+0+0+0+8+4+2+0 = 39810
2. CONVIERTA LOS SIGUIENTES NÚMEROS DECIMALES A BINARIO. DEBE REALIZAR TODO EL PROCEDIMIENTO. 
No. NÚMERO DECIMAL RESPUESTA EN BINARIO (PROCEMIENTO) 
1 15.60010 
15600 2 = 0 15600 = 111100111100002 
7800 2 = 0 
3900 2 = 0 
1950 2 = 0 
975 2 = 1 
487 2 = 1 
243 2 = 1 
121 2 = 1 
60 2 = 0 
30 2 = 0 
15 2 = 1 
7 2 = 1 
3 2 = 1 
1 2 = 1 
0 
2 10.80010 
10800 2 = 0 10.800 = 101010001100002 
5400 2 = 0 
2700 2 = 0 
1350 2 = 0 
675 2 = 1 
337 2 = 1 
168 2 = 0 
84 2 = 0 
42 2 = 0 
21 2 = 1 
10 2 = 0 
5 2 = 1 
2 2 = 0 
1 2 = 1 
0
3 11.79110 
11791 2 = 1 11.791 = 10111000001111 
5895 2 = 1 
2947 2 = 1 
1473 2 = 1 
736 2 = 0 
368 2 = 0 
184 2 = 0 
92 2 = 0 
46 2 = 0 
23 2 = 1 
11 2 = 1 
5 2 = 1 
2 2 = 0 
1 2 = 1 
0 
4 5.35910 
5359 2 = 1 5.359 = 1010011101111 
2679 2 = 1 
1339 2 = 1 
699 2 = 1 
334 2 = 0 
167 2 = 1 
83 2 = 1 
41 2 = 1 
20 2 = 0 
10 2 = 0 
5 2 = 1 
2 2 = 0 
1 2 = 1 
0 
5 4.82510 
4825 2 = 1 4825 = 1001011011001 
2412 2 = 0 
1206 2 = 0 
603 2 = 1 
301 2 = 1 
150 2 = 0 
75 2 = 1 
37 2 = 1 
18 2 = 0 
9 2 = 1 
4 2 = 0 
2 2 = 0 
1 2 = 1 
0
6 3.00010 
3000 2 = 0 3000= 101110111000 
1500 2 = 0 
750 2 = 0 
375 2 = 1 
187 2 = 1 
93 2 = 1 
46 2 = 0 
23 2 = 1 
11 2 = 1 
5 2 = 1 
2 2 = 0 
1 2 = 1 
0 
7 2.00010 
2000 2 = 0 2000 = 11111010000 
1000 2 = 0 
500 2 = 0 
250 2 = 0 
125 2 = 1 
62 2 = 0 
31 2 = 1 
15 2 = 1 
7 2 = 1 
3 2 = 1 
1 2 = 1 
0 
8 1.56010 
9 80010 
800 2 = 0 800 = 1100100000 
400 2 = 0 
200 2 = 0 
100 2 = 0 
50 2 = 0 
25 2 = 1 
12 2 = 0 
6 2 = 0 
3 2 = 1 
1 2 = 1 
0 
10 32910

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Taller+de+conversiones+bd+db (1)

  • 1. TALLER DE CONVERSIONES DECIMAL A BINARIO Y BINARIO A DECIMAL M. TÉCNICA EN SISTEMAS GRADO 10 SEPTIEMBRE DE 2014 INTEGRANTES: Nombres y apellidos Yeison Arley Agudelo Mejia Nombres y apellidos 1. CONVIERTA LOS SIGUIENTES NÚMEROS BINARIOS A DECIMAL. DEBE REALIZAR TODO EL PROCEDIMIENTO. No. NÚMERO BINARIO RESPUESTA EN DECIMAL (PROCEMIENTO) 1 10001112 1x26 + 0x25 + 0x24 + 0x23 + 1x22 + 1x21 +1x20 = 64+0+0+0+4+2+1 = 7110 2 10000002 1x26 + 0x25 + 0x24 + 0x23 + 0x22 + 0x21 + 0x20 = 64+0+0+0+0+0+0 = 6410 3 11111112 1x26 + 1x25 + 1x24 + 1x23 + 1x22 + 1x21 + 1x20 = 64+32+16+8+4+2+1 = 12710 4 101010102 1x27 + 0x26 + 1x25 + 0x24 + 1x23 + 0x22 + 1x21 + 0x20 = 128+0+32+0+8+0+2+0 = 17010 5 110101012 1x27 + 1x26 + 0x25 + 1x24 + 0x23 + 1x22 + 0x21 + 1x20 =128+64+0+16+0+4+0+1= 21310 6 10001112 1x26 + 0x25 + 0x24 + 0x23 + 1x22 + 1x21 +1x20 = 64+0+0+0+4+2+1 = 7110 7 111111102 1x27 + 1x26 + 1x25 + 1x24 + 1x23 + 1x22 + 1x21 + 0x20 = 128+64+32+16+8+4+2+0 = 25410 8 1110000112 1x28 + 1x27 + 1x26 + 0x25 + 0x24 + 0x23 + 0x22 + 1x21 + 1x20 = 256+128+64+0+0+0+0+2+1 = 45110 9 101110002 1x27 + 0x26 + 1x25 + 1x24 + 1x23 + 0x22 + 0x21 + 0x20= 128+0+32+16+8+0+0+0= 18410 10 1100011102 1x28 + 1x27 + 0x26 + 0x25 + 0x24 + 1x23 + 1x22 + 1x21 + 0x20 = 256+128+0+0+0+8+4+2+0 = 39810
  • 2. 2. CONVIERTA LOS SIGUIENTES NÚMEROS DECIMALES A BINARIO. DEBE REALIZAR TODO EL PROCEDIMIENTO. No. NÚMERO DECIMAL RESPUESTA EN BINARIO (PROCEMIENTO) 1 15.60010 15600 2 = 0 15600 = 111100111100002 7800 2 = 0 3900 2 = 0 1950 2 = 0 975 2 = 1 487 2 = 1 243 2 = 1 121 2 = 1 60 2 = 0 30 2 = 0 15 2 = 1 7 2 = 1 3 2 = 1 1 2 = 1 0 2 10.80010 10800 2 = 0 10.800 = 101010001100002 5400 2 = 0 2700 2 = 0 1350 2 = 0 675 2 = 1 337 2 = 1 168 2 = 0 84 2 = 0 42 2 = 0 21 2 = 1 10 2 = 0 5 2 = 1 2 2 = 0 1 2 = 1 0
  • 3. 3 11.79110 11791 2 = 1 11.791 = 10111000001111 5895 2 = 1 2947 2 = 1 1473 2 = 1 736 2 = 0 368 2 = 0 184 2 = 0 92 2 = 0 46 2 = 0 23 2 = 1 11 2 = 1 5 2 = 1 2 2 = 0 1 2 = 1 0 4 5.35910 5359 2 = 1 5.359 = 1010011101111 2679 2 = 1 1339 2 = 1 699 2 = 1 334 2 = 0 167 2 = 1 83 2 = 1 41 2 = 1 20 2 = 0 10 2 = 0 5 2 = 1 2 2 = 0 1 2 = 1 0 5 4.82510 4825 2 = 1 4825 = 1001011011001 2412 2 = 0 1206 2 = 0 603 2 = 1 301 2 = 1 150 2 = 0 75 2 = 1 37 2 = 1 18 2 = 0 9 2 = 1 4 2 = 0 2 2 = 0 1 2 = 1 0
  • 4. 6 3.00010 3000 2 = 0 3000= 101110111000 1500 2 = 0 750 2 = 0 375 2 = 1 187 2 = 1 93 2 = 1 46 2 = 0 23 2 = 1 11 2 = 1 5 2 = 1 2 2 = 0 1 2 = 1 0 7 2.00010 2000 2 = 0 2000 = 11111010000 1000 2 = 0 500 2 = 0 250 2 = 0 125 2 = 1 62 2 = 0 31 2 = 1 15 2 = 1 7 2 = 1 3 2 = 1 1 2 = 1 0 8 1.56010 9 80010 800 2 = 0 800 = 1100100000 400 2 = 0 200 2 = 0 100 2 = 0 50 2 = 0 25 2 = 1 12 2 = 0 6 2 = 0 3 2 = 1 1 2 = 1 0 10 32910