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Fixed Wing Fighter Aircraft
Flight Performance
Part II
SOLO HERMELIN
Updated: 04.12.12
28.02.15
1
http://www.solohermelin.com
Table of Content
SOLO
2
Aerodynamics
Introduction to Fixed Wing Aircraft Performance
Earth Atmosphere
Mach Number
Shock & Expansion Waves
Reynolds Number and Boundary Layer
Knudsen Number
Flight Instruments
Aerodynamic Forces
Aerodynamic Drag
Lift and Drag Forces
Wing Parameters
Specific Stabilizer/Tail Configurations
F
i
x
e
d
W
i
n
g
P
a
r
t
I
Fixed Wing Fighter Aircraft Flight Performance
Table of Content (continue – 1)
SOLO
3
Specific Energy
Aircraft Propulsion Systems
Aircraft Propellers
Aircraft Turbo Engines
Afterburner
Thrust Reversal Operation
Aircraft Propulsion Summary
Vertical Take off and Landing - VTOL
Engine Control System
Aircraft Flight Control
Aircraft Equations of Motion
Aerodynamic Forces (Vectorial)
Three Degrees of Freedom Model in Earth Atmosphere
F
i
x
e
d
W
i
n
g
P
a
r
t
I
Fixed Wing Fighter Aircraft Flight Performance
Table of Content (continue – 2)
SOLO
Fixed Wing Fighter Aircraft Flight Performance
4
Parameters defining Aircraft Performance
Takeoff (no VSTOL capabilities)
Landing (no VSTOL capabilities)
Climbing Aircraft Performance
Gliding Flight
Level Flight
Steady Climb (V, γ = constant)
Optimum Climbing Trajectories using Energy State
Approximation (ESA)
Minimum Fuel-to- Climb Trajectories using Energy State
Approximation (ESA)
Maximum Range during Glide using Energy State
Approximation (ESA)
Aircraft Turn Performance
Maneuvering Envelope, V – n Diagram
Table of Content (continue – 3)
SOLO
Fixed Wing Fighter Aircraft Flight Performance
5
Air-to-Air Combat
Energy–Maneuverability Theory
Supermaneuverability
Constraint Analysis
References
Aircraft Combat Performance Comparison
SOLO
This Presentation is about Fixed Wing Aircraft Flight Performance.
The Fixed Wing Aircraft are
•Commercial/Transport Aircraft (Passenger and/or Cargo)
•Fighter Aircraft
Fixed Wing Fighter Aircraft Flight Performance
Continue from Part I
7
Fixed Wing Fighter Aircraft Flight PerformanceSOLO
The Aircraft Flight Performance is defined by the following parameters
• Take-off distance
• Landing distance
• Maximum Endurance and Speed for Maximum Endurance
• Maximum Range and Speed for Maximum Range
• Ceiling(s)
• Climb Performance
• Turn Performance
• Combat Radius
• Maximum Payload
Parameters defining Aircraft Performance
8
Performance of an Aircraft with Parabolic PolarSOLO
Assumptions:
•Point mass model.
•Flat earth with g = constant.
•Three-dimensional aircraft trajectory.
•Air density that varies with altitude ρ=ρ(h)
•Drag that varies with altitude, Mach
number and control effort D = D(h,M,n)
and is given by a Parabolic Polar.
•Thrust magnitude is controllable by the
throttle.
•No sideslip angle.
•No wind.
α
T
V
L
D
Bx
Wx
Bz
Wz
Wy
By
Aircraft Coordinate System
To understand how different parameters affect Aircraft Performance we start with a
Simplified Model, where Analytical Solutions can be obtained.
Results for real aircraft will then be presented.
Return to Table of Content
9
SOLO
Aircraft Flight Performance
Takeoff
The Takeoff distance sTO
is divided as the sum of the
following distances:
sg – Ground Run
sr – Rotation Distance
st – Transition Distance
sc – Climb Distance to
reach Screen Height
ctrgTO sssss +++=
Ground Run
V = 0
sg
sTO
sr str
V TO
Rotation
Transition
sCL
θ CL
htr
hobs
R
Takeoff htransition < hobstacle
θ CL
Ground Run
V = 0
sg
sTO
sr sobs
V TO
Rotation
Transition
hobs
R
Takeoff htransition > hobstacle
We distinguish between two cases
of Takeoff
•The Aircraft must passes over an
obstacle at altitude hobs..
•The obstacle is cleared during
the transition phase.
Assume no Vertical Takeoff
Capability.
10
Takeoff (continue – 1)
During the Ground Run there are additional
effects than in free flight, that must be considered:
-Friction between the tires and the ground
during rolling.
-Additional drag due to the landing gear
fully extended.
-Additional Lift Coefficient due to extended
flaps.
-Ground Effect due to proximity of the wings
to the ground, that reduces the Induced Drag
and the Lift.
Ground Run
SOLO
Aircraft Flight Performance
Ground run sg
Transition
distance st
Climb
distance sc
Stall safety
Take-off possible
with one engine
Continue take-off
if engine fails
after this point
Stop take-off if
engine fails before
this point
Acceleration at
full power
γ c
Total take-off if distance
VCRVMCG
VTVS
L
W
TD
R
μR
The Aircraft can leave the ground when the velocity
reaches the Stall Velocity where Lift equals Weight
max,
2
0
2
1
Lstallstall CSVLW ρ==
max,0
12
L
stall
CS
W
V
ρ
=
The Liftoff Velocity is 1.1 to 1.2 Vstall.
11
ReactionGroundLWR
gW
RDT
td
Vd
V
V
td
xd
−=
−−
==
=
/
µ
( )
( )LWDT
gW
Vd
td
LWDT
gWV
Vd
sd xs
−−−
=
−−−
=
=
µ
µ
/
/
Takeoff (continue – 2)
Average Coefficient of Friction Values μ
Ground Run
SOLO
Aircraft Flight Performance
Ground run sg
Transition
distance st
Climb
distance sc
Stall safety
Take-off possible
with one engine
Continue take-off
if engine fails
after this point
Stop take-off if
engine fails before
this point
Acceleration at
full power
γ c
Total take-off if distance
VCRVMCG
VTVS
hc
L
W
R
μR
D
T
V
12
Takeoff (continue – 3)
SOLO
Aircraft Flight Performance
Ground run sg
Transition
distance st
Climb
distance sc
Stall safety
Take-off possible
with one engine
Continue take-off
if engine fails
after this point
Stop take-off if
engine fails before
this point
Acceleration at
full power
γc
Total take-off if distance
VCRVMCG
VTVS
hc
L
W
R
μR
D
T
V
T (Jet)
Lift,Drag,Thrust,Resistance–lb
L,D,T,R
T (Prop)
D +μ R
Ground Speed – ft/s
Texcess(Prop)=T(Prop) -(D+μ R)
Texcess(Jet)=T(Jet) -(D+μ R)
Vground
( )
ReactionGroundLWR
RDT
g
WV
−=
+−= µ

Ground Run (continue -1)
13
2
0 VCVBTT ++=
cVbVaVd
td
cVbVa
V
Vd
sd xs
++
=
++
=
=
2
2
1
Takeoff (continue – 4)
Ground Run (continue – 2)
To obtain an Analytic Solution assume that
during the Ground Run the Thrust can be
approximated by
Using






=
=
L
D
CSVL
CSVD
2
2
2
1
2
1
ρ
ρ
( )






−=
=
+−−=
µ
µ
ρ
W
T
gc
W
gB
b
W
gC
CC
W
Sg
a LD
0
:
2
:
2
:
where
SOLO
Aircraft Flight Performance
Ground run sg
Transition
distance st
Climb
distance sc
Stall safety
Take-off possible
with one engine
Continue take-off
if engine fails
after this point
Stop take-off if
engine fails before
this point
Acceleration at
full power
γ c
Total take-off if distance
VCRVMCG
VTVS
hc
L
W
R
μR
D
T
V
14
cVbVaVd
td
cVbVa
V
Vd
sd xs
++
=
++
=
=
2
2
1
Takeoff (continue – 5)
Ground Run (continue – 3)
Integrating those equations between two
velocities V1 and V2 gives






−
−
⋅
+
+
−
+
++
++
=
2
1
1
2
2
1
2
1
2
2
2
1
1
1
1
ln
42
ln
2
1
a
a
a
a
caba
b
cVbVa
cVbVa
a
sg






−
−
⋅
+
+
−
=
1
2
2
1
2 1
1
1
1
ln
4
1
a
a
a
a
cab
tg
where
cab
bVa
a
cab
bVa
a
4
2
:
4
2
:
2
2
2
2
1
1
−
+
=
−
+
=
SOLO
Aircraft Flight Performance
Ground run sg
Transition
distance st
Climb
distance sc
Stall safety
Take-off possible
with one engine
Continue take-off
if engine fails
after this point
Stop take-off if
engine fails before
this point
Acceleration at
full power
γ c
Total take-off if distance
VCRVMCG
VTVS
hc
L
W
R
μR
D
T
V
2
0 VCVBTT ++=
15
Takeoff (continue – 6)
Ground Run (continue – 4)
then
( )
( ) 











−
−
−−
=
+
=
TL
LDLD
g
CWT
CCCCg
SW
c
cVa
a
s
µ
µµρ
/
1
1
ln
/
ln
2
1
0
2
2
0,00 01 ==⇐== CBTTV
Assume
where
22
:&
/2
: VV
V
SW
C T
T
LT
==
ρ
A further simplification, using , givesZ
Z
Z 1
1
1
ln
<<
≈
−






−
=
µρ
W
T
Cg
SW
s
TL
g
0
/
SOLO
Aircraft Flight Performance
gL sCg
SW
W
T
T
ρ
/0
>
Ground run sg
Transition
distance st
Climb
distance sc
Stall safety
Take-off possible
with one engine
Continue take-off
if engine fails
after this point
Stop take-off if
engine fails before
this point
Acceleration at
full power
γc
Total take-off if distance
VCRVMCG
VTVS
hc
L
W
R
μR
D
T
V
16
Takeoff (continue – 7)
Rotation Distance
At the ground roll and just prior to going into transition phase, most aircraft are
Rotated to achieve an Angle of Attack to obtain the desired Takeoff Lift Coefficient
CL. Since the rotation consumes a finite amount of time (1 – 4 seconds), the distance
traveled during rotation sr, must be accounted for by using
where Δt is usually taken as 3 seconds.
SOLO
Aircraft Flight Performance
tVs tr ∆=
Ground Run
V = 0
sg
sTO
sr str
V TO
Rotation
Transition
sCL
θ CL
htr
hobs
R
L
W
R
μR
D
T
V
17
Takeoff (continue – 8)
Transition Distance
In the Transition Phase the Aircraft is in the Air (μ = 0) and turn to the Climb Angle.
The Equation of Motion are:
SOLO
Aircraft Flight Performance
Ta
Ta
t
Ta
t
VV
DT
VV
g
W
t
DT
VV
g
W
s
>







−
−
=
−
−
=
2
2
22
DT
gW
Vd
td
DT
gWV
Vd
sd xs
−
=
−
=
=
/
/
Assuming T – D = const., we can
Integrate the Equations of Motion
(assuming Va > VT)
Ground Run
V = 0
sg
sTO
sr str
V TO
Rotation
Transition
sCL
θ CL
htr
hobs
R
18
Takeoff (continue – 9)
Climb Distance
The Climb Distance is evaluated from the following (see Figure):
SOLO
Aircraft Flight Performance
c
c
c
c
c
hh
s
c
γγ
γ 1
tan
<<
≈=
For small angles of Climb L = W.
We can write Ground Run
V = 0
sg
sTO
sr str
V TO
Rotation
Transition
sCL
θ CL
htr
hobs
R
cL
cLD
c
c
c
C
CkC
W
T
L
D
W
T
,
2
,0 +
−=−=γ
We have
cLcLD
c
c
CkCCWT
h
s
,,0 // −−
≈
19
Takeoff (continue – 10)
SOLO
Aircraft Flight Performance
19
ctrgTO sssss +++=
sec41−=∆∆= ttVs tr
Ta
Ta
t
Ta
t
VV
DT
VV
g
W
t
DT
VV
g
W
s
>







−
−
=
−
−
=
2
2
22






−
−
⋅
+
+
−
+
++
++
=
2
1
1
2
2
1
2
1
2
2
2
1
1
1
1
ln
42
ln
2
1
a
a
a
a
caba
b
cVbVa
cVbVa
a
sg
cab
bVa
a
cab
bVa
a
4
2
:
4
2
:
2
2
2
2
1
1
−
+
=
−
+
=






−
−
⋅
+
+
−
=
1
2
2
1
2 1
1
1
1
ln
4
1
a
a
a
a
cab
tg
Ground Run
V = 0
sg
sTO
sr str
V TO
Rotation
Transition
sCL
θ CL
htr
hobs
R
Takeoff Summary
Rotation Phase
Climb Phase
Transition Phase
Ground Run
cLcLD
c
c
CkCCWT
h
s
,,0 // −−
≈
20Minimum required takeoff runway lengths.
Summary of takeoff requirements
In order to establish the allowable
takeoff weight for a transport
category airplane, at any airfield,
the following must be considered:
•Airfield pressure altitude
•Temperature
•Headwind component
•Runway length
•Runway gradient or slope
•Obstacles in the flight path
Return to Table of Content
21
Landing
Landing is similar to Takeoff, but in reverse.
We assume again that the Aircraft doesn’t have
VTOL capabilities.
The Landing Phase can be divide in the following
Phases:
1. The Final approach when the Aircraft
Glides toward the runway at a steady
speed and rate of descent.
2. The Flare, or Transition phase.
The Pilot attempts to rotate the Aircraft nose up and reduce the Rate of Sink to zero and the
forward speed to a minimum, that is larger than Vstall.
When entering this phase the velocity is less than 1.3Vstall and 1.15 Vstall at touchdown.
3. The Floating Phase, which is necessary if at the end of Flare phase, when the rate of
descent is zero, an additional speed reduction is necessary. The Float occurs when the
Aircraft is subjected to ground effect which requires speed reduction for touchdown.
4. The Ground Run after the Touchdown the Aircraft must reduce the speed to reach a
sufficient low one to be able to turn off the runway. For this it can use Thrust Reverse (if
available), spoilers or drag parachutes (like F-15 or MIG-21) and brakes are applied.
SOLO
Aircraft Flight Performance
Ground Run sgr
Transition
Airborne Phase
Total Landing Distance
Float
sf
Flare stGlide sg
γ
hg
hf
Touchdown
22
Landing (continue – 1)
Descending Phase
SOLO
Aircraft Flight Performance
The Aircraft is aligned with the landing runaway at an altitude hg and a gliding angle γ.
The Aircraft Glides toward the runway at a steady speed and rate of descent, until it reaches
The altitude ht at which it goes to Transition Phase, turning with a Radius of Turn R. The
Descending Range on the ground is :
γγ
γ
γ
γ RhRhhh
s
ggtg
g
−
≈
−
=
−
=
<<1
tan
cos
tan
Ground Run sgr
Transition
Airborne Phase
Total Landing Distance
Float
sf
Flare stGlide sg
γ
hg
hf
Touchdown
23
Landing (continue – 2)
Transition Phase
SOLO
Aircraft Flight Performance
If γ is the descent angle and R is the turn radius
then the Aircraft must start the Transition Phase
at an altitude ht, above the ground, given by:
( )γcos1−=Rht
The Transition Range on the ground is
γγ RRst ≈= sin
To calculate the turn radius we must use the flight velocity which varies between 1.3 Vstall
at the beginning to 1.1 Vstall at Touchdown. Let use an average velocity
3.11.1 −∈= tstalltt mVmV
If the Transition Turn Acceleration is nt = 1.15 – 1.25 g than the Turn Radius is
( ) gn
V
R
t
t
1
2
−
=
The Transition Turn time is
( ) gn
V
RV
t
t
t
t
t
1/ −
==
γγ
Ground Run sgr
Transition
Airborne Phase
Total Landing Distance
Float
sf
Flare stGlide sg
γ
hg
hf
Touchdown
24
Landing (continue – 3)
Float Phase
SOLO
Aircraft Flight Performance
In this phase the Pilot brings the nose wheel to the ground at the touchdown velocity Vt:
tVs tf ∆=
where Δt is between 2 to 3 seconds.
Ground Run sgr
Transition
Airborne Phase
Total Landing Distance
Float
sf
Flare stGlide sg
γ
hg
hf
Touchdown
25
Landing (continue – 4)
Ground Run Phase
SOLO
Aircraft Flight Performance
The equations of motion are the same as those
developed for Takeoff, but with different
parameters, adapted for Landing. Those equations
are:
cVbVaVd
td
cVbVa
V
Vd
sd xs
++
=
++
=
=
2
2
1
( )






−=
=
+−−=
µ
µ
ρ
W
T
gc
W
gB
b
W
gC
CC
W
Sg
a grLgrD
0
,,
:
2
:
2
:
where






−
−
⋅
+
+
−
+
++
++
=
2
1
1
2
2
1
2
1
2
2
2
1
1
1
1
ln
42
ln
2
1
a
a
a
a
caba
b
cVbVa
cVbVa
a
sg






−
−
⋅
+
+
−
=
1
2
2
1
2 1
1
1
1
ln
4
1
a
a
a
a
cab
tg
where
cab
bVa
a
cab
bVa
a
4
2
:
4
2
:
2
2
2
2
1
1
−
+
=
−
+
=
2
0 VCVBTT ++=
Assume a constant Thrust T = T0: B = 0, C = 0. V1 = Vtouchdown, V2 = final velocity
cVa
cVa
a
sg
+
+
−= 2
2
2
1
ln
2
1






−
−
⋅
+
+
−
=
1
2
2
1
1
1
1
1
ln
4
1
a
a
a
a
ca
tg ( ) 





−==−−= µµ
ρ
W
T
gcbCC
W
Sg
a LD
0
:,0,
2
:
Ground Run sgr
Transition
Airborne Phase
Total Landing Distance
Float
sf
Flare stGlide sg
γ
hg
hf
Touchdown
26
Landing (continue – 5)
Ground Run Phase (continue – 1)
SOLO
Aircraft Flight Performance
where
( )






−=
−−=
µ
µ
ρ
W
T
gc
CC
W
Sg
a grLgrD
0
,,
:
2
:
cab
Va
a
ca
Va
a
touchdown
4
2
:
4
2
:
2
1
1
−
=
−
=
Assume a constant Thrust T = T0: B = 0, C = 0. V1 = Vtouchdown,
V2 = final velocity
cVa
cVa
a
sg
+
+
−= 2
2
2
1
ln
2
1






−
−
⋅
+
+
−
=
1
2
2
1
1
1
1
1
ln
4
1
a
a
a
a
ca
tg
For the Landing Ground Run Phase the following must included:
• if Thrust Reversal exists we must change T0 to – T0_reversal .
•The Drag Coefficient CD0,gr must consider:
- the landing gear fully extended.
- spoilers or drag parachutes (if exist)
•μ – the friction coefficient must be increased to describe the brakes effect.
Ground Run sgr
Transition
Airborne Phase
Total Landing Distance
Float
sf
Flare stGlide sg
γ
hg
hf
Touchdown
27
Landing (continue – 6)
Summary
SOLO
Aircraft Flight Performance
where
( )






−=
−−=
µ
µ
ρ
W
T
gc
CC
W
Sg
a grLgrD
0
,,
:
2
:
cab
Va
a
ca
Va
a
touchdown
4
2
:
4
2
:
2
1
1
−
=
−
=cVa
cVa
a
sg
+
+
−= 2
2
2
1
ln
2
1






−
−
⋅
+
+
−
=
1
2
2
1
1
1
1
1
ln
4
1
a
a
a
a
ca
tg
Ground Run Phase
tVs tf ∆=
Float Phase
( ) gn
V
Rs
t
t
t
1
2
−
==
γ
γ
( ) gn
V
RV
t
t
t
t
t
1/ −
==
γγ
Transition Phase
Descent Phase
Ground Run sgr
Transition
Airborne Phase
Total Landing Distance
Float
sf
Flare stGlide sg
γ
hg
hf
Touchdown
( )
γγ
γ
γ
1/
tan
cos
tan
2
−−
=
−
=
−
=
ttggfg
g
nVhRhhh
s
28
H.H. Hurt, Jr., “Aerodynamics for Naval Aviators “,NAVAIR 00=80T-80 1-1-1965, pg. 35
Return to Table of Content
29
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
The forces acting on an airplane in Level Flight are
shown in Figure
0=
=
h
Vx


Lift and Drag Forces:
( ) TCkCSVCSVD
WCSVL
LDD
L
=+==
==
2
0
22
2
2
1
2
1
2
1
ρρ
ρ 2
2
VS
W
CL
ρ
=






+=





+=
SV
Wk
CSV
SV
Wk
CSVD DD 2
2
0
2
242
2
0
2 2
2
14
2
1
ρ
ρ
ρ
ρ
Lift
DragThrust
Weight
Equations of motion:
0
0
=−
=−
DT
WL
Quasi-Static
30
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight

DragInducedDragParasite
D
SV
Wk
CSVD 2
2
0
2 2
2
1
ρ
ρ +=
Because of opposite trends in
Parasite Drag and Induced Drag,
with changes in velocity, the Total
Drag assumes a minimum at a
certain velocity. If we ignore the
change in velocity of CD0 and k with
velocity we obtain
0
4
3
2
0 =−=
SV
Wk
CSV
Vd
Dd
D
ρ
ρ
The velocity of minimum Total
Drag is
*
4
0
2
V
C
k
S
W
V
D
==
ρ
We see that the velocity of minimum Total Drag is equal to the Reference Velocity.
0
2
2
1
DCSVρ
SV
Wk
2
2
2
ρ*
V
Lift
DragThrust
Weight
31
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
For the velocity, V*, of minimum
Total Drag we have
02*
2
2
Di CkW
SV
Wk
D ==
ρ

DragInducedDragParasite
D
SV
Wk
CSVD 2
2
0
2 2
2
1
ρ
ρ +=
000min 2 DDD CkWCkWCkWD =+=
and
0
2
2
1
DCSVρ
SV
Wk
2
2
2
ρ
*
V
Lift
DragThrust
Weight
32M. Corcoran, T. Matthewson, N. W. Lee, S. H. Wong, “Thrust Vectoring”
Comparison of Takeoff Weight and Empty Weight of different Aircraft
33
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
The Power Required, PR, for Level Flight is
SV
Wk
CSVVDP DR
ρ
ρ
2
0
3 2
2
1
+=⋅=
The Power Required for Level Flight
assumes a minimum at a certain velocity Vmp.
If we ignore the change in velocity of CD0 and
k with velocity we obtain
0
2
2
3
2
2
0
2
=−=
SV
Wk
CSV
Vd
Pd
D
R
ρ
ρ
or
*
4
0 3
1
3
2
V
C
k
S
W
V
D
mp ==
ρ
*0
2, 3
32
L
D
mp
mpL C
k
C
VS
W
C ===
ρ
( )
*
000
0
2
,0
,
866.0
1
4
3
/3
/3
e
CkkCkC
kC
CkC
C
e
DDD
D
mpLD
mpL
mp ==
+
=
+
= *
2
min,
866.03
8
e
VW
SV
Wk
P mp
mp
R ==
ρ
0
3
2
1
DCSVρ
SV
Wk
ρ
2
2
*
3
1
V
min,RP
Lift
DragThrust
Weight
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Available Aircraft Power and Thrust
• Throttle Effect
10 ≤≤= ηη ATT
• Propeller
airspeedwithvariationsmallVTP propellerA ≈⋅=,
V
Pa, propeller
Power
Propeller Aircraft Available Power
at Altitude (h)
At a given Altitude h
• Turbojet
airspeedwithvariationsmallT jetA ≈,
V
Ta, jet
Thrust
Jet Aircraft Available Power
at Altitude h
At a given Altitude h
Lift
DragThrust
Weight
Lift
DragThrust
Weight
Level Flight
35
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Vmin Vmax
Pa, propeller
PRPmin
BA
ηaPa, propeller
Propeller Aircraft
Vmin Vmax
Ta, jet
TR
Dmin
η Ta, jet
A
B
Jet Aircraft
Level Flight
To have a Level Flight the requirement must be satisfied by
the available propulsion performance.
•For a Propeller Aircraft, the available power Pa,propeller , at a
given altitude h, is almost insensitive with changes in velocity.
The Velocity in Level Flight is steady when the graph of
Required Power PR intersects the graph of Pa,propeller at points A
and B. We get two velocities Vmin (h) at A and Vmax (h) at B. By
controlling the Propeller Power ηa Pa,propeller (0< ηa <1) we can
reach any velocity between
Vmin (h) and Vmax (h).
•For a Jet Aircraft, the available Thrust Ta,jet , at a given
altitude h, is almost insensitive with changes in velocity. The
Velocity in Level Flight is steady when the graph of Required
Thrust TR intersects the graph of Ta,jet at points A and B. We
get two velocities Vmin (h) at A and Vmax (h) at B. By
controlling the Jet Thrust η Ta,jet (0< η<1) we can reach any
velocity between Vmin (h) and Vmax (h).
36
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Vmin Vmax
Ta, jet
TR
Dmin
η Ta, jet
A
B
Jet Aircraft
Level Flight
We have
Analytical Solution for Jet Aircraft
( ) SV
Wk
CSVCkCSVDT DLD 2
2
0
22
0
2 2
2
1
2
1
ρ
ρρ +=+==
Define
0
*
0
0
*
*
*
4
0
2
:
2*,*,:
2
:*,
*
:
D
DD
D
L
D
L
D
CkW
T
W
eT
z
CC
k
C
C
C
C
e
C
k
S
W
V
V
V
u
==
===
==
ρ


 2
2
/1
2
0
0
2
2
0
2
2
2
u
D
u
Dz
D
V
C
k
S
W
C
k
S
W
V
T
CkW
ρ
ρ
+=
012 24
=+− uzu
Lift
DragThrust
Weight
37
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Vmin Vmax
Ta, jet
TR
Dmin
η Ta, jet
A
B
Jet Aircraft
Level Flight
Analytical Solution for Jet Aircraft
012 24
=+− uzu
Solving we obtain
1
1
2
max
2
min
−+=
−−=
zzu
zzu
4
0
maxmaxmax
4
0
minminmin
2
*
2
*
D
D
C
k
S
W
uVuV
C
k
S
W
uVuV
ρ
ρ
==
==
Lift
DragThrust
Weight
0
*
0
0
*
*
*
4
0
2
:
2*,*,:
2
:*,
*
:
D
DD
D
L
D
L
D
CkW
T
W
eT
z
CC
k
C
C
C
C
e
C
k
S
W
V
V
V
u
==
===
==
ρ
38
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Analytical Solution for Jet Aircraft
1
1
2
max
2
min
−+=
−−=
zzu
zzu
12
min −−= zzu
12
max −+= zzu
At the absolute Ceiling (when is only one possible velocity) we have umax = umin, therefore
z = 1.
max,
2
L
stall
CS
W
V
ρ
=
Lift
DragThrust
Weight
0
*
0
0
*
*
*
4
0
2
:
2*,*,:
2
:*,
*
:
D
DD
D
L
D
L
D
CkW
T
W
eT
z
CC
k
C
C
C
C
e
C
k
S
W
V
V
V
u
==
===
==
ρ
39
Drag Characteristics
Fixed Wing Fighter Aircraft Flight Performance
SOLO
40
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Aircraft Range in Level Flight
Lift
DragThrust
Weight
Range in Level Flight of Jet Aircraft
Equations of motion:
0
0
=−
=−
DT
WL
0=
=
h
Vx


We add the equation of fuel consumption
TcW −=
c – specific fuel consumption
We assume that fuel consumption is constant for a given altitude.
V
td
Wd
Wd
xd
td
xd
==
Dc
V
Tc
V
W
V
Wd
xd DT
−=−==
=

41
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Aircraft Range in Level Flight
Lift
DragThrust
Weight
Range in Level Flight of Jet Aircraft
Dc
V
Wd
xd
−=
The quantity dx/dW is called the “Instantaneous Range”
and is equal to the Horizontal Range traveled per unit load
of fuel or the “Specific Range”.
Multiply and divide by L = W
Wc
V
C
C
Wc
V
D
L
Wd
xd
D
L






−=











−=
Integrating we obtain
∫ 





−=−=
f
i
W
W
D
L
if
W
Wd
V
cC
C
xxR
1
:
42
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Aircraft Range in Level Flight
Lift
DragThrust
Weight
Range in Level Flight of Jet Aircraft
To perform the integration we must specify the variation
of CL, CD and V. Let consider two cases:
∫ 





−=−=
f
i
W
W
D
L
if
W
Wd
V
cC
C
xxR
1
:
a. Range at Constant Altitude of Jet Aircraft
We have LCVSLW 2
2
1
ρ==
LCS
W
V
ρ
2
=
The velocity changes (decreases) since the weight W decreases due to fuel
consumption.
[ ]if
D
L
W
W
D
L
WW
C
C
cW
Wd
ScC
C
R
f
i
−








=








−= ∫
221
ρ
43
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Aircraft Range in Level Flight
Lift
DragThrust
Weight
a. Range at Constant Altitude of Jet Aircraft
[ ]if
D
L
W
W
D
L
WW
C
C
cW
Wd
ScC
C
R
f
i
−








=








−= ∫
221
ρ
The maximum range is obtained when
[ ]if
D
L
WW
C
C
c
R −








=
max
max
2
max
2
0max








+
=








LD
L
D
L
CkC
C
C
C
( )
030
2
2
1
2
022
0
2
0
2
0
=−⇒=
+
−
+
=








+
LD
LD
LL
L
LD
LD
L
L
CkC
CkC
CkC
C
CkC
CkC
C
Cd
d
The maximum range is obtained when
*0
3
1
3
1
L
D
L C
k
C
C ==
The Velocity at maximum range is ( ) ( ) ( ) ( )tV
CS
tW
CS
tW
tV
LL
*4
*
4
*
3
2
3
3/
2
===
ρρ
44
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Aircraft Range in Level Flight
Lift
DragThrust
Weight
b. Range at Constant Velocity of Jet Aircraft














=





−= ∫ f
i
D
L
W
W
D
L
W
W
C
C
c
V
W
Wd
V
cC
C
R
f
i
ln
1
The Velocity V is constant and equal to V* corresponding to initial weight Wi.
4
0
*
* 22
D
i
L
i
C
k
S
W
CS
W
V
ρρ
==
The maximum range is obtained when








=














=
f
i
f
i
D
L
W
W
e
c
V
W
W
C
C
V
c
R lnln
1 *
*
max
max
To keep Velocity V constant when weight W decreases, the air density ρ must
also decrease, hence the Aircraft will gain (qvasistatic) altitude
( ) Pc
td
Wd
td
hd
e
td
hd
p
hh
−==−= − 0/
0ρ
ρ
45
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Aircraft Range in Level Flight
Range in Level Flight of Propeller Aircraft
Lift
DragThrust
Weight
The equation of fuel consumption
PcW P−=
cp – specific fuel consumption (consumed per unit power developed by the engine per
unit time
We assume that fuel consumption is constant for a given altitude.
V
td
Wd
Wd
xd
td
xd
==
Pc
V
W
V
Wd
xd
p
−==

- Required PowerVDPR ⋅=
PP pA ⋅=η - Available Power
ηp – propulsive efficiency
AR PP =
p
VD
P
η
⋅
=
46
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Aircraft Range in Level Flight
Range in Level Flight of Propeller Aircraft
Lift
DragThrust
Weight
WcC
C
WcD
L
DcPc
V
Wd
xd
p
p
D
L
p
p
WL
p
p
p
ηηη






−=−=−=−=
=
Integration gives ∫ 





−=−=
f
i
W
W
p
p
D
L
ff
W
Wd
cC
C
xxR
η
:
We assume
• Angle of Attack is kept constant throughout cruise, therefore e = CL/CD is
constant
•ηp is independent on flight velocity
f
i
p
p
W
W
e
c
R ln
η
= Bréguet Range Equation
The maximum range of Propeller Aircraft in Level Flight is
f
i
Dp
p
f
i
p
p
W
W
CkcW
W
e
c
R ln
2
1
ln
0
*
max
ηη
==
47
Louis Charles Bréguet
(1880 – 1955)
The Bréguet Range Equation
The Bréguet range equation determines the maximum flight
distance. The key assumptions are that SFC, L/D, and flight speed,
V are constant, and therefore take-off, climb, and descend portions
of flights are not well modeled (McCormick, 1979; Houghton,
1982).
( )








⋅
=
final
initial
W
W
SFCg
DLV
Range ln
/
Winitial = Wfuel + Wpayload + Wstructure + Wreserve
Wfinal = Wpayload + Wstructure + Wreserve
where
( )








++
+
⋅
=
reservestructurepayload
fuel
WWW
W
SFCg
DLV
Range 1ln
/
where SFC, L/D, and Wstructure are technology parameters while Wfuel, Wpayload, and Wreserve are
operability parameters.
Fixed Wing Fighter Aircraft Flight Performance
SOLO
48
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Aircraft Range in Level Flight
Range in Level Flight of Propeller Aircraft
Lift
DragThrust
Weight
Let assume that the flight to maximum range is
performed in one of two ways
1. Propeller Aircraft Flight at Constant Altitude
In Constant Altitude Flight the velocity changes with the decrease of weight such that
( ) ( ) 4
0
* 2
DC
k
S
tW
VtV
ρ
==
2. Propeller Aircraft Flight with Constant Velocity
In Constant Velocity Flight the velocity is the V* velocity based on the initial weight
of the Aircraft
.
2
4
0
*
const
C
k
S
W
VV
D
i
===
ρ
49
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Aircraft Endurance in Level Flight
Lift
DragThrust
Weight
The Endurance of an Airplane remains in the air and is
usually expressed in hours.
Endurance of Jet Aircraft in Level Flight
We have TcW −=
c – specific fuel consumption
W
Wd
c
e
W
Wd
D
L
cDc
Wd
Tc
Wd
td
WLDT
−=−=−=−=
== 1
Integrating we obtain
∫−=
f
i
W
W W
Wd
c
e
t
Assuming that the Angle of Attack is held constant throughout the flight, e =CL/CD is constant
f
i
W
W
c
e
t ln=
f
i
Df
i
W
W
CkcW
W
c
e
t ln
2
1
ln
0
*
max ==
The Maximum Endurance for Jet Aircraft occurs for e = e*, CL = CL*, V = V*, D = Dmin.
50
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Aircraft Endurance in Level Flight
The Endurance of an Airplane remains in the air and is
usually expressed in hours.
Endurance of Propeller Aircraft in Level Flight
We have ppp VDcPcW η/⋅−=−=
W
Wd
V
e
cW
Wd
VD
L
cVD
Wd
c
td
p
p
p
p
WL
p
p 11 ηηη
−=−=
⋅
−=
=
Assuming that the Angle of Attack is held constant throughout the flight, e =CL/CD is constant
Lift
DragThrust
Weight
cp – specific fuel consumption (consumed per unit power
developed by the engine per unit time.
ηp – propulsive efficiency
Integrating we obtain
∫−=
f
i
W
W
p
p
W
Wd
V
e
c
t
1η
The Endurance of Propeller Aircraft depends on Velocity, therefore we will assume two cases
1.Flight at Constant Altitude
2.Flight with Constant Velocity
51
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Endurance of Propeller Aircraft in Level Flight
Lift
DragThrust
Weight
The velocity will change to compensate for the decrease in weight
∫ =−=
f
i
W
W
D
L
p
p
C
C
e
W
Wd
V
e
c
t
1η
1. Propeller Aircraft Flight at Constant Altitude
We have LCVSLW 2
2
1
ρ==
LCS
W
V
ρ
2
=








−







=
ifD
L
p
p
WW
S
C
C
c
t
11
2
2 2/3
ρη
For Maximum Endurance Propeller Aircraft has to fly at that Angle of Attack such that
(CL
3/2
/CD) is maximum, which occurs when CL=√3 CL
*
and V = 0.76 V*
.








−







=
ifDp
p
WW
S
Ckc
t
11
2
27
4
12
0
3max
ρη
52
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Level Flight
Endurance of Propeller Aircraft in Level Flight
Lift
DragThrust
Weight
∫ =−=
f
i
W
W
D
L
p
p
C
C
e
W
Wd
V
e
c
t
1η
2. Propeller Aircraft Flight with Constant Velocity
f
i
p
p
W
W
V
e
c
t ln
1η
=
For Maximum Endurance Propeller Aircraft has to fly at a velocity such that e=(CL/CD) is
maximum, which occurs when CL=CL
*
and V = V*
, which is based on initial weight Wi
4
0
*
* 22
D
i
L
i
C
k
S
W
CS
W
V
ρρ
==
0
*
2
1
DCk
e =
f
i
D
i
p
p
f
i
D
i
Dp
p
f
i
p
p
W
W
CkS
W
cW
W
C
k
S
W
CkcW
W
V
e
c
t ln
1
2
ln
2
2
1
ln
1
4
3
0
4
00
*
*
max
ρ
η
ρ
ηη
===
53
D=TR
V
V*
tmax
Slope min(PR/V)
Bréguet
Velocities for Maximum Range and Maximum
Endurance of Propeller Aircraft
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Graphical Finding of Maximum Range and
Endurance of Jet Aircraft in Level Flight






=





⇔
V
D
D
V
R
VV
minmaxmax
Maximum Range
From Figure we can see that min (D/V) is
obtained by taking the tangent to D
graph that passes through origin.
The point of tangency will give D and V
for (D)min.
Maximum Endurance
 ∫∫
<
=
<
−=−=
00
111
Wd
Dc
Wd
Tc
t
DT
( )D
D
t
VV
min
1
maxmax =





⇔
From Figure we can see that min (PR) is
obtained by taking the PR and V for (PR)min.
Lift
DragThrust
Weight
∫∫
<
−==
0
Wd
Dc
V
xdR
54
PR
V
V*
Rmax
0.866 V*
tmax
Slope min(PR/V)
Velocities for Maximum Range and Maximum
Endurance of Propeller Aircraft
Lift
DragThrust
Weight
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Graphical Finding of Maximum Range and
Endurance of Propeller Aircraft in Level Flight
  ∫∫∫∫
>>>
⋅
−=−=−==
000
Wd
VD
V
c
Wd
P
V
c
Wd
Pc
V
xdR
p
p
Rp
p
p
ηη
D
V
P
P
V
R
V
R
V
R
V
minminmaxmax =





=





⇔
Maximum Range
From Figure we can see that min (PR/V)
is obtained by taking the tangent to PR
graph that passes through origin.
The point of tangency will give PR and V
for (PR/V)min.
Maximum Endurance
 ∫∫
<<
−=−=
00
11
Wd
Pc
Wd
Pc
t
Rp
p
p
η
( ) ( )VDP
P
t
V
R
V
R
V
⋅==





⇔ minmin
1
maxmax
From Figure we can see that min (PR) is
obtained by taking the PR and V for (PR)min.
55
H.H. Hurt, Jr., “Aerodynamics for Naval Aviators “,NAVAIR 00-80T-80 1-1-1965, pg. 35
Fixed Wing Fighter Aircraft Flight Performance
56
H.H. Hurt, Jr., “Aerodynamics for Naval Aviators “,NAVAIR 00-80T-80 1-1-1965, pg. 35
Fixed Wing Fighter Aircraft Flight Performance
57
H.H. Hurt, Jr., “Aerodynamics for Naval Aviators “,NAVAIR 00-80T-80 1-1-1965, pg. 35
Fixed Wing Fighter Aircraft Flight Performance
58
Flight Ceiling by the
available Climb Rate
- Absolute 0 ft/min
- Service 100 ft/min
- Performance 200 ft/min
True Airspeed
Altitude
Absolute Ceiling
Service Ceiling
Performance Ceiling
Excess Thrust
provides the ability
to accelerate or climb
True Airspeed
Thrust Available
Thrust
Required
Thrust
True Airspeed
Thrust
Available
Thrust
Required
Thrust
A AB B
C D
E
E
Thrust
True Airspeed
Available
Thrust
Required
Thrust
C D
Jet Aircraft Flight Envelope Determined by Available Thrust
Flight Envelope: Encompasses all Altitudes
and Airspeeds at which Aircraft can Fly
Stengel, MAE331, Lecture 7, Gliding, Climbing and Turning Performance
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Lift
DragThrust
Weight
Changes in Jet Aircraft
Thrust with Altitude
59
Propeller Aircraft Ceiling Determined by Available Power
To find graphically the maximum Flight Altitude (Ceiling) for a Propeller Aircraft we use
the PR (Power Required) versus V (Velocity) graph. The maximum Flight Altitude
corresponds to maximum Range Rmax.
We have shown that to find Rmax we draw the Tangent Line to PR Graph, passing trough
the origin.
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Lift
DragThrust
Weight
Changes in Propeller Aircraft Power
and Thrust with Altitude
VC
Pa, propeller
PR
hcruise
A
h2
h1
h0
h0 < h1 <h2 < hcruise
The intersection point A with PR Graph defines the Ceiling Velocity VC, and the Pa
(Available Power – function of Altitude) with this point defines the Ceiling Altitude.
Return to Table of Content
60
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Gliding Flight
A Glider is an unpowered airplane.
0
sin
cos
=
=
=
W
Vh
Vx



γ
γ
1<<γ
0=+
=
γWD
WL
.constW
Vh
Vx
=
=
=
γ

Lift and Drag Forces:
( ) γρρ
ρ
WCkCSVCSVD
WCSVL
LDD
L
−=+==
==
2
0
22
2
2
1
2
1
2
1
LCS
W
V
ρ
2
=
eC
C
L
D
W
D
L
D
LW 1
−=−=−=−=
=
γ
Equations of motion:
0sin
0cos
=+
=−
γ
γ
WD
WLQuasi-Steady
Flight
61
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Gliding Flight
We found
LCS
W
V
ρ
2
= eC
C
L
D
W
D
L
D
LW 1
−=−=−=−=
=
γ
Flattest Glide” (γ = γmin)
The Flattest Glide (γ = γmin) is given by:
0
*
max
min
min 22
1
DL CkCk
eW
D
−=−=−=−=γ
e
LC*LC
*2
1
LCk
CL/CD as a function of CL
k
C
C D
L
0
* =
The flight velocity for the Flattest Glide is given by:
4
0
*..
2
*
2
DL
GF
C
k
S
W
V
CS
W
V
ρρ
===
The flight velocity for the Flattest Glide is equal to the reference velocity V*
or u = 1.
The Flattest Glide is conducted at constant dynamic pressure.
.
2
1
0
*
2
.. const
C
k
W
C
W
VSq
DL
GFG ==== ρ
62
H.H. Hurt, Jr., “Aerodynamics for Naval Aviators “,NAVAIR 00=80T-80 1-1-1965, pg. 35
Gliding Flight
CLEAR CONFIGURATION
LANDING CONFIGURATION
LIFT to DRAG
RATIO
L/D
(L/D)max
LIFT COEFFICIENT, CL
CLEAR CONFIGURATION
LANDING CONFIGURATION
RATEOF
SINK
VELOCITY
(L/D)max
TANGENT TO RATE OF SINK
GRAPH AT THE ORIGIN
Gliding Performance
Fixed Wing Fighter Aircraft Flight Performance
SOLO
63
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Gliding Flight
We have:
Distance Covered with respect to Ground
The maximum Ground Range is covered for the Flattest Glide at the reference
velocity V*
or u = 1.
γV
td
hd
V
td
xd
=
=
D
L
e
V
V
hd
xd
−=−===
γγ
1
Assuming a constant Angle of Attack during Glide, e is constant and the Ground
Range R, to descend from altitude hi to altitude hf is given by:
( ) hehhehdexxR fi
h
h
if
f
i
∆=−=−=−= ∫:
and
0
maxmax
2 DCk
h
heR
∆
=∆=
e
LC*LC
*2
1
LCk
CL/CD as a function of CL
64
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Gliding Flight
Rate of sink is defined as:
Rate of Sink








==
⋅
=−=−=
=
=
2/3
2
22
L
D
L
D
L
L
D
W
D
CS
W
V
s
C
C
S
W
C
C
CS
W
W
VD
V
td
hd
h
L
ρρ
γ
ρ

The term DV = PR represents the Power Required to sustain the Gliding Flight.
Therefore the Rate of Sink is minimum when the Power Required is minimum, or
(CD/CL
3/2
) is minimum
( ) ( ) 0
2
3
2
342
3
2
2/5
0
2
2/5
2
0
2
3
2
0
2/12/3
2/3
2
0
2/3
=
−
=
+−
=
+−
=






 +
=







L
DL
L
LDL
L
LDLLL
L
LD
LL
D
L C
CCk
C
CkCCk
C
CkCCCCk
C
CkC
Cd
d
C
C
Cd
d
Denote by CL,m the value of Lift Coefficient CL for which (CD/CL
3/2
) is minimum
*0
, 3
3
0*
L
k
C
C
D
mL C
k
C
C
D
L =
== 27
4
3
3
0
3
2/3
0
0
0
min
2/3
D
D
D
D
L
D Ck
k
C
k
C
kC
C
C
=






+
=







65
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Gliding Flight
Rate of Sink
*0
, 3
3
0*
L
k
C
C
D
mL C
k
C
C
D
L =
==
0
3
max
2/3
27
4
1
DD
L
CkC
C
=







We found:
The velocity Vm for glide with minimum
sink rate is given by:

*
4
0
76.0~
4
4
0,
76.0
2
3
1
3
22
*
V
C
k
S
W
C
k
S
W
CS
W
V
V
D
DmL
m
≈







=
==
  
ρ
ρρ
S
CkW
C
C
S
W
h D
L
D
s
ρρ 27
22 0
3
min
2/3min, =







=
The minimum sink rate is given by:
66
Fixed Wing Fighter Aircraft Flight Performance
SOLO
Gliding Flight
Endurance
The Endurance is the total time the glider remains in the
air.
Minimum
Sink Rate
tmax
Flatest
Glide
Rmax








−== 2/3
2
L
D
C
C
S
W
V
td
hd
ρ
γ








−==
D
L
C
C
W
S
V
hd
td
2/3
2
ρ
γ
( )fi
D
L
h
h
D
L
hh
C
C
W
S
hd
C
C
W
S
t
f
i
−







=







−= ∫
2/32/3
22
ρρ
Assuming that the Angle of Attack is held constant during
the glide and ignoring the variation in density as function
of altitude, we have
For Maximum Endurance the Glider has to fly at that
Angle of Attack such that (CL
3/2
/CD) is maximum, which
occurs when CL=√3 CL
*
and V = 0.76 V*
.





 −
=
4
27
2
4
0
3max
fi
D
hh
CkW
S
t
ρ
Return to Table of Content
67
Performance of an Aircraft with Parabolic PolarSOLO
W
LT
n
+
=
αsin
:'
W
L
n =:
2
0
:
LD
L
D
L
CkC
C
CSq
CSq
D
L
e
+
===
We assume a Parabolic Drag Polar:
2
0 LDD CkCC +=
Let find the maximum of e as a function of CL
( ) ( )
0
2
22
0
2
0
22
0
22
0
=
+
−
=
+
−+
=
∂
∂
LD
LD
LD
LLD
L CkC
CkC
CkC
CkCkC
C
e e
LC*LC
*2
1
LCk
CL/CD as a function of CL
The maximum of e is obtained for
k
C
C D
L
0
* =
( ) 0
0
0
2
0 2** D
D
DLDD C
k
C
kCCkCC =+=+=
Start with
Load Factor
Total Load Number
Lift to Drag Ratio
Climbing Aircraft Performance
68
Performance of an Aircraft with Parabolic PolarSOLO
e
LC*LC
*2
1
LCk
CL/CD as a function of CL
The maximum of e is obtained for
k
C
C D
L
0
* =
( ) 0
0
0
2
0 2** D
D
DLDD C
k
C
kCCkCC =+=+=
*2
1
*2
1
2
1
2*
*
*
22
00
0
LLDD
D
D
L
CkCkCkC
k
C
C
C
e =====
We have WnCSVCSqL LL === 2
2
1
ρ
Let define for n = 1












=
=
==
2
4
0
*
2
1
:*
*
:
2
*
2
1
:*
Vq
V
V
u
C
k
S
W
CS
W
V
D
L
ρ
ρρ
2
0
:
LD
L
D
L
CkC
C
CSq
CSq
D
L
e
+
===
Climbing Aircraft Performance
69
Performance of an Aircraft with Parabolic PolarSOLO
Using those definitions we obtain
L
L
L
L
C
C
nqq
WCSq
WnCSqL *
*
**
=→



=
==
2
2
2
1
2
1
*
2
1
*
uV
V
n
q
q
==
ρ
ρ
2
*
*
*
u
C
nC
q
q
nC L
LL ==
( )






+=





+=






+=+=
=
2
2
2
04
02
0
2
*
4
2
2
0
22
0
**
*
*
0
2
u
n
uCSq
u
C
nCuSq
u
C
nkCuSqCkCSqD
D
D
D
CCk
L
DLD
DL










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
*2
1
*
*** 0
0
e
W
C
C
CSqCSq
L
D
LD ==






+= 2
2
2
*2 u
n
u
e
W
D
Therefore
Return to Table of Content
Climbing Aircraft Performance
70
Performance of an Aircraft with Parabolic PolarSOLO
We obtained 





+= 2
2
2
*2 u
n
u
e
W
D
u 0
- - - - 0 + + + + +
D ↓ min ↑
n
u
D
∂
∂
Let find the minimum of D as function of u.
nu
u
nu
e
W
u
n
u
e
W
u
D
=→
=
−
=





−=
∂
∂
2
3
24
3
2
0
*
22
*2
*
2min
e
Wn
DD nu
== =
Aircraft Drag
Climbing Aircraft Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
71
Performance of an Aircraft with Parabolic PolarSOLO
Aircraft Drag
( )
MAXn
W
VhL
n ≤=
,








+== 2
2
2
*2 u
n
u
e
W
D MAX
nn MAX
Maximum Lift Coefficient or Maximum Angle of Attack
( ) ( ) ( )VhorMCMC STALLMAXLL ,, _ ααα ≤≤
We have
u
C
C
u
n
u
C
nC
q
q
nC
L
MAXL
CC
L
LL
MAXLL
*
*
*
* _
2
_
=→==
=
2
2
_
2
2
_2
*
1
*2
**2_
u
C
C
e
W
u
C
C
u
e
W
D
L
MAXL
L
MAXL
CC MAXLL














+=














+==
Maximum dynamic pressure limit
( ) ( ) MAX
MAX
MAXMAX u
V
V
uhVVorqVhq =<→≤≤= :
*2
1 2
ρ
*e
W
D
MAXLC _
2
2
_
1
2
1
u
C
C
L
MAXL














+








+= 2
2
2
2
1
*
u
n
ue
W
D MAX
LIMIT
nn MAX=
2min
* ue
W
D
=






+= 2
2
2
2
1
*
u
n
ue
W
D
MAXuu =MAX
MAXL
L
CORNER n
C
C
u
_
*
=
n
LIMIT
u
MAXnu =
as a function of u*e
W
D
Maximum Load Factor
Climbing Aircraft Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
72
Performance of an Aircraft with Parabolic PolarSOLO
Energy per unit mass E
Let define Energy per unit mass E:
g
V
hE
2
:
2
+=
Let differentiate this equation:
( ) ( )
W
VDT
W
VDT
W
DT
g
g
V
V
g
VV
hEps
−
≈
−
=











−
−
+=+==
α
γ
α
γ
cos
sin
cos
sin:


*&
*2 2
2
2
VuV
u
n
u
e
W
D =





+=
Define *: e
W
T
z 





=
We obtain ( )












+−=












+−





=
−
= 2
2
2
2
2
2
2
1
*
*
*
2
1
*
*
u
n
uzu
e
V
W
Vu
u
n
ue
W
T
e
W
W
VDT
ps
or ( )
u
nuzu
e
V
ps
224
2
*2
* −+−
=
020 224
=+−→==
nuzup constns
( ) ( )
2
224
2
2243
23
*
*244
*
*
u
nuzu
e
V
u
nuzuuuzu
e
V
u
p
constn
s ++−
=
−+−−+−
=
∂
∂
=
0=
∂
∂
=constn
s
u
p 2
21
2
uu
uu
MAX <<
+
nz >
Climbing Aircraft Performance
nz
nzzu
nzzu
>




−+=
−−=
22
2
22
1
3
3 22
nzz
uMAX
++
=










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
73
Performance of an Aircraft with Parabolic PolarSOLO
Energy per unit mass E
sp
2u1u
MAXu
2
21 uu + u
MAXn
n
1=n
( )
u
nuzu
e
V
ps
224
2
*
* −+−
=
ps as a function of u
u
V
pe
uzunnuzuu
V
pe ss
*
*2
22
*
*2 242224
−+−=→−+−=
From which u
V
pe
uzun s
*
*2
2 24
−+−=
( )
*
*2
44 3
2
V
pe
uzu
u
n s
constps
−+−=
∂
∂
=
( )
3
0412 2
2
22
z
uzu
u
n
constps
=→=+−=
∂
∂
=
( )
u
nuzu
e
V
ps
224
2
*2
* −+−
=
Climbing Aircraft Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
74
Performance of an Aircraft with Parabolic PolarSOLO
Load Factor n
u
3
z z
z2z
3
z
u
2
n
0=sp
0>sp
0<sp
0<sp
0=sp
0>sp
( )
u
n
∂
∂ 2
( )
2
22
u
n
∂
∂
3
z
u
( ) ( ) 2
2
2
22
,, n
u
n
u
n
∂
∂
∂
∂ as a function of u
( )
3
0412 2
2
22
z
uzu
u
n
constps
=→=+−=
∂
∂
=
( )
*
*2
44 3
2
V
pe
uzu
u
n s
constps
−+−=
∂
∂
=
Integrating once
u
V
pe
uzun s
*
*2
2 24
−+−=
Integrating twice
Climbing Aircraft Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
75
Performance of an Aircraft with Parabolic PolarSOLO
Load Factor n
For ps = 0 we have
zuuzun 202 24
≤≤+−=
Let find the maximum of n as function of u.
0
22
44
24
3
=
+−
+−
=
∂
∂
uzu
uzu
u
n
Therefore the maximum value for n is
achieved for zu =
( ) zn
MAXps
==0
u 0 √z √2z
∂ n/∂u | + + + 0 - - - - | - -
n ↑ Max ↓
z2z
u
n
0=sp
0>sp
0<sp
MAXn
z
MAX
MAXL
L
n
C
C
_
*
n as a function of u
Climbing Aircraft Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
Performance of an Aircraft with Parabolic PolarSOLO
Energy per unit mass E
g
V
hE
2
:
2
+=
Climbing Aircraft Performance
Energy Height versus Mach NumberEnergy Height versus True Airspeed
( )hV
V
M
sound
=:( )
00
:
T
T
V
T
T
MhVTAS sound ==
Return to Table of Content
77
Performance of an Aircraft with Parabolic PolarSOLO
Steady Climb (V, γ = constant)
Climbing Aircraft Performance
0sin
0cos
==−−
==−
td
Vd
g
W
WDT
td
d
V
g
W
WL
γ
γ
γ
Equation of Motion for Steady Climb:
γ
γ
sin
cos
Vh
Vx
=
=


Define the Rate of Climb:
( )
s
Ra
C p
W
PP
W
DTV
Vh =
−
=
−⋅
== γsin
where
Pa = V T - available power
PR = V D - required power
ps - excess power per unit weight
Weight
ThrustExcess
W
DT
=
−
=γsin
C
C
WL
const
γ
γγ
cos
.
=
==
Lift
Drag
Thrust
Weight
78
Performance of an Aircraft with Parabolic PolarSOLO
Climbing Aircraft Performance
LC CSVW 2
2
1
cos ργ =
( )
s
C
D
LD
C p
SV
W
kCSVVT
WW
CkCSVVT
h =












−−=
+−
=
ρ
γ
ρ
ρ
2
1
cos
2
112
1
22
0
3
2
0
3

Let find the velocity V for which the Rate of Climb is maximum, for the Propeller Aircraft:
0
cos2
2
31
2
22
0
2
=





+−==
SV
Wk
CSV
Wtd
pd
td
hd C
D
sC,Prop
ρ
γ
ρ

Steady Climb (V, γ = constant)
For a Propeller Aircraft we assume that Pa=T V= constant.
or **
4
4
0
4
76.0
3
12
3
1
VV
C
k
S
W
V
D
Climb.Prop ===
ρ
s
C
DaPropC p
SV
W
kCSVP
W
h =





−−=
ρ
γ
ρ
22
0
3
,
cos
2
2
11
We can see that the velocity at which the Rate of Climb of Propeller Aircraft is maximum
is the same as the velocity at which the Required Power in Level Flight is maximum.
Lift
Drag
Thrust
Weight
79
Performance of an Aircraft with Parabolic PolarSOLO
Climbing Aircraft Performance
LC CSVW 2
2
1
cos ργ =
( )












−−=
+−
=
SV
W
kCSVVT
WW
CkCSVVT
h C
D
LD
C
ρ
γ
ρ
ρ
2
1
cos
2
112
1
22
0
3
2
0
3

Let find the velocity V for which the Rate of Climb is maximum, for the Jet Aircraft:
0
cos2
2
31
2
22
0
2
=





+−=
SV
Wk
CSVT
Wtd
hd C
D
C
ρ
γ
ρ

Steady Climb (V, γ = constant)
For a Jet Aircraft we assume that T = constant.
Define
0
*
0
0
*
*
*
4
0
2
:2*,*,:
2
:*,
*
:
D
DD
D
L
D
L
D CkW
T
W
eT
zCC
k
C
C
C
C
e
C
k
S
W
V
V
V
u =======
ρ
0cos
2
2
3
2 2
/1
2
0
0
2
2
0
2
2
=+− C
u
D
u
Dz
D
V
C
k
S
W
C
k
S
W
V
T
CkW
γ
ρ
ρ



0cos23 224
=−− Cuzu γ
Czzu γ22
cos3++=
80
Performance of an Aircraft with Parabolic PolarSOLO
Climbing Aircraft Performance
Steady Climb (V, γ = constant)
ps versus the nondimensional velocity u
ps versus the velocity V
0sin ==−−
td
Vd
g
W
WDT γ
1
2
2
2
*2 =






+=
n
u
n
u
e
W
D
Define
0
*
0
0
*
*
*
4
0
2
:2*,*
,:
2
:*,
*
:
D
DD
D
L
D
L
D
CkW
T
W
eT
zCC
k
C
C
C
C
e
C
k
S
W
V
V
V
u
====
===
ρ












+−==
−
= 2
2
*
1
2
2
1
sin
u
uz
eV
p
W
DT s
γ
To find the maximum γ we must have
0
2
2
2
1sin
3*
=





−−=
u
u
eud
d γ
4
0
2
*max
DC
k
S
W
VV
ρ
γ ==
( ) ( )1
*
*2
*2
*
1
1
224
, max
−=
−+−
=
=
=
z
e
V
u
nuzu
e
V
p
u
n
s γ *
,
max
1
sin
max
max
e
z
V
ps −
==
γ
γ
γ
1max
=γu
SOLO
81
Aircraft Flight Performance
Construction of the Specific Excess Power contours ps in the
Altitude-Mach Number map for a Subsonic Aircraft below the
Drag-divergence Mach Number.
These contour are constructed for a fixed load factor W/S and
Thrust factor T/S, if the load or thrust factor change, the ps
contours will shift.
( ) ( )
W
VDT
W
VDT
W
DT
g
g
V
V
g
VV
hEps
−
≈
−
=











−
−
+=+==
α
γ
α
γ
cos
sin
cos
sin:


In Figure (a) is a graph of Specific Excess Power contours ps
versus Mach Number. Each curve is for a specific altitude h.
In Figure (b) each curve is for a given Specific Excess Power ps
in Altitude versus Mach Number coordinates.
The points a, b, c, d, e, f for ps = 0 in Figure (a) are plotted on
the curve for ps = 0 in Figure (b).
Similarly all points ps = 200 ft/sec in Figure (a) on the line AB
are projected on the curve ps = 200 ft/sec in Figure (b).
Specific Excess Power
contours ps for a Subsonic
Aircraft
Specific Excess Power contours ps
SOLO
82
Aircraft Flight Performance
Specific Excess Power contours ps for a Supersonic Aircraft
In the graphs of Specific Excess
Power ps versus Mach Number
Figure (a) for a Supersonic
Aircraft we see a “dent” in h
contour in the Transonic
Region. This is due to the
increase in Drag in this region.2
In Figure (b) the graphs of
Altitude versus Mach Number
we see a “closed” ps = 400 ft/sec
contour due to the increase in
Drag in this Transonic Region.
Specific Excess Power contours ps
( ) ( )
W
VDT
W
VDT
W
DT
g
g
V
V
g
VV
hEps
−
≈
−
=











−
−
+=+==
α
γ
α
γ
cos
sin
cos
sin:


Return to Table of Content
83
Performance of an Aircraft with Parabolic PolarSOLO
Climbing Aircraft Performance
Optimum Climbing Trajectories using Energy State Approximation (ESA)
We defined the Energy per unit mass E (Specific Energy):
g
V
hE
2
:
2
+=
Differentiate this equation:
( ) ( )
W
VDT
W
VDT
W
DT
g
g
V
V
g
VV
h
td
Ed
ps
−
≈
−
=











−
−
+=+==
α
γ
α
γ
cos
sin
cos
sin:


Minimum Time-to-Climb
The time to reach a given Energy Height Ef is computed as follows
E
Ed
td

= ∫=
fE
E
f
E
Ed
t
0 
The minimum time to reach the given Energy Height Ef is obtained by using
at each level.
( )∫=
fE
E
f
E
Ed
t
0
max
max, 
( )maxE
84
Performance of an Aircraft with Parabolic PolarSOLO
Climbing Aircraft Performance
Optimum Climbing Trajectories using Energy State Approximation (ESA)
Minimum Time Climb Profiles for Subsonic Speed
( ) ( )
W
VDT
W
VDT
W
DT
g
g
V
V
g
VV
hEps
−
≈
−
=











−
−
+=+==
α
γ
α
γ
cos
sin
cos
sin:


Stengel, MAE331, Lecture 7, Gliding,
Climbing and Turning Performance
The minimum time to reach the given Energy Height Ef is obtained by using at
each level.
( )maxE
Energy can be converted from potential to kinetic or vice versa along lines of constant
energy in zero time with zero fuel expended. This is physically not possible so the
method gives only an approximation of real paths.
SOLO
85
Aircraft Flight Performance
Stengel, MAE331, Lecture 7, Gliding,
Climbing and Turning Performance
Minimum Time Climb Profiles for Supersonic Speed
( ) ( )
W
VDT
W
VDT
W
DT
g
g
V
V
g
VV
hEps
−
≈
−
=











−
−
+=+==
α
γ
α
γ
cos
sin
cos
sin:


The minimum time to reach the given Energy Height Ef is obtained by using at
each level.
( )maxE
The optimum flight profile for the fastest time to altitude or time to speed involves climbing to
maximal altitude at subsonic speed, then diving in order to get through the transonic speed
range as quickly as possible, and than climbing at supersonic speeds again using .( )maxE
86
SOLO
Climbing Aircraft Performance
Optimum Climbing Trajectories using Energy State Approximation (ESA)
Shaw, “Fighter Combats – Tactics and Maneuvering”
Minimum Time Climb Profiles
Aircraft Flight Performance
The minimum time to reach the given Energy Height Ef is obtained by using at
each level .
( )maxE
87
SOLO
Climbing Aircraft Performance
Optimum Climbing Trajectories using Energy State Approximation (ESA)
A.E. Bryson, Course “Performance Analysis of Flight Vehicles”, AA200, Stanford University, Winter 1977-1978
Aircraft Flight Performance
A.E. Bryson, Jr., “Energy-State Approximation in Performance Optimization of Supersonic Aircraft”, Journal of Aircraft, Vol.6,
No. 5, Nov-Dec 1969, pp. 481-488
Approximate (ESA) Solutions.
Implicit to ESA Approximation
is the possibility of
instantaneous jump between
kinetic to potential energy
(from A to B ).
This non physical situation is
called a “zoom climb” or
“zoom dive”.
A
B
The minimum time to reach the given Energy Height Ef is obtained by using at
each level.
( )maxE
SOLO
Climbing Aircraft Performance
Optimum Climbing Trajectories using Energy State Approximation (ESA)
“Exact” calculated using
Optimization Methods
Computations
Aircraft Flight Performance
Comparison between
“Exact” and Approximate
(ESA) Solutions.
Implicit to ESA
Approximation is the
possibility of instantaneous
jump between kinetic to
potential energy (from
A to B , and from C to D).
This non physical situation
is called a “zoom climb”
or “zoom dive”. We can see
the “exact” solution in
those cases.
A
B
C
D
The minimum time to reach the given Energy Height Ef is obtained by using at
each level.
( )maxE
88
A.E. Bryson, Course “Performance Analysis of Flight Vehicles”, AA200, Stanford University, Winter 1977-1978
A.E. Bryson, Jr., “Energy-State Approximation in Performance Optimization of Supersonic Aircraft”, Journal of Aircraft, Vol.6,
No. 5, Nov-Dec 1969, pp. 481-488
89http://msflights.net/forum/showthread.php?1184-Supersonic-Level-Flight-Envelopes-in-FSX
F-15 Streak Eagle Time to Climb Records, which follow the ideal path to reach set altitudes in a
minimal amount of time. The Streak Eagle could break the sound barrier in a vertical climb, so
the ideal flightpath to 30000m involved a large Immelmann.
https://www.youtube.com/watch?v=HLka4GoUbLo https://www.youtube.com/watch?v=S7YAN9--3MA
F-15 Streak Eagle Record Flights part 2F-15 Streak Eagle Record Flights part 1
SOLO
Climbing Aircraft Performance
Optimum Climbing Trajectories using Energy State Approximation (ESA)
Aircraft Flight Performance
90
How to climb as fast as possible
Takeoff and pull up: You want to build energy (kinetic or potential) as quickly as you
can. Peak acceleration is at mach 0.9, which is the speed that energy is gained the
fastest. You should first accelerate to near that speed. Avoid bleeding off energy in a
high-g pull up. Start a smooth pull up before at mach 0.7-0.8 and accelerate to mach 0.9
during the pull.
http://msflights.net/forum/showthread.php?1184-Supersonic-Level-Flight-Envelopes-in-FSX
SOLO
Climbing Aircraft Performance
Optimum Climbing Trajectories using Energy State Approximation (ESA)
F-15 Streak Eagle Time to Climb Records, which follow the ideal path to reach set altitudes in a
minimal amount of time. The Streak Eagle could break the sound barrier in a vertical climb, so
the ideal flightpath to 30000m involved a large Immelmann.
Aircraft Flight Performance
Climb again: to 36000ft for maximum speed, or higher as to not exceed design limits or
to save fuel for a longer run
Climb: Adjust your climb angle to maintain mach 0.9. In a modern fighter, the climb angle
may be 45-60 degrees. If you need a heading change, during the pull and climb is a good time
to make it.
Level off: between 25000 and 36000ft by rolling inverted. Maximum speed is reached at
36000, but remember the engines produce more thrust at higher KIAS, so slightly denser air
may not hurt acceleration through the sound barrier.
Break the mach barrier: Accelerate to mach 1.25 with minimal wing loading (don't turn, try to
set 0AoA)
Return to Table of Content
91
SOLO
Climbing Aircraft Performance
Optimum Climbing Trajectories using Energy State Approximation (ESA)
Aircraft Flight Performance
Minimum Fuel-to- Climb Trajectories using Energy State Approximation (ESA)
The Rate of Fuel consumed by the Aircraft is given by:



=−=
AircraftJetTc
AircraftPropellerPc
td
Wd
td
fd
T
p
We can write
( )DTV
EdW
E
Ed
td
−
==

The fuel consumed in a flight time , tf for a Jet Aircraft is:
( )∫∫∫ −
===
fff t
T
t
T
t
f Ed
TDV
Wc
E
Ed
Tctd
td
fd
f
000 /1
The minimum fuel consumed in a flight time tf is obtained when using
Maximum Thrust and the Mach Number that minimize the integrand:
( )∫ −
=
ft
T
M
f Ed
TDV
Wc
f
0
max
min,
/1
minarg
for each level of E.
92
SOLO
Climbing Aircraft Performance
Optimum Climbing Trajectories using Energy State Approximation (ESA)
Aircraft Flight Performance
Minimum Fuel-to- Climb Trajectories using Energy State Approximation (ESA)
Assuming W nearly constant, during the climb period, contours of constant
( )
max
max
Tc
DTV
T
−
can be computed, as we see in the Figure
A.E. Bryson, Course “Performance Analysis of Flight Vehicles”, AA200, Stanford University, Winter 1977-1978
A.E. Bryson, Jr., “Energy-State Approximation in Performance Optimization of Supersonic Aircraft”, Journal of Aircraft, Vol.6,
No. 5, Nov-Dec 1969, pp. 481-488
The Minimum Fuel-to- Climb
Trajectory is obtained by choosing
at each state.
( )
max
max
Tc
DTV
T
−
The Minimum Time-to- Climb
Path is also displayed.
Implicit to ESA Approximation is the
possibility of instantaneous jump
between kinetic to potential energy
(from A to B) where the Total Energy
is constant.
A
B
Return to Table of Content
93
SOLO
Climbing Aircraft Performance
Optimum Climbing Trajectories using Energy State Approximation (ESA)
Aircraft Flight Performance
Maximum Range during Glide using Energy State Approximation (ESA)
Equations of motion
A.E. Bryson, Jr., “Energy-State Approximation in Performance Optimization of Supersonic Aircraft”, Journal of Aircraft, Vol.6,
No. 5, Nov-Dec 1969, pp. 481-488
γ
γ
γ
sin
0cos
WDTV
g
W
WL
td
d
V
g
W
−−=
≈−=

( )
W
VDT
Eps
−
== :
g
V
W
DT 
−
−
=γsin
γ
γ
sin
cos
Vh
Vx
=
=








−
−
=
g
V
W
DT
Vh


γγ cos
1
cos 





−
−
===
g
V
W
DT
V
h
x
h
xd
hd 


During Glide we have: T = 0, W = constant, dE≤0, |γ| <<1, therefore 





+−=
g
V
W
D
xd
hd 
( )
γcos
1
VW
DT
xd
Ed −
=
2
2
1
: VhE +=
( ) ( )
( )EL
VED
W
VED
td
Ed
−≈−=
V
td
xd
= ( )
( )
( )ED
EL
ED
W
Ed
xd
−≈−=
( )
( )
( )∫∫∫ −≈−== Ed
ED
EL
Ed
ED
W
xdR
94
SOLO
Climbing Aircraft Performance
Optimum Climbing Trajectories using Energy State Approximation (ESA)
Aircraft Flight Performance
Maximum Range during Glide using Energy State Approximation (ESA)
We found
A.E. Bryson, Jr., “Energy-State Approximation in Performance Optimization of Supersonic Aircraft”, Journal of Aircraft, Vol.6,
No. 5, Nov-Dec 1969, pp. 481-488
( )
( )
( )∫∫ −≈−= Ed
ED
EL
Ed
ED
W
R
Using the first integral we see that to maximize R we must choose the path that
minimizes the drag D (E). The approximate optimal trajectory can be divided in:
1.If the initial conditions are not on the maximum range glide path the Aircraft
shall either “zoom dive” or “zoom climb” at constant E0, A to B path in Figure .
2.The Aircraft will dive on the min D (E)
until it reaches the altitude h = 0 at a
velocity V and Specific Energy E1=V2
/2,
B to C in the Figure.
3.Since h=0 no optimization is possible and
to stay airborne one must keep the drag
such that L = W, by increasing the Angle of
Attack and decreasing velocity until it
reaches Vstall and Es=Vstall
2
/2, C to D in Figure
Since h=0, d E=V dV.
( ) ( ) ( )[ ]∫ ∫∫ =
=
−−−=
1
0 1
0
0
0min
10
max
E
E
E
E
h
pathon
E
E
s
Vd
VD
VW
Ed
ED
W
Ed
ED
W
R
  
Return to Table of Content
95
Performance of an Aircraft with Parabolic PolarSOLO






−
+
=
=
γσ
α
γσ
coscos
sin
cossin
V
g
Vm
LT
q
V
g
r
W
W
n
W
L
W
LT
n =≈
+
=
αsin
:'
Therefore
( )





−=
=
γσ
γσ
coscos'
cossin
n
V
g
q
V
g
r
W
W
γσγσγσω 2222222
coscoscoscos'2'cossin +−+=+= nn
V
g
qr WW
or
γγσω 22
coscoscos'2' +−= nn
V
g
γγσω 22
2
coscoscos'2'
1
+−
==
nng
VV
R
Aircraft Turn Performance
96
Performance of an Aircraft with Parabolic PolarSOLO
( ) ( )
( )
γ
σ
σ
γ
α
χ
γσγσ
α
γ
cos
sin
sin
cos
sin
coscos'coscos
sin
V
gLT
n
V
g
V
g
Vm
LT
=
+
=
−=−
+
=


2. Horizontal Plan Trajectory ( )0,0 == γγ 
( )
1'
1
1'
'
1
1'sin'
cos
1
'01cos'
2
2
2
2
−
=
−=





−==
=→=−=
ng
V
R
n
V
g
n
n
V
g
n
V
g
nn
V
g
σχ
σ
σγ


Aircraft Turn Performance
1. Vertical Plan Trajectory (σ = 0)
( )
γ
γγ
χ
cos'
1
cos'
0
2
−
=
−=
=
ng
V
R
n
V
g


97
98
Vertical Plan Trajectory (σ = 0)
SOLO
Prof. Earll Murman, “Introduction to Aircraft Performance and Static Stability”, September 18, 2003
99
R
V
=:χ1'2
−= n
V
g
χ
Contours of Constant n and Contours of Constant Turn Radius
in Turn-Rate in Horizontal Plan versus Mach coordinates
Horizontal Plan TrajectorySOLO
100Maneuverability Diagram
R
V
=:χ
1'2
−= n
V
g
χ
Horizontal Plan Trajectory
101
F-5E Turn Performance
Horizontal Plan Trajectory
102
Performance of an Aircraft with Parabolic PolarSOLO
2. Horizontal Plan Trajectory ( )0,0 == γγ 
We can see that for n > 1
We found that
2
2
*
*
u
C
C
n
u
C
nC
L
LL
L =→=
n
1n
2n
MAXn
u u
LC
MAXLC _
1
_
n
C
C
MAXL
L
MAX
MAXL
L
corner n
C
C
u
_
*
=
*2 L
MAX
L C
u
n
C =
MAX
MAXL
L
corner n
C
C
u
_
*
= MAX
L
L
n
C
C
1
*
MAXLC _
2LC
1LC
2
*
1
u
C
C
n
L
L
=
MAXn
n, CL as a function of u
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
1
1
1'
1
11'
2
2
2
2
22
−
≈
−
=
−≈−=
ng
V
ng
V
R
n
V
g
n
V
g
χ Horizontal Turn Rate
Horizontal Turn Radius
103
Performance of an Aircraft with Parabolic PolarSOLO
MAX
MAX
L
MAXL
n
n
C
C
V
g 1
**
2
_ −
MAX
MAXL
L
corner n
C
C
V
g
u
_
*
*
=
MAXL
L
C
C
V
g
u
_
1
*
*
=
MAXn
2n
1n
MAXLC _
2LC
1LC
u
χ
MAXu
Horizontal Turn Rate as function of u, with n and CL as parametersχ
We defined 2
*
&
*
: u
C
C
n
V
V
u
L
L
==
We found 2
2
2
22 1
**
1
*
1
u
u
C
C
V
g
n
Vu
g
n
V
g
L
L
−





=−=−=χ
This is defined for 1:
**
1
__
<=≥≥= u
C
C
un
C
C
u
MAXL
L
MAX
MAXL
L
corner
2. Horizontal Plan Trajectory ( )0,0 == γγ 
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
104
Performance of an Aircraft with Parabolic PolarSOLO
From
2
2
2
22 1
**
1
*
1
u
u
C
C
V
g
n
Vu
g
n
V
g
L
L
−





=−=−=χ
4
2
2
2
22
1
*
1*
1
*
:
uC
Cg
V
n
u
g
VV
R
L
L
−





=
−
==
χ
Therefore
cornerMAX
MAXL
L
MAXL
L
L
MAXL
C
un
C
C
u
C
C
u
uC
Cg
V
R
MAXL
=≤≤=
−





=
__
1
4
2
_
2
**
1
*
1*
_
cornerMAX
MAXL
L
MAX
n
un
C
C
u
n
u
g
V
R
MAX
=≥
−
=
_
2
22
*
1
*
MAX
L
L
L
L
L
L
C
n
C
C
u
C
C
u
uC
Cg
V
R
L
**
1
*
1*
1
4
2
2
≤≤=
−





=
n
C
C
u
n
u
g
V
R
MAXL
L
n
_
2
22
*
1
*
≥
−
=
2. Horizontal Plan Trajectory ( )0,0 == γγ 
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
105
Performance of an Aircraft with Parabolic PolarSOLO
R (Radius of Turn) a function of u, with n and CL as parameters
1
**
2
_
2
−MAX
MAX
MAXL
L
n
n
C
C
g
V
MAX
MAXL
L
corner n
C
C
V
g
u
_
*
*
=
MAXL
L
C
C
V
g
u
_
1
*
*
=
MAXn
2n
1nMAXLC _
2LC 1LC
u
R
4
2
2
2
22
1
*
1*
1
*
:
uC
Cg
V
n
u
g
VV
R
L
L
−





=
−
==
χ
2. Horizontal Plan Trajectory ( )0,0 == γγ 
Return to Table of Content
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
106
Performance of an Aircraft with Parabolic PolarSOLO
Horizontal Turn Rate as Function of ps, n
( )
u
nuzu
e
V
ps
224
2
*2
* −+−
=
up
V
e
uzun s
*
*2
2 242
−+−=
2
24
2
2 1
*
*2
2
*
1
* u
up
V
e
uzu
V
g
u
n
V
g s −−+−
=
−
=χ
2
24
4
2423
1
*
*2
2
2
1
*
*2
22
*
*2
44
*
u
up
V
e
uzu
u
up
V
e
uzuuup
V
e
uzu
V
g
u
s
ss
−−+−






−−+−−





−+−
=
∂
∂ χ
Therefore






−−+−
++−
=
∂
∂
1
*
*2
2
1
*
*
* 244
4
up
V
e
uzuu
up
V
e
u
V
g
u
s
s
χ
For ps = 0
2
22
12
24
0
11
12
*
uzzuzzu
u
uzu
V
g
sp
=−+<<−−=
−+−
==
χ
( ) 2
22
1
244
4
0
11
12
1
*
uzzuzzu
uzuu
u
V
g
u
sp
=−+<<−−=
−+−
+−
=
∂
∂
=
χ
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
107
Performance of an Aircraft with Parabolic PolarSOLO
Horizontal Turn Rate as Function of ps, n
For ps = 0
2
22
12
24
0
11
12
*
uzzuzzu
u
uzu
V
g
sp
=−+<<−−=
−+−
==
χ
( ) 2
22
1
244
4
0
11
12
1
*
uzzuzzu
uzuu
u
V
g
u
sp
=−+<<−−=
−+−
+−
=
∂
∂
=
χ
Let find the maximum of as a function of uχ
( )12
1
* 244
4
0 −+−
+−
=
∂
∂
= uzuu
u
V
g
u
sp
χ
( ) ( )12
*
1 00
−=== ==
z
V
g
u
ss ppMAX χχ 
u 0 u1 1 (u1+u2)/2 u2
∞ + + 0 - - - - - - -∞
↑ Max ↓
u∂
∂ χ
χ
From
2
24
1
*
*2
2
* u
up
V
e
uzu
V
g s −−+−
=χ 





−−+−
++−
=
∂
∂
1
*
*2
2
1
*
*
* 244
4
up
V
e
uzuu
up
V
e
u
V
g
u
s
sχ
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
108
Performance of an Aircraft with Parabolic PolarSOLO
Horizontal Turn Rate as Function of ps, n
u
u
0<sp
0<sp
0=sp
0=sp 0>sp
0>sp
χ
u∂
∂ χ
( )12
*
−z
V
g
1=u1u
2u
as a function of u with ps as
parameter
u∂
∂ χ
χ

,






−−+−
++−
=
∂
∂
1
*
*2
2
1
*
*
* 244
4
up
V
e
uzuu
up
V
e
u
V
g
u
s
sχ
2
24
1
*
*2
2
* u
up
V
e
uzu
V
g s −−+−
=χ
Because ,we have0
*
*
>u
V
e
000 >=<
>>
sss ppp
χχχ 
0
1
0
1
0
1
0
>
=
=
=
<
= ∂
∂
<=
∂
∂
<
∂
∂
sss p
u
p
u
p
u uuu
χχχ 
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
109
Performance of an Aircraft with Parabolic PolarSOLO
Horizontal Turn Rate as Function of ps, n
a function of u, with ps
as parameter
χ
2
24
1
*
*2
2
* u
up
V
e
uzu
V
g s −−+−
=χ
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
Sustained
Turn
Instantaneous
Turn
110
Performance of an Aircraft with Parabolic PolarSOLO
Horizontal Turn Rate as Function of ps, n
2
24
1
*
*2
2
* u
up
V
e
uzu
V
g s −−+−
=χ
( ) ( )ss
s
puupu
up
V
e
uzu
u
g
VV
R 21
24
42
1
*
*2
2
*
<<
−−+−
==
χ
3
242
23
2
24
4
2
24
34243
2
1
*
*2
22
2
*
*3
22
*
1
*
*2
2
2
1
*
*2
2
*
*2
441
*
*2
24
*






−−+−






−−
=
−−+−






−−+−






−+−−





−−+−
=
∂
∂
up
V
e
uzuu
up
V
e
uzu
g
V
up
V
e
uzu
u
up
V
e
uzu
p
V
e
uzuuup
V
e
uzuu
g
V
u
R
s
s
s
s
ss
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
111
Performance of an Aircraft with Parabolic PolarSOLO
Horizontal Turn Rate as Function of ps, n
3
24
2
2
1
*
*2
2
2
*
*3
2
*






−−+−






−−
=
∂
∂
up
V
e
uzu
up
V
e
uzu
g
V
u
R
s
s
or
We have











>
+





+
=
<
+





−
=
→=
∂
∂
0
4
16
*
*
9
*
*3
0
4
16
*
*
9
*
*3
0
2
2
2
1
z
zp
V
e
up
V
e
u
z
zp
V
e
up
V
e
u
u
R
ss
R
ss
R
u 0 u1 uR2 u2
∞ - - - 0 + + ∞
↓ min ↑
u
R
∂
∂
R
2
22
124
42
0
11
12
*
uzzuzzu
uzu
u
g
V
R
sp
=−+<<−−=
−+−
==
( )
( )
2
22
1
324
22
0
11
12
1*2
uzzuzzu
uzu
uzu
g
V
u
R
sp
=−+<<−−=
−+−
−
=
∂
∂
=
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
112
Performance of an Aircraft with Parabolic PolarSOLO
Horizontal Turn Rate as Function of ps, n
u
R
0>sp
0=sp
0<sp
MAXL
L
C
C
_
*
1
**
2
_ −MAX
MAX
MAXL
L
n
n
C
C
g
V
1
1*
2
−zg
V
4
2
_
1*
1*
uC
C
g
V
MAXL
L
−








1
*
2
22
−MAXn
u
g
V
MAX
MAXL
L
n
C
C
_
*
LIMIT
C MAXL_
LIMIT
nMAX
z
1
12
−− zz 12
−+ zz
1
*
*2
2
*
24
42
−−+−
=
up
V
e
uzu
u
g
V
R
s
Minimum Radius of Turn R is obtained for zu /1=
1
1*
2
2
0
−
==
zg
V
R
sp
R (Radius of Turn) a function
of u, with ps as parameter
( ) ( )ss
s
puupu
up
V
e
uzu
u
g
VV
R
21
24
42
1
*
*2
2
*
<<
−−+−
==
χ
Return to Table of Content
Because ,we have0
*
*
>u
V
e
000 >=<
<<
sss ppp
RRR 000 minminmin >=<
<<
sss pRpRpR uuu
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
113
Performance of an Aircraft with Parabolic PolarSOLO
Horizontal Turn Rate as Function of nV,
( )
W
VDT
g
VV
hEps
−
≈+==

:
For an horizontal turn 0=h
V
g
Vu
g
VV
ps

 *
==
We found
2
24
1
*
*2
2
* u
up
V
e
uzu
V
g s −−+−
=χ
from which
2
24
1*2
* u
ue
g
V
zu
V
g
−





−+−
=

χ
defined for
2
22
1 :1**1**: ue
g
V
ze
g
V
zue
g
V
ze
g
V
zu =−





−+





−≤≤−





−−





−=

Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
114
Performance of an Aircraft with Parabolic PolarSOLO
Horizontal Turn Rate as Function of nV,
Let compute
2
24
4
2423
1*2
2
1*22*44
*
u
ue
g
V
zu
u
ue
g
V
zuuuue
g
V
zu
V
g
u
−





−+−






−





−+−−











−+−
=
∂
∂


χ






−





−+−
+−
=
∂
∂
1*2
1
*
244
4
ue
g
V
zuu
u
V
g
u 
χ
or
u 0 u1 1 (u1+u2)/2 u2
∞ + + 0 - - - - - - -∞
↑ Max ↓
u∂
∂ χ
χ






−−= 1*2
*
e
g
V
z
V
g
MAX

χ
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
115
Performance of an Aircraft with Parabolic PolarSOLO
Horizontal Turn Rate as Function of nV,
u
0<V
0=V
0>V
χ
( )12
*
−z
V
g
1=u1u
2u
2
24
1*2
* u
ue
g
V
zu
V
g
−





−+−
=

χ
1
*
2
−MAXn
uV
g
2
2
2
_ 1
** u
u
C
C
V
g
L
MAXL
−





MAXL
L
C
C
_
*
MAX
MAXL
L
n
C
C
_
*
LIMIT
nMAXLIMIT
C MAXL _
MAX
MAX
L
MAXL
n
n
C
C
V
g 1
**
2
_ −
as function of u
and as parameter
χ
V
Return to Table of Content
Aircraft Turn Performance










=
=
=
2
0
*
2
1
:*
*
:
2
:*
Vq
V
V
u
CS
kW
V
D
ρ
ρ
116http://forum.keypublishing.com/showthread.php?69698-Canards-and-the-4-Gen-aircraft/page11
Example of Horizontal Turn, versus Mach, Performance of an Aircraft
SOLO
Aircraft Flight Performance
117
Mirage 2000 at 15000ft.
http://forums.eagle.ru/showthread.php?t=98497
Max sustained rate
(at around 6.5G on
the 0 Ps line)
occurring at around
0.9M/450KCAS
looking at around
12.5 deg sec
9G Vc (Max instant.
Rate) is around
0.65M/320KCAS
looking at 23.5 deg
sec
SOLO
Aircraft Flight Performance
118http://n631s.blogspot.co.il/2011/03/book-review-boyd-fighter-pilot-who.html
Example of Horizontal Turn, versus Mach, Performance of MiG-21
SOLO Aircraft Flight Performance
SOLO
119
Aircraft Flight Performance
Comparison of Sustained ( ) Turn Performance of three Fightry Aircrafts
F-16, F-4 and MiG-21 at Altitude h = 11 km = 36000 ft
0=V
120
SOLO
Aircraft Flight Performance
121
The black lines are the F-4D, the dark orange
lines are the heavy F-4E, and the blue lines are
the lightweight F-4E (same weight as F-4D). Up
to low transonic mach numbers and up to
medium altitudes, the F-4E is about 7% better
than the F-4D (15% better with the same weight).
At higher mach numbers, the F-4 doesn't have to
pull as much AoA to get the same lift, so the slats
actually cause a drag penalty that allows the F-
4D to perform better. For reference, the F-14 is
known to turn about 20% better than the
unslatted F-4J. So, if the slats made the F-4S
turn about 15% better, sustained turn rates would
almost be pretty close between the F-14 and F-
4S. The F-4E, being heavier, would still be
significantly under the F-14. However, with
numbers this close, pilot quality is everything
rather than precise performance figures.
http://combatace.com/topic/71161-beating-a-dead-horse-us-fighter-turn-performance/
F-4
SOLO
Aircraft Flight Performance
122http://www.worldaffairsboard.com/military-aviation/62863-comparing-fighter-performance-same-
generations-important-factor-war-2.html
F-15
F-4
SOLO
Aircraft Flight Performance
123
http://www.airliners.net/aviation-forums/military/print.main?id=153429
SOLO
Aircraft Flight Performance
Return to Table of Content
124
Corner Speed
Maximum
Positive
Capability
(CL) max
Maximum
Negative
Capability
(CL) min
LoadFactor-n
Structural
Limit
Structural
Limit
Limit
Airspeed
Area of
Structural
Damage of
Failure
Vmin V
n
Operational
Load Limit
Operational
Load Limit
Structural
Load Limit
Structural
Load Limit
Typical Maneuvering Envelope
V – n Diagram
Maneuvering Envelope:
Limits on Normal Load Factor and
Allowable Equivalent Airspeed
-Structural Factor
-Maximum and Minimum
allowable Lift Coefficient
-Maximum and Minimum
Airspeeds
-Corner Velocity: Intersection of
Maximum Lift Coefficient and
Maximum Load Factor
SOLO
Aircraft Flight Performance
125
Typical Maneuvering Envelope
V – n Diagram
Performance of an Aircraft with Parabolic PolarSOLO
126R.W. Pratt, Ed., “Flight Control Systems, Practical issues in design and implementation”,
AIAA Publication, 2000
SOLO
Aircraft Flight Performance
Return to Table of Content
127
Air-to-Air Combat
Destroy Enemy Aircraft to achieve Air Supremacy in order to prevent the enemy
to perform their missions and enable to achieve tactical goals.
SOLO
See S. Hermelin, “Air Combat”, Presentation, http://www.solohermelin.com
128
http://forum.warthunder.com/index.php?/topic/110779-taktik-ve-manevralar-hakk%C4%B1ndaki-e%
Air-to-Air Combat
Before the introduction of all-aspect Air-to-Air Missiles destroying an Enemy Aircraft was
effective only from the tail zone of the Enemy Aircraft, so the pilots had to maneuver to reach
this position, for the minimum time necessary to activate the guns or launch a Missile.
Return to Table of Content
SOLO
129
Energy–Maneuverability Theory
Aircraft Flight Performance
Energy–maneuverability theory is a model of aircraft performance. It was
promulgated by Col. John Boyd, and is useful in describing an aircraft's
performance as the total of kinetic and potential energies or aircraft specific
energy. It relates the thrust, weight, drag, wing area, and other flight
characteristics of an aircraft into a quantitative model. This allows combat
capabilities of various aircraft or prospective design trade-offs to be predicted and
compared.
Colonel John Richard Boyd
(1927 –1997)
Boyd, a skilled U.S. jet fighter pilot in the Korean War, began
developing the theory in the early 1960s. He teamed with
mathematician Thomas Christie at Eglin Air Force Base to
use the base's high-speed computer to compare the
performance envelopes of U.S. and Soviet aircraft from the
Korean and Vietnam Wars. They completed a two-volume
report on their studies in 1964. Energy Maneuverability came
to be accepted within the U.S. Air Force and brought about
improvements in the requirements for the F-15 Eagle and
later the F-16 Fighting Falcon fighters
130
131
Turning Capability Comparison of F4E and MiG21 at Sea Level
http://forum.keypublishing.com/showthread.php?96201-fighter-maneuverability-
comparison
F-4E
MiG-21
Aircraft Flight Performance
132
http://www.aviationforum.org/military-aviation/16335-fighter-maneuverability-comparison.html
F4 _Phantom versus MIG 21
MiG-21
SOLO
Aircraft Flight Performance
133
Aircraft Flight Performance
134
135
SOLO
136
Aircraft Flight Performance
In combat, a pilot is faced with a variety of limiting factors. Some limitations are
constant, such as gravity, drag, and thrust-to-weight ratio. Other limitations vary
with speed and altitude, such as turn radius, turn rate, and the specific energy of
the aircraft. The fighter pilot uses Basic Fighter Maneuvers (BFM) to turn these
limitations into tactical advantages. A faster, heavier aircraft may not be able to
evade a more maneuverable aircraft in a turning battle, but can often choose to
break off the fight and escape by diving or using its thrust to provide a speed
advantage. A lighter, more maneuverable aircraft can not usually choose to
escape, but must use its smaller turning radius at higher speeds to evade the
attacker's guns, and to try to circle around behind the attacker.[13]
BFM are a constant series of trade-offs between these limitations to conserve
the specific energy state of the aircraft. Even if there is no great difference
between the energy states of combating aircraft, there will be as soon as the
attacker accelerates to catch up with the defender. Instead of applying thrust, a
pilot may use gravity to provide a sudden increase in kinetic energy (speed), by
diving, at a cost in the potential energy that was stored in the form of altitude.
Similarly, by climbing the pilot can use gravity to provide a decrease in speed,
conserving the aircraft's kinetic energy by changing it into altitude. This can help
an attacker to prevent an overshoot, while keeping the energy available in case
one does occur
Energy Management
SOLO
137
Aircraft Flight Performance
Energy Management
Colonel J. R. Boyd:
In an air-to-air battle offensive maneuvering advantage will belong to the pilot
who can enter an engagement at a higher energy level and maintain more energy than his
opponent while locked into a maneuver and counter-maneuver duel. Maneuvering
advantage will also belong to the pilot who enters an air-to-air battle at a lower energy
level, but can gain more energy than his opponent during the course of the battle, From a
performance standpoint, such an advantage is clear because the pilot with the most energy
has a better opportunity to engage or disengage at his own choosing. On the other hand,
energy-loss maneuvers can be employed defensively to nullify an attack or to gain a
temporary offensive maneuvering position.
http://www.ausairpower.net/JRB/fast_transients.pdf
“New Conception for Air-to-Air Combat”, J. Boyd, 4 Aug. 1976
138
http://www.alr-aerospace.ch/Performance_Mission_Analysis.php
F-16
SOLO
Aircraft Flight Performance
139Comparative Ps Diagram for Aircraft A and Aircraft B. Two Multi-Role Jet Fighters
SOLO
Aircraft Flight Performance
140
http://www.simhq.com/_air/air_065a.html
http://en.wikipedia.org/wiki/Lavochkin_La-5
Comparison of Turn Performance of two WWII Fighter Aircraft:
Russian Lavockin La5 vs German Messershmitt Bf 109
http://en.wikipedia.org/wiki/Messerschmitt_Bf_109
SOLO Aircraft Flight Performance
141
Comparison of Turn Performance of two WWII Fighter Aircraft:
Russian Lavockin La5 vs German Messershmitt Bf 109
http://en.wikipedia.org/wiki/Lavochkin_La-5http://en.wikipedia.org/wiki/Messerschmitt_Bf_109
http://www.simhq.com/_air/air_065a.html
SOLO
Aircraft Flight Performance
142
F-86F Sabre and MiG-15 performance comparison
North American
F-86 Sabre
MiG-15
SOLO
Aircraft Flight Performance
143
Falcon F-16C versus Fulcrum MIG 29,
left is w/o afterburner, right is with it, fuel reserves 50%
http://forum.keypublishing.com/showthread.php?47529-MiG-29-kontra-F-16-(aerodynamics-)
FulcrumMiG-29F-16
SOLO
Aircraft Flight Performance
144
Comparison of Turn Performance of two Modern Fighter Aircraft:
Russian MiG-29 vs USA F-16
FulcrumMiG-29
F-16
http://www.simhq.com/_air/air_012a.html
http://www.evac-fr.net/forums/lofiversion/index.php?t984.html
145
Comparison of Turn Performance of two Modern Fighter Aircraft:
Russian MiG-29 vs USA F-16
FulcrumMiG-29
F-16
http://www.simhq.com/_air/air_012a.html
http://www.evac-fr.net/forums/lofiversion/index.php?t984.html
146
http://www.simhq.com/_air/air_012a.html
Comparison of Turn Performance of two Modern Fighter Aircraft:
Russian MiG-29 vs USA F-16
Fulcrum MiG-29
F-16
http://www.evac-fr.net/forums/lofiversion/index.php?t984.html
147
http://www.simhq.com/_air3/air_117e.html
While the turn radius of both aircraft is very similar, the MiG-29
has gained a significant angular advantage.
Comparison of Turn Performance of two Modern Fighter Aircraft:
Russian MiG-29 vs USA F-16
MiG-29
F-16
SOLO Aircraft Flight Performance
148
http://www.evac-fr.net/forums/lofiversion/index.php?t984.html
Comparison of Turn Performance of two Modern Fighter Aircraft:
Russian MiG-29 vs USA F-16
With afterburner, fuel reserves 50%
Without afterburner, fuel reserves 50%
MiG-29
F-16
SOLO Aircraft Flight Performance
149
http://forums.eagle.ru/showthread.php?t=30263
SOLO Aircraft Flight Performance
150
An assessment is made of the applicability of Energy Maneuverability techniques (EM)
to flight path optimization. A series of minimum time and fuel maneuvers using the F-4C
aircraft were established to progressively violate the assumptions inherent in the EM program
and comparisons were made with the Air Force Flight Dynamics Laboratory's (AFFDL)
Three-Degree-of-Freedom Trajectory Optimization Program and a point mass option of the
Six-Degree-of-Freedom flight path program. It was found the EM results were always optimistic
in the value of the payoff functions with the optimism increasing as the percentage
of the maneuver involving constant energy transitions Increases. For the minimum time
paths the resulting optimism was less than 27%f1o r the maneuvers where the constant energy
percentage was less than 35.',", followed by a rather steeply rising curve approaching in the
limit 100% error for paths which are comprised entirely of constant energy transitions. Two
new extensions are developed in the report; the first is a varying throttle technique for use
on minimum fuel paths and the second a turning analysis that can be applied in conjunction
with a Rutowski path. Both extensions were applied to F-4C maneuvers in conjunction with
'Rutowski’s paths generated from the Air Force Armament Laboratory's Energy Maneuverability
program. The study findings are that energy methods offer a tool especially useful in
the early stages of preliminary design and functional performance studies where rapid
results with reasonable accuracy are adequate. If the analyst uses good judgment in its applications
to maneuvers the results provide a good qualitative insight for comparative purposes.
The paths should not, however, be used as a source of maneuver design or flight
schedule without verification especially on relatively dynamic maneuvers where the accuracy
and optimality of the method decreases.
David T. Johnson, “Evaluation of Energy Maneuverability Procedures
in Aircraft Flight Path Optimization and Performance Estimation”,
November 1972, AFFDL-TR-72-53
SOLO Aircraft Flight Performance
151
Lockheed F-104 Starfighter
SOLO Aircraft Flight Performance
152
Typical Ps Plot for Lockheed F-104 Starfighter
Lockheed F-104 Starfighter
SOLO Aircraft Flight Performance
153
SOLO
Aircraft Flight Performance
F-104 Flight Envelope
Lockheed F-104 Starfighter
154F-104A flight envelope
Lockheed F-104 Starfighter
SOLO Aircraft Flight Performance
Return to Table of Content
155
http://defence.pk/threads/design-characteristics-of-canard-non-canard-fighters.178592/
SOLO
Aircraft Flight Performance
Aircraft Combat Performance Comparison
156
http://defence.pk/threads/design-characteristics-of-canard-non-canard-fighters.178592/
SOLO
Aircraft Flight Performance
157
http://img138.imageshack.us/img138/4146/image4u.jpg
SOLO
Aircraft Flight Performance
158
https://s3-eu-west-1.amazonaws.com/rbi-blogs/wp-content/uploads/mt/flightglobalweb/blogs/the-dewline/assets_c/2011/05/chart%20
Aircraft Combat Performance Comparison
SOLO
Aircraft Flight Performance
Return to Table of Content
159
Supermaneuverability is defined as the ability of an aircraft to perform high
alpha maneuvers that are impossible for most aircraft is evidence of the
aircraft's supermaneuverability. Such maneuvers include Pugachev's Cobra
and the Herbst maneuver (also known as the "J-turn").
Some aircraft are capable of performing Pugachev's Cobra without the aid
of features that normally provide post-stall maneuvering such as thrust
vectoring. Advanced fourth generation fighters such as the Su-27, MiG-29
along with their variants have been documented as capable of performing
this maneuver using normal, non-thrust vectoring engines. The ability of
these aircraft to perform this maneuver is based in inherent instability like
that of the F-16; the MiG-29 and Su-27 families of jets are designed for
desirable post-stall behavior. Thus, when performing a maneuver like
Pugachev's Cobra the aircraft will stall as the nose pitches up and the
airflow over the wing becomes separated, but naturally nose down even from
a partially inverted position, allowing the pilot to recover complete control.
http://en.wikipedia.org/wiki/Supermaneuverability
Supermaneuverability
SOLO
Aircraft Flight Performance
160
SOLO
Aircraft Flight Performance
161
Sukhoi Su-30MKI
SOLO
Aircraft Flight Performance
http://vayu-sena.tripod.com/interview-simonov1.html
162
SOLO
Aircraft Flight Performance
The Herbst maneuver or "J-Turn" named after Wolfgang Herbst is the only thrust
vector post stall maneuver that can be used in actual combat but very few air frames
can sustain the stress of this violent maneuver.
Herbst Maneuver
http://en.wikipedia.org/wiki/Herbst_maneuver
Return to Table of Content
163
Constraint Analysis
SOLO Aircraft Flight Performance
The Performance Requirements can be translated
into functional relationship between the Thrust-to-
Weight or Thrust Loading at Sea Level Takeoff
(TSL/WTO) and the Wing Loading at Takeoff (WTO/S).
The keys to the development are
•Reasonable assumption hor Aircraft Lift-to-Drag
Polar.
•The low sensibility of Engine Thrust with Flight
Altitude and Mach Number.
The minimum of TSL/WTO as functions of WTO/S are required for:
•Takeoff from a Runway of a specified length.
•Flight at a given Altitude and Required Speed.
•Climb at a Required Speed.
•Turn at a given Altitude, Speed and a required Rate.
•Acceleration capability at constant Altitude.
•Landing without reverse Thrust on a Runway of a given length.
164
Energy per unit mass E
Let define Energy per unit mass E:
g
V
hE
2
:
2
+=
Let differentiate this equation:
( ) ( )
W
VDT
W
VDT
W
DT
g
g
V
V
g
VV
hEps
−
≈
−
=











−
−
+=+==
α
γ
α
γ
cos
sin
cos
sin:


define
10 ≤<= ββ TOWW WTO – Take-off Weight
( ) ( ) ( ) SLThThhT αα === 0 TSL – Sea Level Thrust
V
p
W
D
W
T s
+=
Load Factor
W
CSq
W
L
n L
==:
SOLO Aircraft Flight Performance
TOL W
Sq
n
W
Sq
n
C β==






+=
V
p
W
D
W
T s
TO
SL
α
β
Constraint Analysis
165
SOLO Aircraft Flight Performance
General Mission Description of a Typical Fighter Aircraft
10: ≤<= ββ
TOW
W
WTO – Take-off Weight
W – Aircraft Weight during Flight
Constraint Analysis
166
Assume a General Lift-to-Drag Polar Relationship
Total DragRD CSqCSqRD +=+
D, CD - Clean Aircraft Drag and Drag Coefficient
R, CR – Additional Aircraft Drag and Additional Drag Coefficient caused by
External Stores, Bracking Parachute, Flaps, External Hardware
02
2
102
2
1 D
TOTO
DLLD C
S
W
q
n
K
S
W
q
n
KCCKCKC +





+





=++=
ββ
TOL W
Sq
n
W
Sq
n
C β==
( ) 





++=
V
p
CC
W
Sq
W
T s
RD
TOTO
SL
βα
β








+








++





+





=
V
p
CC
S
W
q
n
K
S
W
q
n
K
W
Sq
W
T s
DRD
TOTO
TOTO
SL
02
2
1
ββ
βα
β
SOLO Aircraft Flight Performance
Constraint Analysis
167
( )WLn
td
Vd
td
hd
==== ,1,0,0
Case 1: Constant Altitude/Speed Cruise (ps = 0)
Given:


















+
++





=
S
W
q
CC
K
S
W
q
K
W
T
TO
DRDTO
TO
SL
β
β
α
β 0
21
We obtain:
We can see that TSL/WTO → ∞ for WTO/S → 0 and WTO/S→∞, therefore a
minimum exist. By differentiating TSL/WTO with respect to WTO/S and
setting the result equal to zero, we obtain:
1
0
/min K
CCq
S
W DRD
WT
TO +
=





β
( )[ ]210
min
2 KKCC
W
T
DRD
TO
SL
++=





α
β
Lift
DragThrust
Weight
SOLO Aircraft Flight Performance
Constraint Analysis
168M. Corcoran, T. Matthewson, N. W. Lee, S. H. Wong, “Thrust Vectoring”
Case 1: Constant Altitude/Speed Cruise (ps = 0)
SOLO Aircraft Flight Performance
Constraint Analysis
169
( )WLn
td
hd
≈≈= ,1,0
Case 2: Constant Speed Climb (ps = dh/dt)
Given:
We can see that TSL/WTO → ∞ for WTO/S → 0 and WTO/S→∞, therefore a
minimum exist. By differentiating TSL/WTO with respect to WTO/S and
setting the result equal to zero, we obtain:
1
0
/min K
CCq
S
W DRD
WT
TO +
=





β
( ) 





+++=





td
hd
V
KKCC
W
T
DRD
TO
SL 1
2 210
min
α
β
We obtain:












+






+
++





=
td
hd
V
S
W
q
CC
K
S
W
q
K
W
T
TO
DRDTO
TO
SL 10
21
β
β
α
β
SOLO Aircraft Flight Performance
170
,1,0,0
,,
>== n
td
hd
td
Vd
givenhVgivenhV
Case 3: Constant Altitude/Speed Turn (ps = 0)
Given:
We can see that TSL/WTO → ∞ for WTO/S → 0 and WTO/S→∞, therefore a
minimum exist. By differentiating TSL/WTO with respect to WTO/S and
setting the result equal to zero, we obtain:
1
0
/min K
CC
n
q
S
W DRD
WT
TO +
=





β
( )[ ]210
min
2 KKCC
n
W
T
DRD
TO
SL
++=





α
β
We obtain:












+






+
++





=
td
hd
V
S
W
q
CC
nK
S
W
q
nK
W
T
TO
DRDTO
TO
SL 10
2
2
1
β
β
α
β
2
0
2
2
0
11 





+=




 Ω
+=
cRg
V
g
V
n
SOLO Aircraft Flight Performance
Constraint Analysis
171
( )WLn
td
hd
givenh
=== ,1,0
Case 4: Horizontal Acceleration (ps = (V/g0) (dV/dt) )
Given:
We obtain:












+






+
++





=
td
Vd
g
S
W
q
CC
K
S
W
q
K
W
T
TO
DRDTO
TO
SL
0
0
21
1
β
β
α
β
SOLO Aircraft Flight Performance
Lift
DragThrust
Weight
This can be rearranged to give:


















+
++





=
S
W
q
CC
K
S
W
q
K
W
T
td
Vd
g TO
DRDTO
TO
SL
β
β
β
α 0
21
0
1
Constraint Analysis
172
( )WLn
td
hd
givenh
=== ,1,0
Case 4: Horizontal Acceleration (ps = (V/g0) (dV/dt) ) (continue – 1)
Given:
SOLO Aircraft Flight Performance
Lift
DragThrust
Weight
We obtain:


















+
++





=
S
W
q
CC
K
S
W
q
K
W
T
td
Vd
g TO
DRDTO
TO
SL
β
β
β
α 0
21
0
1
This equation can be integrated from initial velocity V0 to final velocity Vf,
from initial t0 to final tf times.
( )∫=−
fV
V
s
f
Vp
VdV
g
tt
0
0
0
1
where
































+
++





−=
S
W
q
CC
K
S
W
q
K
W
T
Vp
TO
DRDTO
TO
SL
s
β
β
β
α 0
21
The solutions of TSL/WTO for different WTO/S are obtained iteratively.
Constraint Analysis
173http://elpdefensenews.blogspot.co.il/2013_04_01_archive.html
Constraint Analysis
SOLO Aircraft Flight Performance
174
0=
givenh
td
hd
Case 5: Takeoff (sg given and TSL >> (D+R) )
Given:
SOLO Aircraft Flight Performance
Ground Run
V = 0
sg
sTO
sr str
V TO
Rotation
Transition
sCL
θ CL
htr
hobs
R
Start from:

( )
TO
T
SL
s
W
VRDT
td
Vd
g
V
td
hd
p
SL
β
α
α








+−
≈+=
≈
  
0







==
TO
SL
V
W
Tg
td
sd
sd
Vd
td
Vd
β
α 0
/1
VdV
T
W
g
sd
SL
TO






=
0α
β
max,2
2
0max,
2
0
2
1
2
1
L
TO
TO
LstallstallTO CS
k
V
CSVLW ρρβ ===
The take-off velocity VTO is
VTO = kTO Vstall
Where Vstall is the minimum velocity at at which Lift equals weight and
kTO ≈ 1.1 to 1.2:






==
S
W
C
kV
k
V TO
L
TOstall
TO
TO
max,0
22
2
2
22 ρ
β
Integration from:
s = 0 to s = sg
V = 0 to V = VTO
2
2
0
TO
SL
TO
g
V
T
W
g
s 





=
α
β
sg – Ground Run
Constraint Analysis
175
Case 5: Takeoff (sg given and TSL >> (D+R) ) (continue – 1)
SOLO Aircraft Flight Performance
Ground Run
V = 0
sg
sTO
sr str
V TO
Rotation
Transition
sCL
θ CL
htr
hobs
R
2
2
0
TO
SL
TO
g
V
T
W
g
s 





=
α
β






==
S
W
C
kV
k
V TO
L
TOstall
TO
TO
max,0
22
2
2
22 ρ
β






=
S
W
Cgs
k
W
T TO
Lg
TO
TO
SL
max,00
22
ρ
β
α
β
We obtained:
from which:












=
S
W
C
k
T
W
g
s TO
L
TO
SL
TO
g
max,0
2
0 ρ
β
α
β
We have a Linear Relation between TSL/WTO and WTO/S
Constraint Analysis
176
Case 6: Landing
SOLO Aircraft Flight Performance
where ( )
( )






−=
−−=
µ
µ
β
ρ
W
T
gc
CC
SW
g
a grLgrD
TO
0
,,
:
/2
:
cab
Va
a
ca
Va
a
touchdown
4
2
:
4
2
:
2
1
1
−
=
−
=cVa
cVa
a
sg
+
+
−= 2
2
2
1
ln
2
1






−
−
⋅
+
+
−
=
1
2
2
1
1
1
1
1
ln
4
1
a
a
a
a
ca
tg
Ground Run Phase
We found
Ground Run sgr
Transition
Airborne Phase
Total Landing Distance
Float
sf
Flare stGlide sg
γ
hg
hf
Touchdown
2
0 VCVBTT ++=
For a given value of sg , there is only one value of WTO/S that satisfies this equation.
( )gTO sfSW =/
This constraint is represented in the TSL/WTO versus WTO/S plane as a vertical line, at
WTO/S corresponding to the required sg.
Constraint Analysis
177Constraint Diagram
SOLO Aircraft Flight Performance


















+
++





=
S
W
q
CC
K
S
W
q
K
W
T
TO
DRDTO
TO
SL
β
β
α
β 0
21












+






+
++





=
td
hd
V
S
W
q
CC
nK
S
W
q
nK
W
T
TO
DRDTO
TO
SL 10
2
2
1
β
β
α
β






=
S
W
Cgs
k
W
T TO
Lg
TO
TO
SL
max,00
22
ρ
β
α
β
( )gTO sfSW =/
Constraint Analysis
178
Comparison of Fighter Aircraft Propulsion Systems
SOLO
179
Comparison of Fighter Aircraft Propulsion Systems
SOLO
180
SOLO Aircraft Flight Performance
Composite Thrust Loading versus Wing Loading – for different Aircraft
Constraint Analysis
181
Constraint Diagram for F-16
SOLO
Aircraft Flight Performance
Constraint Analysis
Return to Table of Content
182
Weapon System Agility
Weapon System Agility
Return to Table of Content
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii
14 fixed wing fighter aircraft- flight performance - ii

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14 fixed wing fighter aircraft- flight performance - ii

  • 1. Fixed Wing Fighter Aircraft Flight Performance Part II SOLO HERMELIN Updated: 04.12.12 28.02.15 1 http://www.solohermelin.com
  • 2. Table of Content SOLO 2 Aerodynamics Introduction to Fixed Wing Aircraft Performance Earth Atmosphere Mach Number Shock & Expansion Waves Reynolds Number and Boundary Layer Knudsen Number Flight Instruments Aerodynamic Forces Aerodynamic Drag Lift and Drag Forces Wing Parameters Specific Stabilizer/Tail Configurations F i x e d W i n g P a r t I Fixed Wing Fighter Aircraft Flight Performance
  • 3. Table of Content (continue – 1) SOLO 3 Specific Energy Aircraft Propulsion Systems Aircraft Propellers Aircraft Turbo Engines Afterburner Thrust Reversal Operation Aircraft Propulsion Summary Vertical Take off and Landing - VTOL Engine Control System Aircraft Flight Control Aircraft Equations of Motion Aerodynamic Forces (Vectorial) Three Degrees of Freedom Model in Earth Atmosphere F i x e d W i n g P a r t I Fixed Wing Fighter Aircraft Flight Performance
  • 4. Table of Content (continue – 2) SOLO Fixed Wing Fighter Aircraft Flight Performance 4 Parameters defining Aircraft Performance Takeoff (no VSTOL capabilities) Landing (no VSTOL capabilities) Climbing Aircraft Performance Gliding Flight Level Flight Steady Climb (V, γ = constant) Optimum Climbing Trajectories using Energy State Approximation (ESA) Minimum Fuel-to- Climb Trajectories using Energy State Approximation (ESA) Maximum Range during Glide using Energy State Approximation (ESA) Aircraft Turn Performance Maneuvering Envelope, V – n Diagram
  • 5. Table of Content (continue – 3) SOLO Fixed Wing Fighter Aircraft Flight Performance 5 Air-to-Air Combat Energy–Maneuverability Theory Supermaneuverability Constraint Analysis References Aircraft Combat Performance Comparison
  • 6. SOLO This Presentation is about Fixed Wing Aircraft Flight Performance. The Fixed Wing Aircraft are •Commercial/Transport Aircraft (Passenger and/or Cargo) •Fighter Aircraft Fixed Wing Fighter Aircraft Flight Performance Continue from Part I
  • 7. 7 Fixed Wing Fighter Aircraft Flight PerformanceSOLO The Aircraft Flight Performance is defined by the following parameters • Take-off distance • Landing distance • Maximum Endurance and Speed for Maximum Endurance • Maximum Range and Speed for Maximum Range • Ceiling(s) • Climb Performance • Turn Performance • Combat Radius • Maximum Payload Parameters defining Aircraft Performance
  • 8. 8 Performance of an Aircraft with Parabolic PolarSOLO Assumptions: •Point mass model. •Flat earth with g = constant. •Three-dimensional aircraft trajectory. •Air density that varies with altitude ρ=ρ(h) •Drag that varies with altitude, Mach number and control effort D = D(h,M,n) and is given by a Parabolic Polar. •Thrust magnitude is controllable by the throttle. •No sideslip angle. •No wind. α T V L D Bx Wx Bz Wz Wy By Aircraft Coordinate System To understand how different parameters affect Aircraft Performance we start with a Simplified Model, where Analytical Solutions can be obtained. Results for real aircraft will then be presented. Return to Table of Content
  • 9. 9 SOLO Aircraft Flight Performance Takeoff The Takeoff distance sTO is divided as the sum of the following distances: sg – Ground Run sr – Rotation Distance st – Transition Distance sc – Climb Distance to reach Screen Height ctrgTO sssss +++= Ground Run V = 0 sg sTO sr str V TO Rotation Transition sCL θ CL htr hobs R Takeoff htransition < hobstacle θ CL Ground Run V = 0 sg sTO sr sobs V TO Rotation Transition hobs R Takeoff htransition > hobstacle We distinguish between two cases of Takeoff •The Aircraft must passes over an obstacle at altitude hobs.. •The obstacle is cleared during the transition phase. Assume no Vertical Takeoff Capability.
  • 10. 10 Takeoff (continue – 1) During the Ground Run there are additional effects than in free flight, that must be considered: -Friction between the tires and the ground during rolling. -Additional drag due to the landing gear fully extended. -Additional Lift Coefficient due to extended flaps. -Ground Effect due to proximity of the wings to the ground, that reduces the Induced Drag and the Lift. Ground Run SOLO Aircraft Flight Performance Ground run sg Transition distance st Climb distance sc Stall safety Take-off possible with one engine Continue take-off if engine fails after this point Stop take-off if engine fails before this point Acceleration at full power γ c Total take-off if distance VCRVMCG VTVS L W TD R μR The Aircraft can leave the ground when the velocity reaches the Stall Velocity where Lift equals Weight max, 2 0 2 1 Lstallstall CSVLW ρ== max,0 12 L stall CS W V ρ = The Liftoff Velocity is 1.1 to 1.2 Vstall.
  • 11. 11 ReactionGroundLWR gW RDT td Vd V V td xd −= −− == = / µ ( ) ( )LWDT gW Vd td LWDT gWV Vd sd xs −−− = −−− = = µ µ / / Takeoff (continue – 2) Average Coefficient of Friction Values μ Ground Run SOLO Aircraft Flight Performance Ground run sg Transition distance st Climb distance sc Stall safety Take-off possible with one engine Continue take-off if engine fails after this point Stop take-off if engine fails before this point Acceleration at full power γ c Total take-off if distance VCRVMCG VTVS hc L W R μR D T V
  • 12. 12 Takeoff (continue – 3) SOLO Aircraft Flight Performance Ground run sg Transition distance st Climb distance sc Stall safety Take-off possible with one engine Continue take-off if engine fails after this point Stop take-off if engine fails before this point Acceleration at full power γc Total take-off if distance VCRVMCG VTVS hc L W R μR D T V T (Jet) Lift,Drag,Thrust,Resistance–lb L,D,T,R T (Prop) D +μ R Ground Speed – ft/s Texcess(Prop)=T(Prop) -(D+μ R) Texcess(Jet)=T(Jet) -(D+μ R) Vground ( ) ReactionGroundLWR RDT g WV −= +−= µ  Ground Run (continue -1)
  • 13. 13 2 0 VCVBTT ++= cVbVaVd td cVbVa V Vd sd xs ++ = ++ = = 2 2 1 Takeoff (continue – 4) Ground Run (continue – 2) To obtain an Analytic Solution assume that during the Ground Run the Thrust can be approximated by Using       = = L D CSVL CSVD 2 2 2 1 2 1 ρ ρ ( )       −= = +−−= µ µ ρ W T gc W gB b W gC CC W Sg a LD 0 : 2 : 2 : where SOLO Aircraft Flight Performance Ground run sg Transition distance st Climb distance sc Stall safety Take-off possible with one engine Continue take-off if engine fails after this point Stop take-off if engine fails before this point Acceleration at full power γ c Total take-off if distance VCRVMCG VTVS hc L W R μR D T V
  • 14. 14 cVbVaVd td cVbVa V Vd sd xs ++ = ++ = = 2 2 1 Takeoff (continue – 5) Ground Run (continue – 3) Integrating those equations between two velocities V1 and V2 gives       − − ⋅ + + − + ++ ++ = 2 1 1 2 2 1 2 1 2 2 2 1 1 1 1 ln 42 ln 2 1 a a a a caba b cVbVa cVbVa a sg       − − ⋅ + + − = 1 2 2 1 2 1 1 1 1 ln 4 1 a a a a cab tg where cab bVa a cab bVa a 4 2 : 4 2 : 2 2 2 2 1 1 − + = − + = SOLO Aircraft Flight Performance Ground run sg Transition distance st Climb distance sc Stall safety Take-off possible with one engine Continue take-off if engine fails after this point Stop take-off if engine fails before this point Acceleration at full power γ c Total take-off if distance VCRVMCG VTVS hc L W R μR D T V 2 0 VCVBTT ++=
  • 15. 15 Takeoff (continue – 6) Ground Run (continue – 4) then ( ) ( )             − − −− = + = TL LDLD g CWT CCCCg SW c cVa a s µ µµρ / 1 1 ln / ln 2 1 0 2 2 0,00 01 ==⇐== CBTTV Assume where 22 :& /2 : VV V SW C T T LT == ρ A further simplification, using , givesZ Z Z 1 1 1 ln << ≈ −       − = µρ W T Cg SW s TL g 0 / SOLO Aircraft Flight Performance gL sCg SW W T T ρ /0 > Ground run sg Transition distance st Climb distance sc Stall safety Take-off possible with one engine Continue take-off if engine fails after this point Stop take-off if engine fails before this point Acceleration at full power γc Total take-off if distance VCRVMCG VTVS hc L W R μR D T V
  • 16. 16 Takeoff (continue – 7) Rotation Distance At the ground roll and just prior to going into transition phase, most aircraft are Rotated to achieve an Angle of Attack to obtain the desired Takeoff Lift Coefficient CL. Since the rotation consumes a finite amount of time (1 – 4 seconds), the distance traveled during rotation sr, must be accounted for by using where Δt is usually taken as 3 seconds. SOLO Aircraft Flight Performance tVs tr ∆= Ground Run V = 0 sg sTO sr str V TO Rotation Transition sCL θ CL htr hobs R L W R μR D T V
  • 17. 17 Takeoff (continue – 8) Transition Distance In the Transition Phase the Aircraft is in the Air (μ = 0) and turn to the Climb Angle. The Equation of Motion are: SOLO Aircraft Flight Performance Ta Ta t Ta t VV DT VV g W t DT VV g W s >        − − = − − = 2 2 22 DT gW Vd td DT gWV Vd sd xs − = − = = / / Assuming T – D = const., we can Integrate the Equations of Motion (assuming Va > VT) Ground Run V = 0 sg sTO sr str V TO Rotation Transition sCL θ CL htr hobs R
  • 18. 18 Takeoff (continue – 9) Climb Distance The Climb Distance is evaluated from the following (see Figure): SOLO Aircraft Flight Performance c c c c c hh s c γγ γ 1 tan << ≈= For small angles of Climb L = W. We can write Ground Run V = 0 sg sTO sr str V TO Rotation Transition sCL θ CL htr hobs R cL cLD c c c C CkC W T L D W T , 2 ,0 + −=−=γ We have cLcLD c c CkCCWT h s ,,0 // −− ≈
  • 19. 19 Takeoff (continue – 10) SOLO Aircraft Flight Performance 19 ctrgTO sssss +++= sec41−=∆∆= ttVs tr Ta Ta t Ta t VV DT VV g W t DT VV g W s >        − − = − − = 2 2 22       − − ⋅ + + − + ++ ++ = 2 1 1 2 2 1 2 1 2 2 2 1 1 1 1 ln 42 ln 2 1 a a a a caba b cVbVa cVbVa a sg cab bVa a cab bVa a 4 2 : 4 2 : 2 2 2 2 1 1 − + = − + =       − − ⋅ + + − = 1 2 2 1 2 1 1 1 1 ln 4 1 a a a a cab tg Ground Run V = 0 sg sTO sr str V TO Rotation Transition sCL θ CL htr hobs R Takeoff Summary Rotation Phase Climb Phase Transition Phase Ground Run cLcLD c c CkCCWT h s ,,0 // −− ≈
  • 20. 20Minimum required takeoff runway lengths. Summary of takeoff requirements In order to establish the allowable takeoff weight for a transport category airplane, at any airfield, the following must be considered: •Airfield pressure altitude •Temperature •Headwind component •Runway length •Runway gradient or slope •Obstacles in the flight path Return to Table of Content
  • 21. 21 Landing Landing is similar to Takeoff, but in reverse. We assume again that the Aircraft doesn’t have VTOL capabilities. The Landing Phase can be divide in the following Phases: 1. The Final approach when the Aircraft Glides toward the runway at a steady speed and rate of descent. 2. The Flare, or Transition phase. The Pilot attempts to rotate the Aircraft nose up and reduce the Rate of Sink to zero and the forward speed to a minimum, that is larger than Vstall. When entering this phase the velocity is less than 1.3Vstall and 1.15 Vstall at touchdown. 3. The Floating Phase, which is necessary if at the end of Flare phase, when the rate of descent is zero, an additional speed reduction is necessary. The Float occurs when the Aircraft is subjected to ground effect which requires speed reduction for touchdown. 4. The Ground Run after the Touchdown the Aircraft must reduce the speed to reach a sufficient low one to be able to turn off the runway. For this it can use Thrust Reverse (if available), spoilers or drag parachutes (like F-15 or MIG-21) and brakes are applied. SOLO Aircraft Flight Performance Ground Run sgr Transition Airborne Phase Total Landing Distance Float sf Flare stGlide sg γ hg hf Touchdown
  • 22. 22 Landing (continue – 1) Descending Phase SOLO Aircraft Flight Performance The Aircraft is aligned with the landing runaway at an altitude hg and a gliding angle γ. The Aircraft Glides toward the runway at a steady speed and rate of descent, until it reaches The altitude ht at which it goes to Transition Phase, turning with a Radius of Turn R. The Descending Range on the ground is : γγ γ γ γ RhRhhh s ggtg g − ≈ − = − = <<1 tan cos tan Ground Run sgr Transition Airborne Phase Total Landing Distance Float sf Flare stGlide sg γ hg hf Touchdown
  • 23. 23 Landing (continue – 2) Transition Phase SOLO Aircraft Flight Performance If γ is the descent angle and R is the turn radius then the Aircraft must start the Transition Phase at an altitude ht, above the ground, given by: ( )γcos1−=Rht The Transition Range on the ground is γγ RRst ≈= sin To calculate the turn radius we must use the flight velocity which varies between 1.3 Vstall at the beginning to 1.1 Vstall at Touchdown. Let use an average velocity 3.11.1 −∈= tstalltt mVmV If the Transition Turn Acceleration is nt = 1.15 – 1.25 g than the Turn Radius is ( ) gn V R t t 1 2 − = The Transition Turn time is ( ) gn V RV t t t t t 1/ − == γγ Ground Run sgr Transition Airborne Phase Total Landing Distance Float sf Flare stGlide sg γ hg hf Touchdown
  • 24. 24 Landing (continue – 3) Float Phase SOLO Aircraft Flight Performance In this phase the Pilot brings the nose wheel to the ground at the touchdown velocity Vt: tVs tf ∆= where Δt is between 2 to 3 seconds. Ground Run sgr Transition Airborne Phase Total Landing Distance Float sf Flare stGlide sg γ hg hf Touchdown
  • 25. 25 Landing (continue – 4) Ground Run Phase SOLO Aircraft Flight Performance The equations of motion are the same as those developed for Takeoff, but with different parameters, adapted for Landing. Those equations are: cVbVaVd td cVbVa V Vd sd xs ++ = ++ = = 2 2 1 ( )       −= = +−−= µ µ ρ W T gc W gB b W gC CC W Sg a grLgrD 0 ,, : 2 : 2 : where       − − ⋅ + + − + ++ ++ = 2 1 1 2 2 1 2 1 2 2 2 1 1 1 1 ln 42 ln 2 1 a a a a caba b cVbVa cVbVa a sg       − − ⋅ + + − = 1 2 2 1 2 1 1 1 1 ln 4 1 a a a a cab tg where cab bVa a cab bVa a 4 2 : 4 2 : 2 2 2 2 1 1 − + = − + = 2 0 VCVBTT ++= Assume a constant Thrust T = T0: B = 0, C = 0. V1 = Vtouchdown, V2 = final velocity cVa cVa a sg + + −= 2 2 2 1 ln 2 1       − − ⋅ + + − = 1 2 2 1 1 1 1 1 ln 4 1 a a a a ca tg ( )       −==−−= µµ ρ W T gcbCC W Sg a LD 0 :,0, 2 : Ground Run sgr Transition Airborne Phase Total Landing Distance Float sf Flare stGlide sg γ hg hf Touchdown
  • 26. 26 Landing (continue – 5) Ground Run Phase (continue – 1) SOLO Aircraft Flight Performance where ( )       −= −−= µ µ ρ W T gc CC W Sg a grLgrD 0 ,, : 2 : cab Va a ca Va a touchdown 4 2 : 4 2 : 2 1 1 − = − = Assume a constant Thrust T = T0: B = 0, C = 0. V1 = Vtouchdown, V2 = final velocity cVa cVa a sg + + −= 2 2 2 1 ln 2 1       − − ⋅ + + − = 1 2 2 1 1 1 1 1 ln 4 1 a a a a ca tg For the Landing Ground Run Phase the following must included: • if Thrust Reversal exists we must change T0 to – T0_reversal . •The Drag Coefficient CD0,gr must consider: - the landing gear fully extended. - spoilers or drag parachutes (if exist) •μ – the friction coefficient must be increased to describe the brakes effect. Ground Run sgr Transition Airborne Phase Total Landing Distance Float sf Flare stGlide sg γ hg hf Touchdown
  • 27. 27 Landing (continue – 6) Summary SOLO Aircraft Flight Performance where ( )       −= −−= µ µ ρ W T gc CC W Sg a grLgrD 0 ,, : 2 : cab Va a ca Va a touchdown 4 2 : 4 2 : 2 1 1 − = − =cVa cVa a sg + + −= 2 2 2 1 ln 2 1       − − ⋅ + + − = 1 2 2 1 1 1 1 1 ln 4 1 a a a a ca tg Ground Run Phase tVs tf ∆= Float Phase ( ) gn V Rs t t t 1 2 − == γ γ ( ) gn V RV t t t t t 1/ − == γγ Transition Phase Descent Phase Ground Run sgr Transition Airborne Phase Total Landing Distance Float sf Flare stGlide sg γ hg hf Touchdown ( ) γγ γ γ 1/ tan cos tan 2 −− = − = − = ttggfg g nVhRhhh s
  • 28. 28 H.H. Hurt, Jr., “Aerodynamics for Naval Aviators “,NAVAIR 00=80T-80 1-1-1965, pg. 35 Return to Table of Content
  • 29. 29 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight The forces acting on an airplane in Level Flight are shown in Figure 0= = h Vx   Lift and Drag Forces: ( ) TCkCSVCSVD WCSVL LDD L =+== == 2 0 22 2 2 1 2 1 2 1 ρρ ρ 2 2 VS W CL ρ =       +=      += SV Wk CSV SV Wk CSVD DD 2 2 0 2 242 2 0 2 2 2 14 2 1 ρ ρ ρ ρ Lift DragThrust Weight Equations of motion: 0 0 =− =− DT WL Quasi-Static
  • 30. 30 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight  DragInducedDragParasite D SV Wk CSVD 2 2 0 2 2 2 1 ρ ρ += Because of opposite trends in Parasite Drag and Induced Drag, with changes in velocity, the Total Drag assumes a minimum at a certain velocity. If we ignore the change in velocity of CD0 and k with velocity we obtain 0 4 3 2 0 =−= SV Wk CSV Vd Dd D ρ ρ The velocity of minimum Total Drag is * 4 0 2 V C k S W V D == ρ We see that the velocity of minimum Total Drag is equal to the Reference Velocity. 0 2 2 1 DCSVρ SV Wk 2 2 2 ρ* V Lift DragThrust Weight
  • 31. 31 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight For the velocity, V*, of minimum Total Drag we have 02* 2 2 Di CkW SV Wk D == ρ  DragInducedDragParasite D SV Wk CSVD 2 2 0 2 2 2 1 ρ ρ += 000min 2 DDD CkWCkWCkWD =+= and 0 2 2 1 DCSVρ SV Wk 2 2 2 ρ * V Lift DragThrust Weight
  • 32. 32M. Corcoran, T. Matthewson, N. W. Lee, S. H. Wong, “Thrust Vectoring” Comparison of Takeoff Weight and Empty Weight of different Aircraft
  • 33. 33 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight The Power Required, PR, for Level Flight is SV Wk CSVVDP DR ρ ρ 2 0 3 2 2 1 +=⋅= The Power Required for Level Flight assumes a minimum at a certain velocity Vmp. If we ignore the change in velocity of CD0 and k with velocity we obtain 0 2 2 3 2 2 0 2 =−= SV Wk CSV Vd Pd D R ρ ρ or * 4 0 3 1 3 2 V C k S W V D mp == ρ *0 2, 3 32 L D mp mpL C k C VS W C === ρ ( ) * 000 0 2 ,0 , 866.0 1 4 3 /3 /3 e CkkCkC kC CkC C e DDD D mpLD mpL mp == + = + = * 2 min, 866.03 8 e VW SV Wk P mp mp R == ρ 0 3 2 1 DCSVρ SV Wk ρ 2 2 * 3 1 V min,RP Lift DragThrust Weight
  • 34. Fixed Wing Fighter Aircraft Flight Performance SOLO Available Aircraft Power and Thrust • Throttle Effect 10 ≤≤= ηη ATT • Propeller airspeedwithvariationsmallVTP propellerA ≈⋅=, V Pa, propeller Power Propeller Aircraft Available Power at Altitude (h) At a given Altitude h • Turbojet airspeedwithvariationsmallT jetA ≈, V Ta, jet Thrust Jet Aircraft Available Power at Altitude h At a given Altitude h Lift DragThrust Weight Lift DragThrust Weight Level Flight
  • 35. 35 Fixed Wing Fighter Aircraft Flight Performance SOLO Vmin Vmax Pa, propeller PRPmin BA ηaPa, propeller Propeller Aircraft Vmin Vmax Ta, jet TR Dmin η Ta, jet A B Jet Aircraft Level Flight To have a Level Flight the requirement must be satisfied by the available propulsion performance. •For a Propeller Aircraft, the available power Pa,propeller , at a given altitude h, is almost insensitive with changes in velocity. The Velocity in Level Flight is steady when the graph of Required Power PR intersects the graph of Pa,propeller at points A and B. We get two velocities Vmin (h) at A and Vmax (h) at B. By controlling the Propeller Power ηa Pa,propeller (0< ηa <1) we can reach any velocity between Vmin (h) and Vmax (h). •For a Jet Aircraft, the available Thrust Ta,jet , at a given altitude h, is almost insensitive with changes in velocity. The Velocity in Level Flight is steady when the graph of Required Thrust TR intersects the graph of Ta,jet at points A and B. We get two velocities Vmin (h) at A and Vmax (h) at B. By controlling the Jet Thrust η Ta,jet (0< η<1) we can reach any velocity between Vmin (h) and Vmax (h).
  • 36. 36 Fixed Wing Fighter Aircraft Flight Performance SOLO Vmin Vmax Ta, jet TR Dmin η Ta, jet A B Jet Aircraft Level Flight We have Analytical Solution for Jet Aircraft ( ) SV Wk CSVCkCSVDT DLD 2 2 0 22 0 2 2 2 1 2 1 ρ ρρ +=+== Define 0 * 0 0 * * * 4 0 2 : 2*,*,: 2 :*, * : D DD D L D L D CkW T W eT z CC k C C C C e C k S W V V V u == === == ρ    2 2 /1 2 0 0 2 2 0 2 2 2 u D u Dz D V C k S W C k S W V T CkW ρ ρ += 012 24 =+− uzu Lift DragThrust Weight
  • 37. 37 Fixed Wing Fighter Aircraft Flight Performance SOLO Vmin Vmax Ta, jet TR Dmin η Ta, jet A B Jet Aircraft Level Flight Analytical Solution for Jet Aircraft 012 24 =+− uzu Solving we obtain 1 1 2 max 2 min −+= −−= zzu zzu 4 0 maxmaxmax 4 0 minminmin 2 * 2 * D D C k S W uVuV C k S W uVuV ρ ρ == == Lift DragThrust Weight 0 * 0 0 * * * 4 0 2 : 2*,*,: 2 :*, * : D DD D L D L D CkW T W eT z CC k C C C C e C k S W V V V u == === == ρ
  • 38. 38 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Analytical Solution for Jet Aircraft 1 1 2 max 2 min −+= −−= zzu zzu 12 min −−= zzu 12 max −+= zzu At the absolute Ceiling (when is only one possible velocity) we have umax = umin, therefore z = 1. max, 2 L stall CS W V ρ = Lift DragThrust Weight 0 * 0 0 * * * 4 0 2 : 2*,*,: 2 :*, * : D DD D L D L D CkW T W eT z CC k C C C C e C k S W V V V u == === == ρ
  • 39. 39 Drag Characteristics Fixed Wing Fighter Aircraft Flight Performance SOLO
  • 40. 40 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Aircraft Range in Level Flight Lift DragThrust Weight Range in Level Flight of Jet Aircraft Equations of motion: 0 0 =− =− DT WL 0= = h Vx   We add the equation of fuel consumption TcW −= c – specific fuel consumption We assume that fuel consumption is constant for a given altitude. V td Wd Wd xd td xd == Dc V Tc V W V Wd xd DT −=−== = 
  • 41. 41 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Aircraft Range in Level Flight Lift DragThrust Weight Range in Level Flight of Jet Aircraft Dc V Wd xd −= The quantity dx/dW is called the “Instantaneous Range” and is equal to the Horizontal Range traveled per unit load of fuel or the “Specific Range”. Multiply and divide by L = W Wc V C C Wc V D L Wd xd D L       −=            −= Integrating we obtain ∫       −=−= f i W W D L if W Wd V cC C xxR 1 :
  • 42. 42 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Aircraft Range in Level Flight Lift DragThrust Weight Range in Level Flight of Jet Aircraft To perform the integration we must specify the variation of CL, CD and V. Let consider two cases: ∫       −=−= f i W W D L if W Wd V cC C xxR 1 : a. Range at Constant Altitude of Jet Aircraft We have LCVSLW 2 2 1 ρ== LCS W V ρ 2 = The velocity changes (decreases) since the weight W decreases due to fuel consumption. [ ]if D L W W D L WW C C cW Wd ScC C R f i −         =         −= ∫ 221 ρ
  • 43. 43 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Aircraft Range in Level Flight Lift DragThrust Weight a. Range at Constant Altitude of Jet Aircraft [ ]if D L W W D L WW C C cW Wd ScC C R f i −         =         −= ∫ 221 ρ The maximum range is obtained when [ ]if D L WW C C c R −         = max max 2 max 2 0max         + =         LD L D L CkC C C C ( ) 030 2 2 1 2 022 0 2 0 2 0 =−⇒= + − + =         + LD LD LL L LD LD L L CkC CkC CkC C CkC CkC C Cd d The maximum range is obtained when *0 3 1 3 1 L D L C k C C == The Velocity at maximum range is ( ) ( ) ( ) ( )tV CS tW CS tW tV LL *4 * 4 * 3 2 3 3/ 2 === ρρ
  • 44. 44 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Aircraft Range in Level Flight Lift DragThrust Weight b. Range at Constant Velocity of Jet Aircraft               =      −= ∫ f i D L W W D L W W C C c V W Wd V cC C R f i ln 1 The Velocity V is constant and equal to V* corresponding to initial weight Wi. 4 0 * * 22 D i L i C k S W CS W V ρρ == The maximum range is obtained when         =               = f i f i D L W W e c V W W C C V c R lnln 1 * * max max To keep Velocity V constant when weight W decreases, the air density ρ must also decrease, hence the Aircraft will gain (qvasistatic) altitude ( ) Pc td Wd td hd e td hd p hh −==−= − 0/ 0ρ ρ
  • 45. 45 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Aircraft Range in Level Flight Range in Level Flight of Propeller Aircraft Lift DragThrust Weight The equation of fuel consumption PcW P−= cp – specific fuel consumption (consumed per unit power developed by the engine per unit time We assume that fuel consumption is constant for a given altitude. V td Wd Wd xd td xd == Pc V W V Wd xd p −==  - Required PowerVDPR ⋅= PP pA ⋅=η - Available Power ηp – propulsive efficiency AR PP = p VD P η ⋅ =
  • 46. 46 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Aircraft Range in Level Flight Range in Level Flight of Propeller Aircraft Lift DragThrust Weight WcC C WcD L DcPc V Wd xd p p D L p p WL p p p ηηη       −=−=−=−= = Integration gives ∫       −=−= f i W W p p D L ff W Wd cC C xxR η : We assume • Angle of Attack is kept constant throughout cruise, therefore e = CL/CD is constant •ηp is independent on flight velocity f i p p W W e c R ln η = Bréguet Range Equation The maximum range of Propeller Aircraft in Level Flight is f i Dp p f i p p W W CkcW W e c R ln 2 1 ln 0 * max ηη ==
  • 47. 47 Louis Charles Bréguet (1880 – 1955) The Bréguet Range Equation The Bréguet range equation determines the maximum flight distance. The key assumptions are that SFC, L/D, and flight speed, V are constant, and therefore take-off, climb, and descend portions of flights are not well modeled (McCormick, 1979; Houghton, 1982). ( )         ⋅ = final initial W W SFCg DLV Range ln / Winitial = Wfuel + Wpayload + Wstructure + Wreserve Wfinal = Wpayload + Wstructure + Wreserve where ( )         ++ + ⋅ = reservestructurepayload fuel WWW W SFCg DLV Range 1ln / where SFC, L/D, and Wstructure are technology parameters while Wfuel, Wpayload, and Wreserve are operability parameters. Fixed Wing Fighter Aircraft Flight Performance SOLO
  • 48. 48 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Aircraft Range in Level Flight Range in Level Flight of Propeller Aircraft Lift DragThrust Weight Let assume that the flight to maximum range is performed in one of two ways 1. Propeller Aircraft Flight at Constant Altitude In Constant Altitude Flight the velocity changes with the decrease of weight such that ( ) ( ) 4 0 * 2 DC k S tW VtV ρ == 2. Propeller Aircraft Flight with Constant Velocity In Constant Velocity Flight the velocity is the V* velocity based on the initial weight of the Aircraft . 2 4 0 * const C k S W VV D i === ρ
  • 49. 49 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Aircraft Endurance in Level Flight Lift DragThrust Weight The Endurance of an Airplane remains in the air and is usually expressed in hours. Endurance of Jet Aircraft in Level Flight We have TcW −= c – specific fuel consumption W Wd c e W Wd D L cDc Wd Tc Wd td WLDT −=−=−=−= == 1 Integrating we obtain ∫−= f i W W W Wd c e t Assuming that the Angle of Attack is held constant throughout the flight, e =CL/CD is constant f i W W c e t ln= f i Df i W W CkcW W c e t ln 2 1 ln 0 * max == The Maximum Endurance for Jet Aircraft occurs for e = e*, CL = CL*, V = V*, D = Dmin.
  • 50. 50 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Aircraft Endurance in Level Flight The Endurance of an Airplane remains in the air and is usually expressed in hours. Endurance of Propeller Aircraft in Level Flight We have ppp VDcPcW η/⋅−=−= W Wd V e cW Wd VD L cVD Wd c td p p p p WL p p 11 ηηη −=−= ⋅ −= = Assuming that the Angle of Attack is held constant throughout the flight, e =CL/CD is constant Lift DragThrust Weight cp – specific fuel consumption (consumed per unit power developed by the engine per unit time. ηp – propulsive efficiency Integrating we obtain ∫−= f i W W p p W Wd V e c t 1η The Endurance of Propeller Aircraft depends on Velocity, therefore we will assume two cases 1.Flight at Constant Altitude 2.Flight with Constant Velocity
  • 51. 51 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Endurance of Propeller Aircraft in Level Flight Lift DragThrust Weight The velocity will change to compensate for the decrease in weight ∫ =−= f i W W D L p p C C e W Wd V e c t 1η 1. Propeller Aircraft Flight at Constant Altitude We have LCVSLW 2 2 1 ρ== LCS W V ρ 2 =         −        = ifD L p p WW S C C c t 11 2 2 2/3 ρη For Maximum Endurance Propeller Aircraft has to fly at that Angle of Attack such that (CL 3/2 /CD) is maximum, which occurs when CL=√3 CL * and V = 0.76 V* .         −        = ifDp p WW S Ckc t 11 2 27 4 12 0 3max ρη
  • 52. 52 Fixed Wing Fighter Aircraft Flight Performance SOLO Level Flight Endurance of Propeller Aircraft in Level Flight Lift DragThrust Weight ∫ =−= f i W W D L p p C C e W Wd V e c t 1η 2. Propeller Aircraft Flight with Constant Velocity f i p p W W V e c t ln 1η = For Maximum Endurance Propeller Aircraft has to fly at a velocity such that e=(CL/CD) is maximum, which occurs when CL=CL * and V = V* , which is based on initial weight Wi 4 0 * * 22 D i L i C k S W CS W V ρρ == 0 * 2 1 DCk e = f i D i p p f i D i Dp p f i p p W W CkS W cW W C k S W CkcW W V e c t ln 1 2 ln 2 2 1 ln 1 4 3 0 4 00 * * max ρ η ρ ηη ===
  • 53. 53 D=TR V V* tmax Slope min(PR/V) Bréguet Velocities for Maximum Range and Maximum Endurance of Propeller Aircraft Fixed Wing Fighter Aircraft Flight Performance SOLO Graphical Finding of Maximum Range and Endurance of Jet Aircraft in Level Flight       =      ⇔ V D D V R VV minmaxmax Maximum Range From Figure we can see that min (D/V) is obtained by taking the tangent to D graph that passes through origin. The point of tangency will give D and V for (D)min. Maximum Endurance  ∫∫ < = < −=−= 00 111 Wd Dc Wd Tc t DT ( )D D t VV min 1 maxmax =      ⇔ From Figure we can see that min (PR) is obtained by taking the PR and V for (PR)min. Lift DragThrust Weight ∫∫ < −== 0 Wd Dc V xdR
  • 54. 54 PR V V* Rmax 0.866 V* tmax Slope min(PR/V) Velocities for Maximum Range and Maximum Endurance of Propeller Aircraft Lift DragThrust Weight Fixed Wing Fighter Aircraft Flight Performance SOLO Graphical Finding of Maximum Range and Endurance of Propeller Aircraft in Level Flight   ∫∫∫∫ >>> ⋅ −=−=−== 000 Wd VD V c Wd P V c Wd Pc V xdR p p Rp p p ηη D V P P V R V R V R V minminmaxmax =      =      ⇔ Maximum Range From Figure we can see that min (PR/V) is obtained by taking the tangent to PR graph that passes through origin. The point of tangency will give PR and V for (PR/V)min. Maximum Endurance  ∫∫ << −=−= 00 11 Wd Pc Wd Pc t Rp p p η ( ) ( )VDP P t V R V R V ⋅==      ⇔ minmin 1 maxmax From Figure we can see that min (PR) is obtained by taking the PR and V for (PR)min.
  • 55. 55 H.H. Hurt, Jr., “Aerodynamics for Naval Aviators “,NAVAIR 00-80T-80 1-1-1965, pg. 35 Fixed Wing Fighter Aircraft Flight Performance
  • 56. 56 H.H. Hurt, Jr., “Aerodynamics for Naval Aviators “,NAVAIR 00-80T-80 1-1-1965, pg. 35 Fixed Wing Fighter Aircraft Flight Performance
  • 57. 57 H.H. Hurt, Jr., “Aerodynamics for Naval Aviators “,NAVAIR 00-80T-80 1-1-1965, pg. 35 Fixed Wing Fighter Aircraft Flight Performance
  • 58. 58 Flight Ceiling by the available Climb Rate - Absolute 0 ft/min - Service 100 ft/min - Performance 200 ft/min True Airspeed Altitude Absolute Ceiling Service Ceiling Performance Ceiling Excess Thrust provides the ability to accelerate or climb True Airspeed Thrust Available Thrust Required Thrust True Airspeed Thrust Available Thrust Required Thrust A AB B C D E E Thrust True Airspeed Available Thrust Required Thrust C D Jet Aircraft Flight Envelope Determined by Available Thrust Flight Envelope: Encompasses all Altitudes and Airspeeds at which Aircraft can Fly Stengel, MAE331, Lecture 7, Gliding, Climbing and Turning Performance Fixed Wing Fighter Aircraft Flight Performance SOLO Lift DragThrust Weight Changes in Jet Aircraft Thrust with Altitude
  • 59. 59 Propeller Aircraft Ceiling Determined by Available Power To find graphically the maximum Flight Altitude (Ceiling) for a Propeller Aircraft we use the PR (Power Required) versus V (Velocity) graph. The maximum Flight Altitude corresponds to maximum Range Rmax. We have shown that to find Rmax we draw the Tangent Line to PR Graph, passing trough the origin. Fixed Wing Fighter Aircraft Flight Performance SOLO Lift DragThrust Weight Changes in Propeller Aircraft Power and Thrust with Altitude VC Pa, propeller PR hcruise A h2 h1 h0 h0 < h1 <h2 < hcruise The intersection point A with PR Graph defines the Ceiling Velocity VC, and the Pa (Available Power – function of Altitude) with this point defines the Ceiling Altitude. Return to Table of Content
  • 60. 60 Fixed Wing Fighter Aircraft Flight Performance SOLO Gliding Flight A Glider is an unpowered airplane. 0 sin cos = = = W Vh Vx    γ γ 1<<γ 0=+ = γWD WL .constW Vh Vx = = = γ  Lift and Drag Forces: ( ) γρρ ρ WCkCSVCSVD WCSVL LDD L −=+== == 2 0 22 2 2 1 2 1 2 1 LCS W V ρ 2 = eC C L D W D L D LW 1 −=−=−=−= = γ Equations of motion: 0sin 0cos =+ =− γ γ WD WLQuasi-Steady Flight
  • 61. 61 Fixed Wing Fighter Aircraft Flight Performance SOLO Gliding Flight We found LCS W V ρ 2 = eC C L D W D L D LW 1 −=−=−=−= = γ Flattest Glide” (γ = γmin) The Flattest Glide (γ = γmin) is given by: 0 * max min min 22 1 DL CkCk eW D −=−=−=−=γ e LC*LC *2 1 LCk CL/CD as a function of CL k C C D L 0 * = The flight velocity for the Flattest Glide is given by: 4 0 *.. 2 * 2 DL GF C k S W V CS W V ρρ === The flight velocity for the Flattest Glide is equal to the reference velocity V* or u = 1. The Flattest Glide is conducted at constant dynamic pressure. . 2 1 0 * 2 .. const C k W C W VSq DL GFG ==== ρ
  • 62. 62 H.H. Hurt, Jr., “Aerodynamics for Naval Aviators “,NAVAIR 00=80T-80 1-1-1965, pg. 35 Gliding Flight CLEAR CONFIGURATION LANDING CONFIGURATION LIFT to DRAG RATIO L/D (L/D)max LIFT COEFFICIENT, CL CLEAR CONFIGURATION LANDING CONFIGURATION RATEOF SINK VELOCITY (L/D)max TANGENT TO RATE OF SINK GRAPH AT THE ORIGIN Gliding Performance Fixed Wing Fighter Aircraft Flight Performance SOLO
  • 63. 63 Fixed Wing Fighter Aircraft Flight Performance SOLO Gliding Flight We have: Distance Covered with respect to Ground The maximum Ground Range is covered for the Flattest Glide at the reference velocity V* or u = 1. γV td hd V td xd = = D L e V V hd xd −=−=== γγ 1 Assuming a constant Angle of Attack during Glide, e is constant and the Ground Range R, to descend from altitude hi to altitude hf is given by: ( ) hehhehdexxR fi h h if f i ∆=−=−=−= ∫: and 0 maxmax 2 DCk h heR ∆ =∆= e LC*LC *2 1 LCk CL/CD as a function of CL
  • 64. 64 Fixed Wing Fighter Aircraft Flight Performance SOLO Gliding Flight Rate of sink is defined as: Rate of Sink         == ⋅ =−=−= = = 2/3 2 22 L D L D L L D W D CS W V s C C S W C C CS W W VD V td hd h L ρρ γ ρ  The term DV = PR represents the Power Required to sustain the Gliding Flight. Therefore the Rate of Sink is minimum when the Power Required is minimum, or (CD/CL 3/2 ) is minimum ( ) ( ) 0 2 3 2 342 3 2 2/5 0 2 2/5 2 0 2 3 2 0 2/12/3 2/3 2 0 2/3 = − = +− = +− =        + =        L DL L LDL L LDLLL L LD LL D L C CCk C CkCCk C CkCCCCk C CkC Cd d C C Cd d Denote by CL,m the value of Lift Coefficient CL for which (CD/CL 3/2 ) is minimum *0 , 3 3 0* L k C C D mL C k C C D L = == 27 4 3 3 0 3 2/3 0 0 0 min 2/3 D D D D L D Ck k C k C kC C C =       + =       
  • 65. 65 Fixed Wing Fighter Aircraft Flight Performance SOLO Gliding Flight Rate of Sink *0 , 3 3 0* L k C C D mL C k C C D L = == 0 3 max 2/3 27 4 1 DD L CkC C =        We found: The velocity Vm for glide with minimum sink rate is given by:  * 4 0 76.0~ 4 4 0, 76.0 2 3 1 3 22 * V C k S W C k S W CS W V V D DmL m ≈        = ==    ρ ρρ S CkW C C S W h D L D s ρρ 27 22 0 3 min 2/3min, =        = The minimum sink rate is given by:
  • 66. 66 Fixed Wing Fighter Aircraft Flight Performance SOLO Gliding Flight Endurance The Endurance is the total time the glider remains in the air. Minimum Sink Rate tmax Flatest Glide Rmax         −== 2/3 2 L D C C S W V td hd ρ γ         −== D L C C W S V hd td 2/3 2 ρ γ ( )fi D L h h D L hh C C W S hd C C W S t f i −        =        −= ∫ 2/32/3 22 ρρ Assuming that the Angle of Attack is held constant during the glide and ignoring the variation in density as function of altitude, we have For Maximum Endurance the Glider has to fly at that Angle of Attack such that (CL 3/2 /CD) is maximum, which occurs when CL=√3 CL * and V = 0.76 V* .       − = 4 27 2 4 0 3max fi D hh CkW S t ρ Return to Table of Content
  • 67. 67 Performance of an Aircraft with Parabolic PolarSOLO W LT n + = αsin :' W L n =: 2 0 : LD L D L CkC C CSq CSq D L e + === We assume a Parabolic Drag Polar: 2 0 LDD CkCC += Let find the maximum of e as a function of CL ( ) ( ) 0 2 22 0 2 0 22 0 22 0 = + − = + −+ = ∂ ∂ LD LD LD LLD L CkC CkC CkC CkCkC C e e LC*LC *2 1 LCk CL/CD as a function of CL The maximum of e is obtained for k C C D L 0 * = ( ) 0 0 0 2 0 2** D D DLDD C k C kCCkCC =+=+= Start with Load Factor Total Load Number Lift to Drag Ratio Climbing Aircraft Performance
  • 68. 68 Performance of an Aircraft with Parabolic PolarSOLO e LC*LC *2 1 LCk CL/CD as a function of CL The maximum of e is obtained for k C C D L 0 * = ( ) 0 0 0 2 0 2** D D DLDD C k C kCCkCC =+=+= *2 1 *2 1 2 1 2* * * 22 00 0 LLDD D D L CkCkCkC k C C C e ===== We have WnCSVCSqL LL === 2 2 1 ρ Let define for n = 1             = = == 2 4 0 * 2 1 :* * : 2 * 2 1 :* Vq V V u C k S W CS W V D L ρ ρρ 2 0 : LD L D L CkC C CSq CSq D L e + === Climbing Aircraft Performance
  • 69. 69 Performance of an Aircraft with Parabolic PolarSOLO Using those definitions we obtain L L L L C C nqq WCSq WnCSqL * * ** =→    = == 2 2 2 1 2 1 * 2 1 * uV V n q q == ρ ρ 2 * * * u C nC q q nC L LL == ( )       +=      +=       +=+= = 2 2 2 04 02 0 2 * 4 2 2 0 22 0 ** * * 0 2 u n uCSq u C nCuSq u C nkCuSqCkCSqD D D D CCk L DLD DL           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ *2 1 * *** 0 0 e W C C CSqCSq L D LD ==       += 2 2 2 *2 u n u e W D Therefore Return to Table of Content Climbing Aircraft Performance
  • 70. 70 Performance of an Aircraft with Parabolic PolarSOLO We obtained       += 2 2 2 *2 u n u e W D u 0 - - - - 0 + + + + + D ↓ min ↑ n u D ∂ ∂ Let find the minimum of D as function of u. nu u nu e W u n u e W u D =→ = − =      −= ∂ ∂ 2 3 24 3 2 0 * 22 *2 * 2min e Wn DD nu == = Aircraft Drag Climbing Aircraft Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 71. 71 Performance of an Aircraft with Parabolic PolarSOLO Aircraft Drag ( ) MAXn W VhL n ≤= ,         +== 2 2 2 *2 u n u e W D MAX nn MAX Maximum Lift Coefficient or Maximum Angle of Attack ( ) ( ) ( )VhorMCMC STALLMAXLL ,, _ ααα ≤≤ We have u C C u n u C nC q q nC L MAXL CC L LL MAXLL * * * * _ 2 _ =→== = 2 2 _ 2 2 _2 * 1 *2 **2_ u C C e W u C C u e W D L MAXL L MAXL CC MAXLL               +=               +== Maximum dynamic pressure limit ( ) ( ) MAX MAX MAXMAX u V V uhVVorqVhq =<→≤≤= : *2 1 2 ρ *e W D MAXLC _ 2 2 _ 1 2 1 u C C L MAXL               +         += 2 2 2 2 1 * u n ue W D MAX LIMIT nn MAX= 2min * ue W D =       += 2 2 2 2 1 * u n ue W D MAXuu =MAX MAXL L CORNER n C C u _ * = n LIMIT u MAXnu = as a function of u*e W D Maximum Load Factor Climbing Aircraft Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 72. 72 Performance of an Aircraft with Parabolic PolarSOLO Energy per unit mass E Let define Energy per unit mass E: g V hE 2 : 2 += Let differentiate this equation: ( ) ( ) W VDT W VDT W DT g g V V g VV hEps − ≈ − =            − − +=+== α γ α γ cos sin cos sin:   *& *2 2 2 2 VuV u n u e W D =      += Define *: e W T z       = We obtain ( )             +−=             +−      = − = 2 2 2 2 2 2 2 1 * * * 2 1 * * u n uzu e V W Vu u n ue W T e W W VDT ps or ( ) u nuzu e V ps 224 2 *2 * −+− = 020 224 =+−→== nuzup constns ( ) ( ) 2 224 2 2243 23 * *244 * * u nuzu e V u nuzuuuzu e V u p constn s ++− = −+−−+− = ∂ ∂ = 0= ∂ ∂ =constn s u p 2 21 2 uu uu MAX << + nz > Climbing Aircraft Performance nz nzzu nzzu >     −+= −−= 22 2 22 1 3 3 22 nzz uMAX ++ =           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 73. 73 Performance of an Aircraft with Parabolic PolarSOLO Energy per unit mass E sp 2u1u MAXu 2 21 uu + u MAXn n 1=n ( ) u nuzu e V ps 224 2 * * −+− = ps as a function of u u V pe uzunnuzuu V pe ss * *2 22 * *2 242224 −+−=→−+−= From which u V pe uzun s * *2 2 24 −+−= ( ) * *2 44 3 2 V pe uzu u n s constps −+−= ∂ ∂ = ( ) 3 0412 2 2 22 z uzu u n constps =→=+−= ∂ ∂ = ( ) u nuzu e V ps 224 2 *2 * −+− = Climbing Aircraft Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 74. 74 Performance of an Aircraft with Parabolic PolarSOLO Load Factor n u 3 z z z2z 3 z u 2 n 0=sp 0>sp 0<sp 0<sp 0=sp 0>sp ( ) u n ∂ ∂ 2 ( ) 2 22 u n ∂ ∂ 3 z u ( ) ( ) 2 2 2 22 ,, n u n u n ∂ ∂ ∂ ∂ as a function of u ( ) 3 0412 2 2 22 z uzu u n constps =→=+−= ∂ ∂ = ( ) * *2 44 3 2 V pe uzu u n s constps −+−= ∂ ∂ = Integrating once u V pe uzun s * *2 2 24 −+−= Integrating twice Climbing Aircraft Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 75. 75 Performance of an Aircraft with Parabolic PolarSOLO Load Factor n For ps = 0 we have zuuzun 202 24 ≤≤+−= Let find the maximum of n as function of u. 0 22 44 24 3 = +− +− = ∂ ∂ uzu uzu u n Therefore the maximum value for n is achieved for zu = ( ) zn MAXps ==0 u 0 √z √2z ∂ n/∂u | + + + 0 - - - - | - - n ↑ Max ↓ z2z u n 0=sp 0>sp 0<sp MAXn z MAX MAXL L n C C _ * n as a function of u Climbing Aircraft Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 76. Performance of an Aircraft with Parabolic PolarSOLO Energy per unit mass E g V hE 2 : 2 += Climbing Aircraft Performance Energy Height versus Mach NumberEnergy Height versus True Airspeed ( )hV V M sound =:( ) 00 : T T V T T MhVTAS sound == Return to Table of Content
  • 77. 77 Performance of an Aircraft with Parabolic PolarSOLO Steady Climb (V, γ = constant) Climbing Aircraft Performance 0sin 0cos ==−− ==− td Vd g W WDT td d V g W WL γ γ γ Equation of Motion for Steady Climb: γ γ sin cos Vh Vx = =   Define the Rate of Climb: ( ) s Ra C p W PP W DTV Vh = − = −⋅ == γsin where Pa = V T - available power PR = V D - required power ps - excess power per unit weight Weight ThrustExcess W DT = − =γsin C C WL const γ γγ cos . = == Lift Drag Thrust Weight
  • 78. 78 Performance of an Aircraft with Parabolic PolarSOLO Climbing Aircraft Performance LC CSVW 2 2 1 cos ργ = ( ) s C D LD C p SV W kCSVVT WW CkCSVVT h =             −−= +− = ρ γ ρ ρ 2 1 cos 2 112 1 22 0 3 2 0 3  Let find the velocity V for which the Rate of Climb is maximum, for the Propeller Aircraft: 0 cos2 2 31 2 22 0 2 =      +−== SV Wk CSV Wtd pd td hd C D sC,Prop ρ γ ρ  Steady Climb (V, γ = constant) For a Propeller Aircraft we assume that Pa=T V= constant. or ** 4 4 0 4 76.0 3 12 3 1 VV C k S W V D Climb.Prop === ρ s C DaPropC p SV W kCSVP W h =      −−= ρ γ ρ 22 0 3 , cos 2 2 11 We can see that the velocity at which the Rate of Climb of Propeller Aircraft is maximum is the same as the velocity at which the Required Power in Level Flight is maximum. Lift Drag Thrust Weight
  • 79. 79 Performance of an Aircraft with Parabolic PolarSOLO Climbing Aircraft Performance LC CSVW 2 2 1 cos ργ = ( )             −−= +− = SV W kCSVVT WW CkCSVVT h C D LD C ρ γ ρ ρ 2 1 cos 2 112 1 22 0 3 2 0 3  Let find the velocity V for which the Rate of Climb is maximum, for the Jet Aircraft: 0 cos2 2 31 2 22 0 2 =      +−= SV Wk CSVT Wtd hd C D C ρ γ ρ  Steady Climb (V, γ = constant) For a Jet Aircraft we assume that T = constant. Define 0 * 0 0 * * * 4 0 2 :2*,*,: 2 :*, * : D DD D L D L D CkW T W eT zCC k C C C C e C k S W V V V u ======= ρ 0cos 2 2 3 2 2 /1 2 0 0 2 2 0 2 2 =+− C u D u Dz D V C k S W C k S W V T CkW γ ρ ρ    0cos23 224 =−− Cuzu γ Czzu γ22 cos3++=
  • 80. 80 Performance of an Aircraft with Parabolic PolarSOLO Climbing Aircraft Performance Steady Climb (V, γ = constant) ps versus the nondimensional velocity u ps versus the velocity V 0sin ==−− td Vd g W WDT γ 1 2 2 2 *2 =       += n u n u e W D Define 0 * 0 0 * * * 4 0 2 :2*,* ,: 2 :*, * : D DD D L D L D CkW T W eT zCC k C C C C e C k S W V V V u ==== === ρ             +−== − = 2 2 * 1 2 2 1 sin u uz eV p W DT s γ To find the maximum γ we must have 0 2 2 2 1sin 3* =      −−= u u eud d γ 4 0 2 *max DC k S W VV ρ γ == ( ) ( )1 * *2 *2 * 1 1 224 , max −= −+− = = = z e V u nuzu e V p u n s γ * , max 1 sin max max e z V ps − == γ γ γ 1max =γu
  • 81. SOLO 81 Aircraft Flight Performance Construction of the Specific Excess Power contours ps in the Altitude-Mach Number map for a Subsonic Aircraft below the Drag-divergence Mach Number. These contour are constructed for a fixed load factor W/S and Thrust factor T/S, if the load or thrust factor change, the ps contours will shift. ( ) ( ) W VDT W VDT W DT g g V V g VV hEps − ≈ − =            − − +=+== α γ α γ cos sin cos sin:   In Figure (a) is a graph of Specific Excess Power contours ps versus Mach Number. Each curve is for a specific altitude h. In Figure (b) each curve is for a given Specific Excess Power ps in Altitude versus Mach Number coordinates. The points a, b, c, d, e, f for ps = 0 in Figure (a) are plotted on the curve for ps = 0 in Figure (b). Similarly all points ps = 200 ft/sec in Figure (a) on the line AB are projected on the curve ps = 200 ft/sec in Figure (b). Specific Excess Power contours ps for a Subsonic Aircraft Specific Excess Power contours ps
  • 82. SOLO 82 Aircraft Flight Performance Specific Excess Power contours ps for a Supersonic Aircraft In the graphs of Specific Excess Power ps versus Mach Number Figure (a) for a Supersonic Aircraft we see a “dent” in h contour in the Transonic Region. This is due to the increase in Drag in this region.2 In Figure (b) the graphs of Altitude versus Mach Number we see a “closed” ps = 400 ft/sec contour due to the increase in Drag in this Transonic Region. Specific Excess Power contours ps ( ) ( ) W VDT W VDT W DT g g V V g VV hEps − ≈ − =            − − +=+== α γ α γ cos sin cos sin:   Return to Table of Content
  • 83. 83 Performance of an Aircraft with Parabolic PolarSOLO Climbing Aircraft Performance Optimum Climbing Trajectories using Energy State Approximation (ESA) We defined the Energy per unit mass E (Specific Energy): g V hE 2 : 2 += Differentiate this equation: ( ) ( ) W VDT W VDT W DT g g V V g VV h td Ed ps − ≈ − =            − − +=+== α γ α γ cos sin cos sin:   Minimum Time-to-Climb The time to reach a given Energy Height Ef is computed as follows E Ed td  = ∫= fE E f E Ed t 0  The minimum time to reach the given Energy Height Ef is obtained by using at each level. ( )∫= fE E f E Ed t 0 max max,  ( )maxE
  • 84. 84 Performance of an Aircraft with Parabolic PolarSOLO Climbing Aircraft Performance Optimum Climbing Trajectories using Energy State Approximation (ESA) Minimum Time Climb Profiles for Subsonic Speed ( ) ( ) W VDT W VDT W DT g g V V g VV hEps − ≈ − =            − − +=+== α γ α γ cos sin cos sin:   Stengel, MAE331, Lecture 7, Gliding, Climbing and Turning Performance The minimum time to reach the given Energy Height Ef is obtained by using at each level. ( )maxE Energy can be converted from potential to kinetic or vice versa along lines of constant energy in zero time with zero fuel expended. This is physically not possible so the method gives only an approximation of real paths.
  • 85. SOLO 85 Aircraft Flight Performance Stengel, MAE331, Lecture 7, Gliding, Climbing and Turning Performance Minimum Time Climb Profiles for Supersonic Speed ( ) ( ) W VDT W VDT W DT g g V V g VV hEps − ≈ − =            − − +=+== α γ α γ cos sin cos sin:   The minimum time to reach the given Energy Height Ef is obtained by using at each level. ( )maxE The optimum flight profile for the fastest time to altitude or time to speed involves climbing to maximal altitude at subsonic speed, then diving in order to get through the transonic speed range as quickly as possible, and than climbing at supersonic speeds again using .( )maxE
  • 86. 86 SOLO Climbing Aircraft Performance Optimum Climbing Trajectories using Energy State Approximation (ESA) Shaw, “Fighter Combats – Tactics and Maneuvering” Minimum Time Climb Profiles Aircraft Flight Performance The minimum time to reach the given Energy Height Ef is obtained by using at each level . ( )maxE
  • 87. 87 SOLO Climbing Aircraft Performance Optimum Climbing Trajectories using Energy State Approximation (ESA) A.E. Bryson, Course “Performance Analysis of Flight Vehicles”, AA200, Stanford University, Winter 1977-1978 Aircraft Flight Performance A.E. Bryson, Jr., “Energy-State Approximation in Performance Optimization of Supersonic Aircraft”, Journal of Aircraft, Vol.6, No. 5, Nov-Dec 1969, pp. 481-488 Approximate (ESA) Solutions. Implicit to ESA Approximation is the possibility of instantaneous jump between kinetic to potential energy (from A to B ). This non physical situation is called a “zoom climb” or “zoom dive”. A B The minimum time to reach the given Energy Height Ef is obtained by using at each level. ( )maxE
  • 88. SOLO Climbing Aircraft Performance Optimum Climbing Trajectories using Energy State Approximation (ESA) “Exact” calculated using Optimization Methods Computations Aircraft Flight Performance Comparison between “Exact” and Approximate (ESA) Solutions. Implicit to ESA Approximation is the possibility of instantaneous jump between kinetic to potential energy (from A to B , and from C to D). This non physical situation is called a “zoom climb” or “zoom dive”. We can see the “exact” solution in those cases. A B C D The minimum time to reach the given Energy Height Ef is obtained by using at each level. ( )maxE 88 A.E. Bryson, Course “Performance Analysis of Flight Vehicles”, AA200, Stanford University, Winter 1977-1978 A.E. Bryson, Jr., “Energy-State Approximation in Performance Optimization of Supersonic Aircraft”, Journal of Aircraft, Vol.6, No. 5, Nov-Dec 1969, pp. 481-488
  • 89. 89http://msflights.net/forum/showthread.php?1184-Supersonic-Level-Flight-Envelopes-in-FSX F-15 Streak Eagle Time to Climb Records, which follow the ideal path to reach set altitudes in a minimal amount of time. The Streak Eagle could break the sound barrier in a vertical climb, so the ideal flightpath to 30000m involved a large Immelmann. https://www.youtube.com/watch?v=HLka4GoUbLo https://www.youtube.com/watch?v=S7YAN9--3MA F-15 Streak Eagle Record Flights part 2F-15 Streak Eagle Record Flights part 1 SOLO Climbing Aircraft Performance Optimum Climbing Trajectories using Energy State Approximation (ESA) Aircraft Flight Performance
  • 90. 90 How to climb as fast as possible Takeoff and pull up: You want to build energy (kinetic or potential) as quickly as you can. Peak acceleration is at mach 0.9, which is the speed that energy is gained the fastest. You should first accelerate to near that speed. Avoid bleeding off energy in a high-g pull up. Start a smooth pull up before at mach 0.7-0.8 and accelerate to mach 0.9 during the pull. http://msflights.net/forum/showthread.php?1184-Supersonic-Level-Flight-Envelopes-in-FSX SOLO Climbing Aircraft Performance Optimum Climbing Trajectories using Energy State Approximation (ESA) F-15 Streak Eagle Time to Climb Records, which follow the ideal path to reach set altitudes in a minimal amount of time. The Streak Eagle could break the sound barrier in a vertical climb, so the ideal flightpath to 30000m involved a large Immelmann. Aircraft Flight Performance Climb again: to 36000ft for maximum speed, or higher as to not exceed design limits or to save fuel for a longer run Climb: Adjust your climb angle to maintain mach 0.9. In a modern fighter, the climb angle may be 45-60 degrees. If you need a heading change, during the pull and climb is a good time to make it. Level off: between 25000 and 36000ft by rolling inverted. Maximum speed is reached at 36000, but remember the engines produce more thrust at higher KIAS, so slightly denser air may not hurt acceleration through the sound barrier. Break the mach barrier: Accelerate to mach 1.25 with minimal wing loading (don't turn, try to set 0AoA) Return to Table of Content
  • 91. 91 SOLO Climbing Aircraft Performance Optimum Climbing Trajectories using Energy State Approximation (ESA) Aircraft Flight Performance Minimum Fuel-to- Climb Trajectories using Energy State Approximation (ESA) The Rate of Fuel consumed by the Aircraft is given by:    =−= AircraftJetTc AircraftPropellerPc td Wd td fd T p We can write ( )DTV EdW E Ed td − ==  The fuel consumed in a flight time , tf for a Jet Aircraft is: ( )∫∫∫ − === fff t T t T t f Ed TDV Wc E Ed Tctd td fd f 000 /1 The minimum fuel consumed in a flight time tf is obtained when using Maximum Thrust and the Mach Number that minimize the integrand: ( )∫ − = ft T M f Ed TDV Wc f 0 max min, /1 minarg for each level of E.
  • 92. 92 SOLO Climbing Aircraft Performance Optimum Climbing Trajectories using Energy State Approximation (ESA) Aircraft Flight Performance Minimum Fuel-to- Climb Trajectories using Energy State Approximation (ESA) Assuming W nearly constant, during the climb period, contours of constant ( ) max max Tc DTV T − can be computed, as we see in the Figure A.E. Bryson, Course “Performance Analysis of Flight Vehicles”, AA200, Stanford University, Winter 1977-1978 A.E. Bryson, Jr., “Energy-State Approximation in Performance Optimization of Supersonic Aircraft”, Journal of Aircraft, Vol.6, No. 5, Nov-Dec 1969, pp. 481-488 The Minimum Fuel-to- Climb Trajectory is obtained by choosing at each state. ( ) max max Tc DTV T − The Minimum Time-to- Climb Path is also displayed. Implicit to ESA Approximation is the possibility of instantaneous jump between kinetic to potential energy (from A to B) where the Total Energy is constant. A B Return to Table of Content
  • 93. 93 SOLO Climbing Aircraft Performance Optimum Climbing Trajectories using Energy State Approximation (ESA) Aircraft Flight Performance Maximum Range during Glide using Energy State Approximation (ESA) Equations of motion A.E. Bryson, Jr., “Energy-State Approximation in Performance Optimization of Supersonic Aircraft”, Journal of Aircraft, Vol.6, No. 5, Nov-Dec 1969, pp. 481-488 γ γ γ sin 0cos WDTV g W WL td d V g W −−= ≈−=  ( ) W VDT Eps − == : g V W DT  − − =γsin γ γ sin cos Vh Vx = =         − − = g V W DT Vh   γγ cos 1 cos       − − === g V W DT V h x h xd hd    During Glide we have: T = 0, W = constant, dE≤0, |γ| <<1, therefore       +−= g V W D xd hd  ( ) γcos 1 VW DT xd Ed − = 2 2 1 : VhE += ( ) ( ) ( )EL VED W VED td Ed −≈−= V td xd = ( ) ( ) ( )ED EL ED W Ed xd −≈−= ( ) ( ) ( )∫∫∫ −≈−== Ed ED EL Ed ED W xdR
  • 94. 94 SOLO Climbing Aircraft Performance Optimum Climbing Trajectories using Energy State Approximation (ESA) Aircraft Flight Performance Maximum Range during Glide using Energy State Approximation (ESA) We found A.E. Bryson, Jr., “Energy-State Approximation in Performance Optimization of Supersonic Aircraft”, Journal of Aircraft, Vol.6, No. 5, Nov-Dec 1969, pp. 481-488 ( ) ( ) ( )∫∫ −≈−= Ed ED EL Ed ED W R Using the first integral we see that to maximize R we must choose the path that minimizes the drag D (E). The approximate optimal trajectory can be divided in: 1.If the initial conditions are not on the maximum range glide path the Aircraft shall either “zoom dive” or “zoom climb” at constant E0, A to B path in Figure . 2.The Aircraft will dive on the min D (E) until it reaches the altitude h = 0 at a velocity V and Specific Energy E1=V2 /2, B to C in the Figure. 3.Since h=0 no optimization is possible and to stay airborne one must keep the drag such that L = W, by increasing the Angle of Attack and decreasing velocity until it reaches Vstall and Es=Vstall 2 /2, C to D in Figure Since h=0, d E=V dV. ( ) ( ) ( )[ ]∫ ∫∫ = = −−−= 1 0 1 0 0 0min 10 max E E E E h pathon E E s Vd VD VW Ed ED W Ed ED W R    Return to Table of Content
  • 95. 95 Performance of an Aircraft with Parabolic PolarSOLO       − + = = γσ α γσ coscos sin cossin V g Vm LT q V g r W W n W L W LT n =≈ + = αsin :' Therefore ( )      −= = γσ γσ coscos' cossin n V g q V g r W W γσγσγσω 2222222 coscoscoscos'2'cossin +−+=+= nn V g qr WW or γγσω 22 coscoscos'2' +−= nn V g γγσω 22 2 coscoscos'2' 1 +− == nng VV R Aircraft Turn Performance
  • 96. 96 Performance of an Aircraft with Parabolic PolarSOLO ( ) ( ) ( ) γ σ σ γ α χ γσγσ α γ cos sin sin cos sin coscos'coscos sin V gLT n V g V g Vm LT = + = −=− + =   2. Horizontal Plan Trajectory ( )0,0 == γγ  ( ) 1' 1 1' ' 1 1'sin' cos 1 '01cos' 2 2 2 2 − = −=      −== =→=−= ng V R n V g n n V g n V g nn V g σχ σ σγ   Aircraft Turn Performance 1. Vertical Plan Trajectory (σ = 0) ( ) γ γγ χ cos' 1 cos' 0 2 − = −= = ng V R n V g  
  • 97. 97
  • 98. 98 Vertical Plan Trajectory (σ = 0) SOLO Prof. Earll Murman, “Introduction to Aircraft Performance and Static Stability”, September 18, 2003
  • 99. 99 R V =:χ1'2 −= n V g χ Contours of Constant n and Contours of Constant Turn Radius in Turn-Rate in Horizontal Plan versus Mach coordinates Horizontal Plan TrajectorySOLO
  • 102. 102 Performance of an Aircraft with Parabolic PolarSOLO 2. Horizontal Plan Trajectory ( )0,0 == γγ  We can see that for n > 1 We found that 2 2 * * u C C n u C nC L LL L =→= n 1n 2n MAXn u u LC MAXLC _ 1 _ n C C MAXL L MAX MAXL L corner n C C u _ * = *2 L MAX L C u n C = MAX MAXL L corner n C C u _ * = MAX L L n C C 1 * MAXLC _ 2LC 1LC 2 * 1 u C C n L L = MAXn n, CL as a function of u Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ 1 1 1' 1 11' 2 2 2 2 22 − ≈ − = −≈−= ng V ng V R n V g n V g χ Horizontal Turn Rate Horizontal Turn Radius
  • 103. 103 Performance of an Aircraft with Parabolic PolarSOLO MAX MAX L MAXL n n C C V g 1 ** 2 _ − MAX MAXL L corner n C C V g u _ * * = MAXL L C C V g u _ 1 * * = MAXn 2n 1n MAXLC _ 2LC 1LC u χ MAXu Horizontal Turn Rate as function of u, with n and CL as parametersχ We defined 2 * & * : u C C n V V u L L == We found 2 2 2 22 1 ** 1 * 1 u u C C V g n Vu g n V g L L −      =−=−=χ This is defined for 1: ** 1 __ <=≥≥= u C C un C C u MAXL L MAX MAXL L corner 2. Horizontal Plan Trajectory ( )0,0 == γγ  Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 104. 104 Performance of an Aircraft with Parabolic PolarSOLO From 2 2 2 22 1 ** 1 * 1 u u C C V g n Vu g n V g L L −      =−=−=χ 4 2 2 2 22 1 * 1* 1 * : uC Cg V n u g VV R L L −      = − == χ Therefore cornerMAX MAXL L MAXL L L MAXL C un C C u C C u uC Cg V R MAXL =≤≤= −      = __ 1 4 2 _ 2 ** 1 * 1* _ cornerMAX MAXL L MAX n un C C u n u g V R MAX =≥ − = _ 2 22 * 1 * MAX L L L L L L C n C C u C C u uC Cg V R L ** 1 * 1* 1 4 2 2 ≤≤= −      = n C C u n u g V R MAXL L n _ 2 22 * 1 * ≥ − = 2. Horizontal Plan Trajectory ( )0,0 == γγ  Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 105. 105 Performance of an Aircraft with Parabolic PolarSOLO R (Radius of Turn) a function of u, with n and CL as parameters 1 ** 2 _ 2 −MAX MAX MAXL L n n C C g V MAX MAXL L corner n C C V g u _ * * = MAXL L C C V g u _ 1 * * = MAXn 2n 1nMAXLC _ 2LC 1LC u R 4 2 2 2 22 1 * 1* 1 * : uC Cg V n u g VV R L L −      = − == χ 2. Horizontal Plan Trajectory ( )0,0 == γγ  Return to Table of Content Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 106. 106 Performance of an Aircraft with Parabolic PolarSOLO Horizontal Turn Rate as Function of ps, n ( ) u nuzu e V ps 224 2 *2 * −+− = up V e uzun s * *2 2 242 −+−= 2 24 2 2 1 * *2 2 * 1 * u up V e uzu V g u n V g s −−+− = − =χ 2 24 4 2423 1 * *2 2 2 1 * *2 22 * *2 44 * u up V e uzu u up V e uzuuup V e uzu V g u s ss −−+−       −−+−−      −+− = ∂ ∂ χ Therefore       −−+− ++− = ∂ ∂ 1 * *2 2 1 * * * 244 4 up V e uzuu up V e u V g u s s χ For ps = 0 2 22 12 24 0 11 12 * uzzuzzu u uzu V g sp =−+<<−−= −+− == χ ( ) 2 22 1 244 4 0 11 12 1 * uzzuzzu uzuu u V g u sp =−+<<−−= −+− +− = ∂ ∂ = χ Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 107. 107 Performance of an Aircraft with Parabolic PolarSOLO Horizontal Turn Rate as Function of ps, n For ps = 0 2 22 12 24 0 11 12 * uzzuzzu u uzu V g sp =−+<<−−= −+− == χ ( ) 2 22 1 244 4 0 11 12 1 * uzzuzzu uzuu u V g u sp =−+<<−−= −+− +− = ∂ ∂ = χ Let find the maximum of as a function of uχ ( )12 1 * 244 4 0 −+− +− = ∂ ∂ = uzuu u V g u sp χ ( ) ( )12 * 1 00 −=== == z V g u ss ppMAX χχ  u 0 u1 1 (u1+u2)/2 u2 ∞ + + 0 - - - - - - -∞ ↑ Max ↓ u∂ ∂ χ χ From 2 24 1 * *2 2 * u up V e uzu V g s −−+− =χ       −−+− ++− = ∂ ∂ 1 * *2 2 1 * * * 244 4 up V e uzuu up V e u V g u s sχ Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 108. 108 Performance of an Aircraft with Parabolic PolarSOLO Horizontal Turn Rate as Function of ps, n u u 0<sp 0<sp 0=sp 0=sp 0>sp 0>sp χ u∂ ∂ χ ( )12 * −z V g 1=u1u 2u as a function of u with ps as parameter u∂ ∂ χ χ  ,       −−+− ++− = ∂ ∂ 1 * *2 2 1 * * * 244 4 up V e uzuu up V e u V g u s sχ 2 24 1 * *2 2 * u up V e uzu V g s −−+− =χ Because ,we have0 * * >u V e 000 >=< >> sss ppp χχχ  0 1 0 1 0 1 0 > = = = < = ∂ ∂ <= ∂ ∂ < ∂ ∂ sss p u p u p u uuu χχχ  Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 109. 109 Performance of an Aircraft with Parabolic PolarSOLO Horizontal Turn Rate as Function of ps, n a function of u, with ps as parameter χ 2 24 1 * *2 2 * u up V e uzu V g s −−+− =χ Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ Sustained Turn Instantaneous Turn
  • 110. 110 Performance of an Aircraft with Parabolic PolarSOLO Horizontal Turn Rate as Function of ps, n 2 24 1 * *2 2 * u up V e uzu V g s −−+− =χ ( ) ( )ss s puupu up V e uzu u g VV R 21 24 42 1 * *2 2 * << −−+− == χ 3 242 23 2 24 4 2 24 34243 2 1 * *2 22 2 * *3 22 * 1 * *2 2 2 1 * *2 2 * *2 441 * *2 24 *       −−+−       −− = −−+−       −−+−       −+−−      −−+− = ∂ ∂ up V e uzuu up V e uzu g V up V e uzu u up V e uzu p V e uzuuup V e uzuu g V u R s s s s ss Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 111. 111 Performance of an Aircraft with Parabolic PolarSOLO Horizontal Turn Rate as Function of ps, n 3 24 2 2 1 * *2 2 2 * *3 2 *       −−+−       −− = ∂ ∂ up V e uzu up V e uzu g V u R s s or We have            > +      + = < +      − = →= ∂ ∂ 0 4 16 * * 9 * *3 0 4 16 * * 9 * *3 0 2 2 2 1 z zp V e up V e u z zp V e up V e u u R ss R ss R u 0 u1 uR2 u2 ∞ - - - 0 + + ∞ ↓ min ↑ u R ∂ ∂ R 2 22 124 42 0 11 12 * uzzuzzu uzu u g V R sp =−+<<−−= −+− == ( ) ( ) 2 22 1 324 22 0 11 12 1*2 uzzuzzu uzu uzu g V u R sp =−+<<−−= −+− − = ∂ ∂ = Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 112. 112 Performance of an Aircraft with Parabolic PolarSOLO Horizontal Turn Rate as Function of ps, n u R 0>sp 0=sp 0<sp MAXL L C C _ * 1 ** 2 _ −MAX MAX MAXL L n n C C g V 1 1* 2 −zg V 4 2 _ 1* 1* uC C g V MAXL L −         1 * 2 22 −MAXn u g V MAX MAXL L n C C _ * LIMIT C MAXL_ LIMIT nMAX z 1 12 −− zz 12 −+ zz 1 * *2 2 * 24 42 −−+− = up V e uzu u g V R s Minimum Radius of Turn R is obtained for zu /1= 1 1* 2 2 0 − == zg V R sp R (Radius of Turn) a function of u, with ps as parameter ( ) ( )ss s puupu up V e uzu u g VV R 21 24 42 1 * *2 2 * << −−+− == χ Return to Table of Content Because ,we have0 * * >u V e 000 >=< << sss ppp RRR 000 minminmin >=< << sss pRpRpR uuu Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 113. 113 Performance of an Aircraft with Parabolic PolarSOLO Horizontal Turn Rate as Function of nV, ( ) W VDT g VV hEps − ≈+==  : For an horizontal turn 0=h V g Vu g VV ps   * == We found 2 24 1 * *2 2 * u up V e uzu V g s −−+− =χ from which 2 24 1*2 * u ue g V zu V g −      −+− =  χ defined for 2 22 1 :1**1**: ue g V ze g V zue g V ze g V zu =−      −+      −≤≤−      −−      −=  Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 114. 114 Performance of an Aircraft with Parabolic PolarSOLO Horizontal Turn Rate as Function of nV, Let compute 2 24 4 2423 1*2 2 1*22*44 * u ue g V zu u ue g V zuuuue g V zu V g u −      −+−       −      −+−−            −+− = ∂ ∂   χ       −      −+− +− = ∂ ∂ 1*2 1 * 244 4 ue g V zuu u V g u  χ or u 0 u1 1 (u1+u2)/2 u2 ∞ + + 0 - - - - - - -∞ ↑ Max ↓ u∂ ∂ χ χ       −−= 1*2 * e g V z V g MAX  χ Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 115. 115 Performance of an Aircraft with Parabolic PolarSOLO Horizontal Turn Rate as Function of nV, u 0<V 0=V 0>V χ ( )12 * −z V g 1=u1u 2u 2 24 1*2 * u ue g V zu V g −      −+− =  χ 1 * 2 −MAXn uV g 2 2 2 _ 1 ** u u C C V g L MAXL −      MAXL L C C _ * MAX MAXL L n C C _ * LIMIT nMAXLIMIT C MAXL _ MAX MAX L MAXL n n C C V g 1 ** 2 _ − as function of u and as parameter χ V Return to Table of Content Aircraft Turn Performance           = = = 2 0 * 2 1 :* * : 2 :* Vq V V u CS kW V D ρ ρ
  • 116. 116http://forum.keypublishing.com/showthread.php?69698-Canards-and-the-4-Gen-aircraft/page11 Example of Horizontal Turn, versus Mach, Performance of an Aircraft SOLO Aircraft Flight Performance
  • 117. 117 Mirage 2000 at 15000ft. http://forums.eagle.ru/showthread.php?t=98497 Max sustained rate (at around 6.5G on the 0 Ps line) occurring at around 0.9M/450KCAS looking at around 12.5 deg sec 9G Vc (Max instant. Rate) is around 0.65M/320KCAS looking at 23.5 deg sec SOLO Aircraft Flight Performance
  • 118. 118http://n631s.blogspot.co.il/2011/03/book-review-boyd-fighter-pilot-who.html Example of Horizontal Turn, versus Mach, Performance of MiG-21 SOLO Aircraft Flight Performance
  • 119. SOLO 119 Aircraft Flight Performance Comparison of Sustained ( ) Turn Performance of three Fightry Aircrafts F-16, F-4 and MiG-21 at Altitude h = 11 km = 36000 ft 0=V
  • 121. 121 The black lines are the F-4D, the dark orange lines are the heavy F-4E, and the blue lines are the lightweight F-4E (same weight as F-4D). Up to low transonic mach numbers and up to medium altitudes, the F-4E is about 7% better than the F-4D (15% better with the same weight). At higher mach numbers, the F-4 doesn't have to pull as much AoA to get the same lift, so the slats actually cause a drag penalty that allows the F- 4D to perform better. For reference, the F-14 is known to turn about 20% better than the unslatted F-4J. So, if the slats made the F-4S turn about 15% better, sustained turn rates would almost be pretty close between the F-14 and F- 4S. The F-4E, being heavier, would still be significantly under the F-14. However, with numbers this close, pilot quality is everything rather than precise performance figures. http://combatace.com/topic/71161-beating-a-dead-horse-us-fighter-turn-performance/ F-4 SOLO Aircraft Flight Performance
  • 124. 124 Corner Speed Maximum Positive Capability (CL) max Maximum Negative Capability (CL) min LoadFactor-n Structural Limit Structural Limit Limit Airspeed Area of Structural Damage of Failure Vmin V n Operational Load Limit Operational Load Limit Structural Load Limit Structural Load Limit Typical Maneuvering Envelope V – n Diagram Maneuvering Envelope: Limits on Normal Load Factor and Allowable Equivalent Airspeed -Structural Factor -Maximum and Minimum allowable Lift Coefficient -Maximum and Minimum Airspeeds -Corner Velocity: Intersection of Maximum Lift Coefficient and Maximum Load Factor SOLO Aircraft Flight Performance
  • 125. 125 Typical Maneuvering Envelope V – n Diagram Performance of an Aircraft with Parabolic PolarSOLO
  • 126. 126R.W. Pratt, Ed., “Flight Control Systems, Practical issues in design and implementation”, AIAA Publication, 2000 SOLO Aircraft Flight Performance Return to Table of Content
  • 127. 127 Air-to-Air Combat Destroy Enemy Aircraft to achieve Air Supremacy in order to prevent the enemy to perform their missions and enable to achieve tactical goals. SOLO See S. Hermelin, “Air Combat”, Presentation, http://www.solohermelin.com
  • 128. 128 http://forum.warthunder.com/index.php?/topic/110779-taktik-ve-manevralar-hakk%C4%B1ndaki-e% Air-to-Air Combat Before the introduction of all-aspect Air-to-Air Missiles destroying an Enemy Aircraft was effective only from the tail zone of the Enemy Aircraft, so the pilots had to maneuver to reach this position, for the minimum time necessary to activate the guns or launch a Missile. Return to Table of Content
  • 129. SOLO 129 Energy–Maneuverability Theory Aircraft Flight Performance Energy–maneuverability theory is a model of aircraft performance. It was promulgated by Col. John Boyd, and is useful in describing an aircraft's performance as the total of kinetic and potential energies or aircraft specific energy. It relates the thrust, weight, drag, wing area, and other flight characteristics of an aircraft into a quantitative model. This allows combat capabilities of various aircraft or prospective design trade-offs to be predicted and compared. Colonel John Richard Boyd (1927 –1997) Boyd, a skilled U.S. jet fighter pilot in the Korean War, began developing the theory in the early 1960s. He teamed with mathematician Thomas Christie at Eglin Air Force Base to use the base's high-speed computer to compare the performance envelopes of U.S. and Soviet aircraft from the Korean and Vietnam Wars. They completed a two-volume report on their studies in 1964. Energy Maneuverability came to be accepted within the U.S. Air Force and brought about improvements in the requirements for the F-15 Eagle and later the F-16 Fighting Falcon fighters
  • 130. 130
  • 131. 131 Turning Capability Comparison of F4E and MiG21 at Sea Level http://forum.keypublishing.com/showthread.php?96201-fighter-maneuverability- comparison F-4E MiG-21 Aircraft Flight Performance
  • 134. 134
  • 135. 135
  • 136. SOLO 136 Aircraft Flight Performance In combat, a pilot is faced with a variety of limiting factors. Some limitations are constant, such as gravity, drag, and thrust-to-weight ratio. Other limitations vary with speed and altitude, such as turn radius, turn rate, and the specific energy of the aircraft. The fighter pilot uses Basic Fighter Maneuvers (BFM) to turn these limitations into tactical advantages. A faster, heavier aircraft may not be able to evade a more maneuverable aircraft in a turning battle, but can often choose to break off the fight and escape by diving or using its thrust to provide a speed advantage. A lighter, more maneuverable aircraft can not usually choose to escape, but must use its smaller turning radius at higher speeds to evade the attacker's guns, and to try to circle around behind the attacker.[13] BFM are a constant series of trade-offs between these limitations to conserve the specific energy state of the aircraft. Even if there is no great difference between the energy states of combating aircraft, there will be as soon as the attacker accelerates to catch up with the defender. Instead of applying thrust, a pilot may use gravity to provide a sudden increase in kinetic energy (speed), by diving, at a cost in the potential energy that was stored in the form of altitude. Similarly, by climbing the pilot can use gravity to provide a decrease in speed, conserving the aircraft's kinetic energy by changing it into altitude. This can help an attacker to prevent an overshoot, while keeping the energy available in case one does occur Energy Management
  • 137. SOLO 137 Aircraft Flight Performance Energy Management Colonel J. R. Boyd: In an air-to-air battle offensive maneuvering advantage will belong to the pilot who can enter an engagement at a higher energy level and maintain more energy than his opponent while locked into a maneuver and counter-maneuver duel. Maneuvering advantage will also belong to the pilot who enters an air-to-air battle at a lower energy level, but can gain more energy than his opponent during the course of the battle, From a performance standpoint, such an advantage is clear because the pilot with the most energy has a better opportunity to engage or disengage at his own choosing. On the other hand, energy-loss maneuvers can be employed defensively to nullify an attack or to gain a temporary offensive maneuvering position. http://www.ausairpower.net/JRB/fast_transients.pdf “New Conception for Air-to-Air Combat”, J. Boyd, 4 Aug. 1976
  • 139. 139Comparative Ps Diagram for Aircraft A and Aircraft B. Two Multi-Role Jet Fighters SOLO Aircraft Flight Performance
  • 140. 140 http://www.simhq.com/_air/air_065a.html http://en.wikipedia.org/wiki/Lavochkin_La-5 Comparison of Turn Performance of two WWII Fighter Aircraft: Russian Lavockin La5 vs German Messershmitt Bf 109 http://en.wikipedia.org/wiki/Messerschmitt_Bf_109 SOLO Aircraft Flight Performance
  • 141. 141 Comparison of Turn Performance of two WWII Fighter Aircraft: Russian Lavockin La5 vs German Messershmitt Bf 109 http://en.wikipedia.org/wiki/Lavochkin_La-5http://en.wikipedia.org/wiki/Messerschmitt_Bf_109 http://www.simhq.com/_air/air_065a.html SOLO Aircraft Flight Performance
  • 142. 142 F-86F Sabre and MiG-15 performance comparison North American F-86 Sabre MiG-15 SOLO Aircraft Flight Performance
  • 143. 143 Falcon F-16C versus Fulcrum MIG 29, left is w/o afterburner, right is with it, fuel reserves 50% http://forum.keypublishing.com/showthread.php?47529-MiG-29-kontra-F-16-(aerodynamics-) FulcrumMiG-29F-16 SOLO Aircraft Flight Performance
  • 144. 144 Comparison of Turn Performance of two Modern Fighter Aircraft: Russian MiG-29 vs USA F-16 FulcrumMiG-29 F-16 http://www.simhq.com/_air/air_012a.html http://www.evac-fr.net/forums/lofiversion/index.php?t984.html
  • 145. 145 Comparison of Turn Performance of two Modern Fighter Aircraft: Russian MiG-29 vs USA F-16 FulcrumMiG-29 F-16 http://www.simhq.com/_air/air_012a.html http://www.evac-fr.net/forums/lofiversion/index.php?t984.html
  • 146. 146 http://www.simhq.com/_air/air_012a.html Comparison of Turn Performance of two Modern Fighter Aircraft: Russian MiG-29 vs USA F-16 Fulcrum MiG-29 F-16 http://www.evac-fr.net/forums/lofiversion/index.php?t984.html
  • 147. 147 http://www.simhq.com/_air3/air_117e.html While the turn radius of both aircraft is very similar, the MiG-29 has gained a significant angular advantage. Comparison of Turn Performance of two Modern Fighter Aircraft: Russian MiG-29 vs USA F-16 MiG-29 F-16 SOLO Aircraft Flight Performance
  • 148. 148 http://www.evac-fr.net/forums/lofiversion/index.php?t984.html Comparison of Turn Performance of two Modern Fighter Aircraft: Russian MiG-29 vs USA F-16 With afterburner, fuel reserves 50% Without afterburner, fuel reserves 50% MiG-29 F-16 SOLO Aircraft Flight Performance
  • 150. 150 An assessment is made of the applicability of Energy Maneuverability techniques (EM) to flight path optimization. A series of minimum time and fuel maneuvers using the F-4C aircraft were established to progressively violate the assumptions inherent in the EM program and comparisons were made with the Air Force Flight Dynamics Laboratory's (AFFDL) Three-Degree-of-Freedom Trajectory Optimization Program and a point mass option of the Six-Degree-of-Freedom flight path program. It was found the EM results were always optimistic in the value of the payoff functions with the optimism increasing as the percentage of the maneuver involving constant energy transitions Increases. For the minimum time paths the resulting optimism was less than 27%f1o r the maneuvers where the constant energy percentage was less than 35.',", followed by a rather steeply rising curve approaching in the limit 100% error for paths which are comprised entirely of constant energy transitions. Two new extensions are developed in the report; the first is a varying throttle technique for use on minimum fuel paths and the second a turning analysis that can be applied in conjunction with a Rutowski path. Both extensions were applied to F-4C maneuvers in conjunction with 'Rutowski’s paths generated from the Air Force Armament Laboratory's Energy Maneuverability program. The study findings are that energy methods offer a tool especially useful in the early stages of preliminary design and functional performance studies where rapid results with reasonable accuracy are adequate. If the analyst uses good judgment in its applications to maneuvers the results provide a good qualitative insight for comparative purposes. The paths should not, however, be used as a source of maneuver design or flight schedule without verification especially on relatively dynamic maneuvers where the accuracy and optimality of the method decreases. David T. Johnson, “Evaluation of Energy Maneuverability Procedures in Aircraft Flight Path Optimization and Performance Estimation”, November 1972, AFFDL-TR-72-53 SOLO Aircraft Flight Performance
  • 151. 151 Lockheed F-104 Starfighter SOLO Aircraft Flight Performance
  • 152. 152 Typical Ps Plot for Lockheed F-104 Starfighter Lockheed F-104 Starfighter SOLO Aircraft Flight Performance
  • 153. 153 SOLO Aircraft Flight Performance F-104 Flight Envelope Lockheed F-104 Starfighter
  • 154. 154F-104A flight envelope Lockheed F-104 Starfighter SOLO Aircraft Flight Performance Return to Table of Content
  • 159. 159 Supermaneuverability is defined as the ability of an aircraft to perform high alpha maneuvers that are impossible for most aircraft is evidence of the aircraft's supermaneuverability. Such maneuvers include Pugachev's Cobra and the Herbst maneuver (also known as the "J-turn"). Some aircraft are capable of performing Pugachev's Cobra without the aid of features that normally provide post-stall maneuvering such as thrust vectoring. Advanced fourth generation fighters such as the Su-27, MiG-29 along with their variants have been documented as capable of performing this maneuver using normal, non-thrust vectoring engines. The ability of these aircraft to perform this maneuver is based in inherent instability like that of the F-16; the MiG-29 and Su-27 families of jets are designed for desirable post-stall behavior. Thus, when performing a maneuver like Pugachev's Cobra the aircraft will stall as the nose pitches up and the airflow over the wing becomes separated, but naturally nose down even from a partially inverted position, allowing the pilot to recover complete control. http://en.wikipedia.org/wiki/Supermaneuverability Supermaneuverability SOLO Aircraft Flight Performance
  • 161. 161 Sukhoi Su-30MKI SOLO Aircraft Flight Performance http://vayu-sena.tripod.com/interview-simonov1.html
  • 162. 162 SOLO Aircraft Flight Performance The Herbst maneuver or "J-Turn" named after Wolfgang Herbst is the only thrust vector post stall maneuver that can be used in actual combat but very few air frames can sustain the stress of this violent maneuver. Herbst Maneuver http://en.wikipedia.org/wiki/Herbst_maneuver Return to Table of Content
  • 163. 163 Constraint Analysis SOLO Aircraft Flight Performance The Performance Requirements can be translated into functional relationship between the Thrust-to- Weight or Thrust Loading at Sea Level Takeoff (TSL/WTO) and the Wing Loading at Takeoff (WTO/S). The keys to the development are •Reasonable assumption hor Aircraft Lift-to-Drag Polar. •The low sensibility of Engine Thrust with Flight Altitude and Mach Number. The minimum of TSL/WTO as functions of WTO/S are required for: •Takeoff from a Runway of a specified length. •Flight at a given Altitude and Required Speed. •Climb at a Required Speed. •Turn at a given Altitude, Speed and a required Rate. •Acceleration capability at constant Altitude. •Landing without reverse Thrust on a Runway of a given length.
  • 164. 164 Energy per unit mass E Let define Energy per unit mass E: g V hE 2 : 2 += Let differentiate this equation: ( ) ( ) W VDT W VDT W DT g g V V g VV hEps − ≈ − =            − − +=+== α γ α γ cos sin cos sin:   define 10 ≤<= ββ TOWW WTO – Take-off Weight ( ) ( ) ( ) SLThThhT αα === 0 TSL – Sea Level Thrust V p W D W T s += Load Factor W CSq W L n L ==: SOLO Aircraft Flight Performance TOL W Sq n W Sq n C β==       += V p W D W T s TO SL α β Constraint Analysis
  • 165. 165 SOLO Aircraft Flight Performance General Mission Description of a Typical Fighter Aircraft 10: ≤<= ββ TOW W WTO – Take-off Weight W – Aircraft Weight during Flight Constraint Analysis
  • 166. 166 Assume a General Lift-to-Drag Polar Relationship Total DragRD CSqCSqRD +=+ D, CD - Clean Aircraft Drag and Drag Coefficient R, CR – Additional Aircraft Drag and Additional Drag Coefficient caused by External Stores, Bracking Parachute, Flaps, External Hardware 02 2 102 2 1 D TOTO DLLD C S W q n K S W q n KCCKCKC +      +      =++= ββ TOL W Sq n W Sq n C β== ( )       ++= V p CC W Sq W T s RD TOTO SL βα β         +         ++      +      = V p CC S W q n K S W q n K W Sq W T s DRD TOTO TOTO SL 02 2 1 ββ βα β SOLO Aircraft Flight Performance Constraint Analysis
  • 167. 167 ( )WLn td Vd td hd ==== ,1,0,0 Case 1: Constant Altitude/Speed Cruise (ps = 0) Given:                   + ++      = S W q CC K S W q K W T TO DRDTO TO SL β β α β 0 21 We obtain: We can see that TSL/WTO → ∞ for WTO/S → 0 and WTO/S→∞, therefore a minimum exist. By differentiating TSL/WTO with respect to WTO/S and setting the result equal to zero, we obtain: 1 0 /min K CCq S W DRD WT TO + =      β ( )[ ]210 min 2 KKCC W T DRD TO SL ++=      α β Lift DragThrust Weight SOLO Aircraft Flight Performance Constraint Analysis
  • 168. 168M. Corcoran, T. Matthewson, N. W. Lee, S. H. Wong, “Thrust Vectoring” Case 1: Constant Altitude/Speed Cruise (ps = 0) SOLO Aircraft Flight Performance Constraint Analysis
  • 169. 169 ( )WLn td hd ≈≈= ,1,0 Case 2: Constant Speed Climb (ps = dh/dt) Given: We can see that TSL/WTO → ∞ for WTO/S → 0 and WTO/S→∞, therefore a minimum exist. By differentiating TSL/WTO with respect to WTO/S and setting the result equal to zero, we obtain: 1 0 /min K CCq S W DRD WT TO + =      β ( )       +++=      td hd V KKCC W T DRD TO SL 1 2 210 min α β We obtain:             +       + ++      = td hd V S W q CC K S W q K W T TO DRDTO TO SL 10 21 β β α β SOLO Aircraft Flight Performance
  • 170. 170 ,1,0,0 ,, >== n td hd td Vd givenhVgivenhV Case 3: Constant Altitude/Speed Turn (ps = 0) Given: We can see that TSL/WTO → ∞ for WTO/S → 0 and WTO/S→∞, therefore a minimum exist. By differentiating TSL/WTO with respect to WTO/S and setting the result equal to zero, we obtain: 1 0 /min K CC n q S W DRD WT TO + =      β ( )[ ]210 min 2 KKCC n W T DRD TO SL ++=      α β We obtain:             +       + ++      = td hd V S W q CC nK S W q nK W T TO DRDTO TO SL 10 2 2 1 β β α β 2 0 2 2 0 11       +=      Ω += cRg V g V n SOLO Aircraft Flight Performance Constraint Analysis
  • 171. 171 ( )WLn td hd givenh === ,1,0 Case 4: Horizontal Acceleration (ps = (V/g0) (dV/dt) ) Given: We obtain:             +       + ++      = td Vd g S W q CC K S W q K W T TO DRDTO TO SL 0 0 21 1 β β α β SOLO Aircraft Flight Performance Lift DragThrust Weight This can be rearranged to give:                   + ++      = S W q CC K S W q K W T td Vd g TO DRDTO TO SL β β β α 0 21 0 1 Constraint Analysis
  • 172. 172 ( )WLn td hd givenh === ,1,0 Case 4: Horizontal Acceleration (ps = (V/g0) (dV/dt) ) (continue – 1) Given: SOLO Aircraft Flight Performance Lift DragThrust Weight We obtain:                   + ++      = S W q CC K S W q K W T td Vd g TO DRDTO TO SL β β β α 0 21 0 1 This equation can be integrated from initial velocity V0 to final velocity Vf, from initial t0 to final tf times. ( )∫=− fV V s f Vp VdV g tt 0 0 0 1 where                                 + ++      −= S W q CC K S W q K W T Vp TO DRDTO TO SL s β β β α 0 21 The solutions of TSL/WTO for different WTO/S are obtained iteratively. Constraint Analysis
  • 174. 174 0= givenh td hd Case 5: Takeoff (sg given and TSL >> (D+R) ) Given: SOLO Aircraft Flight Performance Ground Run V = 0 sg sTO sr str V TO Rotation Transition sCL θ CL htr hobs R Start from:  ( ) TO T SL s W VRDT td Vd g V td hd p SL β α α         +− ≈+= ≈    0        == TO SL V W Tg td sd sd Vd td Vd β α 0 /1 VdV T W g sd SL TO       = 0α β max,2 2 0max, 2 0 2 1 2 1 L TO TO LstallstallTO CS k V CSVLW ρρβ === The take-off velocity VTO is VTO = kTO Vstall Where Vstall is the minimum velocity at at which Lift equals weight and kTO ≈ 1.1 to 1.2:       == S W C kV k V TO L TOstall TO TO max,0 22 2 2 22 ρ β Integration from: s = 0 to s = sg V = 0 to V = VTO 2 2 0 TO SL TO g V T W g s       = α β sg – Ground Run Constraint Analysis
  • 175. 175 Case 5: Takeoff (sg given and TSL >> (D+R) ) (continue – 1) SOLO Aircraft Flight Performance Ground Run V = 0 sg sTO sr str V TO Rotation Transition sCL θ CL htr hobs R 2 2 0 TO SL TO g V T W g s       = α β       == S W C kV k V TO L TOstall TO TO max,0 22 2 2 22 ρ β       = S W Cgs k W T TO Lg TO TO SL max,00 22 ρ β α β We obtained: from which:             = S W C k T W g s TO L TO SL TO g max,0 2 0 ρ β α β We have a Linear Relation between TSL/WTO and WTO/S Constraint Analysis
  • 176. 176 Case 6: Landing SOLO Aircraft Flight Performance where ( ) ( )       −= −−= µ µ β ρ W T gc CC SW g a grLgrD TO 0 ,, : /2 : cab Va a ca Va a touchdown 4 2 : 4 2 : 2 1 1 − = − =cVa cVa a sg + + −= 2 2 2 1 ln 2 1       − − ⋅ + + − = 1 2 2 1 1 1 1 1 ln 4 1 a a a a ca tg Ground Run Phase We found Ground Run sgr Transition Airborne Phase Total Landing Distance Float sf Flare stGlide sg γ hg hf Touchdown 2 0 VCVBTT ++= For a given value of sg , there is only one value of WTO/S that satisfies this equation. ( )gTO sfSW =/ This constraint is represented in the TSL/WTO versus WTO/S plane as a vertical line, at WTO/S corresponding to the required sg. Constraint Analysis
  • 177. 177Constraint Diagram SOLO Aircraft Flight Performance                   + ++      = S W q CC K S W q K W T TO DRDTO TO SL β β α β 0 21             +       + ++      = td hd V S W q CC nK S W q nK W T TO DRDTO TO SL 10 2 2 1 β β α β       = S W Cgs k W T TO Lg TO TO SL max,00 22 ρ β α β ( )gTO sfSW =/ Constraint Analysis
  • 178. 178 Comparison of Fighter Aircraft Propulsion Systems SOLO
  • 179. 179 Comparison of Fighter Aircraft Propulsion Systems SOLO
  • 180. 180 SOLO Aircraft Flight Performance Composite Thrust Loading versus Wing Loading – for different Aircraft Constraint Analysis
  • 181. 181 Constraint Diagram for F-16 SOLO Aircraft Flight Performance Constraint Analysis Return to Table of Content
  • 182. 182 Weapon System Agility Weapon System Agility Return to Table of Content

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